https://t.me/parmar_ssc_2
r
What is Motion?
i to
&
Relative change in position
↳ What is needed?
>
-
Reference point
Ed
· ·
A B
Point of origin
DF
Two physical quantities
Shortest part between two points (is a straight line)
L -
Distance Displacement
rP
Case 1 Case 2
↳-----------------
te
N 50 m 50 m
L
↓
Distance covered Distance = 100 m
as
Displacement = 0
M
Distance = 50 m
Displacement = 50 m
-
Displacement: vector quantity
Distance: scalar quantity
in
>
-
4
3
I
d
- -
↓
1
te
Case 1: shortest distance
Displacement
ea
Cr
, Types of Motion
r
i to
5 sec 5 sec 5 sec >
- Equal distance covered in equal
intervals: Uniform Motion
-
A l
5m 5m 5m
2 cases
Ed
↳ 5 sec 6 sec 3 sec >
- Equal distance in unequal intervals:
↑ ↑
Non-uniform motion
5m 5m 5m
DF
W
~
Wind speed is decreasing after increasing: Retardation
Rate of change of motion -
> Called as speed
rP
↓
Time involved
- m/km
>
Speed = Distance
te
Time
↳ s/hr
When motion is non-
as
uniform
S.I Unit: m/s -
> Represented
↑
Average speed = Total distance
M
Km/hr >
- m/sec Total time
↳x 5
18
in
m/s > Km/hr
x 18
d
5
te
>
-
Avg. speed = 16m + 16m
4+2
ea
= 32 = 16 m/s
6 3
Cr
, Speed + Direction = Velocity
r
i to
Velocity = Displacement
Time
Ed
Unit: m/s
Scalar quantity Vector quantity
DF
Only represents numerical value Numerical value + Direction
Distance Displacement
rP
Speed Velocity
Time
te
as
Avg. speed = 180 = 3 m/s
M
60
Avg. velocity = 0 = 0 m/s
60
in
d
te
Rate of change in velocity Is called Acceleration
5 m/s
ea
5 m/s 5 m/s
Velocity changing with
Cr
direction
, Change in velocity = Final speed - Initial speed
r
i to
Acceleration = m/s = m/s
s
a
Ed
DF
Case 1
Initial speed = 0 a = 6 - 0 = 1 = 0.2 m/s
rP
30 s
Final speed = 6 m/s 30 5
Case 2
te
Initial speed = 6 m/s
5s a = 4 - 6 = -2 = -0.4 m/s
Final speed = 4 m/s
5 5
as
M
Graph Representation
Slope = speed
in
Slope = Acceleration
Distance Velocity
d
te
Time Time
ea
Area = Motion Area = Displacement
Cr
r
What is Motion?
i to
&
Relative change in position
↳ What is needed?
>
-
Reference point
Ed
· ·
A B
Point of origin
DF
Two physical quantities
Shortest part between two points (is a straight line)
L -
Distance Displacement
rP
Case 1 Case 2
↳-----------------
te
N 50 m 50 m
L
↓
Distance covered Distance = 100 m
as
Displacement = 0
M
Distance = 50 m
Displacement = 50 m
-
Displacement: vector quantity
Distance: scalar quantity
in
>
-
4
3
I
d
- -
↓
1
te
Case 1: shortest distance
Displacement
ea
Cr
, Types of Motion
r
i to
5 sec 5 sec 5 sec >
- Equal distance covered in equal
intervals: Uniform Motion
-
A l
5m 5m 5m
2 cases
Ed
↳ 5 sec 6 sec 3 sec >
- Equal distance in unequal intervals:
↑ ↑
Non-uniform motion
5m 5m 5m
DF
W
~
Wind speed is decreasing after increasing: Retardation
Rate of change of motion -
> Called as speed
rP
↓
Time involved
- m/km
>
Speed = Distance
te
Time
↳ s/hr
When motion is non-
as
uniform
S.I Unit: m/s -
> Represented
↑
Average speed = Total distance
M
Km/hr >
- m/sec Total time
↳x 5
18
in
m/s > Km/hr
x 18
d
5
te
>
-
Avg. speed = 16m + 16m
4+2
ea
= 32 = 16 m/s
6 3
Cr
, Speed + Direction = Velocity
r
i to
Velocity = Displacement
Time
Ed
Unit: m/s
Scalar quantity Vector quantity
DF
Only represents numerical value Numerical value + Direction
Distance Displacement
rP
Speed Velocity
Time
te
as
Avg. speed = 180 = 3 m/s
M
60
Avg. velocity = 0 = 0 m/s
60
in
d
te
Rate of change in velocity Is called Acceleration
5 m/s
ea
5 m/s 5 m/s
Velocity changing with
Cr
direction
, Change in velocity = Final speed - Initial speed
r
i to
Acceleration = m/s = m/s
s
a
Ed
DF
Case 1
Initial speed = 0 a = 6 - 0 = 1 = 0.2 m/s
rP
30 s
Final speed = 6 m/s 30 5
Case 2
te
Initial speed = 6 m/s
5s a = 4 - 6 = -2 = -0.4 m/s
Final speed = 4 m/s
5 5
as
M
Graph Representation
Slope = speed
in
Slope = Acceleration
Distance Velocity
d
te
Time Time
ea
Area = Motion Area = Displacement
Cr
