CHEM 219 Module 1 Problem Set | Principles of
Organic Chemistry | Portage Learning | 2025/2026
Guide
Due No due date Points 10 Questions 21 Time Limit None
Question 2 pts
Classify the bonding between the given pairs of atoms as ionic, covalent,
or polar covalent. Use the table of electronegativities shown below to help
with the classification.
2. C
3. Zero lone pairs
4. Four unpaired electrons
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5. four bonds
, Module 1 Problem Set: Principles of Organic Chemistry with Lab
3. H
4. Zero lone pairs
5. One unpaired electron
6. one bond
4. N
5. One lone pair
6. three unpaired electrons
a.7.Br and bonds
three Br
b. K and Cl
c. P and Cl
d. C and O
Answer:
e. Na and Br
YourOxygen
Answer:– a) 2 b) 2 c) 2
a. covalent
Carbon –
b. Ionic a) 0 b) 4 c) 4
c. covalent
Hydrogen- a) 0 b) 1 c) 1
d. polar covalent
Nitrogen –
e. ionic a) 1 b) 3 c) 3
Score for this quiz: 10 out of 10
Answer:
Submitted Jul 25 at 8:42pm
This attempt took 1,135 minutes.
a. Br-Br: Electronegativity difference ( ) = 0 = COVALENT (or
Question 1
pure covalent) pts
b. K-Cl: ( ) = 2.2 = IONIC
On c. P-Cl: of
a piece ( scratch
)= 0.9 paper,
= POLAR COVALENT
write out the Lewis Dot Diagram for each of
the indicated elements and determine the following for each:
d. C-O: ( )= 1.0 = POLAR COVALENT
a) The number of Lone Pairs the atom possesses in its valence
e. Na-Br: ( ) = 1.8 = POLAR COVALENT
shell.
b) The number of Unpaired Electrons the atom possesses in its
valence shell.
c) The number of bonds the atom will form.
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1. Oxygen
, 2. Carbon
Module 1 Problem Set: Principles of Organic Chemistry with Lab
3. Hydrogen
4. Nitrogen
Question 3 pts
Your
DefineAnswer:
the term constitutional isomer.
1. O
2. Two
Your lone pairs
Answer:
3. Two unpaired electrons
Constitutional isomers are compounds with the same molecular formulas
4. two bonds
but different structural formulas.
Answer:
Two (or more) different chemical compounds with the same
molecular formula but different connectivity between the
atoms in their structural formulae.
Question 4 pts
Explain (using specific evidence) what makes the following two compounds
constitutional isomers of one another:
Your Answer:
Both compounds are , but they are arranged differently and have
different connectivity.
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