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Cryptography Final Exam Study Set fully solved already passed

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Cryptography Final Exam Study Set fully solved already passed

Institution
Cryptography
Course
Cryptography

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Cryptography Final Exam Study Set fully solved
already passed
1. The is the message after decryption plaintext

2. What type of cipher is the Vigenère cipher? polyalphabetic

3. What is the decryption of bsujqsyodysw by happynewyear
use of Vigenère cipher with the key "USF?"

4. In Vernam cipher, its pad must be used just one time. true

5. What is the encryption of HAPPYNEWYEAR by rkzzixogiokb
use of Caesar cipher with its encryption key
10?

6. Vigenère cipher overcomes the problem of a small key having a
sequence of let-
space in Caesar cipher by ters, a word, as a secret key

true
7. For a Caesar cipher, a cyclic shift algorithm is
used to encrypt each letter

8. Caesar cipher is insecure because the frequencies of
letters remain
unchanged

9. A(n) algorithm transforms decryption
ciphertext to plaintext

10. Suppose C = 33 is the public key of the scheme p1 = 3 and p2 = 11
described in the video "Prime Numbers and
Public Key Cryptography." What is the
corresponding private key?

11. 27 is a prime number false
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,Cryptography Final Exam Study Set fully solved
already passed

12. The principle of Fail-Safe default means that




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,Cryptography Final Exam Study Set fully solved
already passed
unless access is
specifical- ly granted to
an object, ac- cess
should be denied
13. Kerckhoff's principle means that one must
never re- veal the design of a cipher false

14. Prime number is an integer that can be divided only by 1 and its

15. The modular arithmetic/remainder of 17 mod 5 is 2


16. You flip a coin and count 0 if it falls on
"heads" and 1 if it falls on "tail." What is the
expected value of your count? 1/2

17. The random variable is to capture the likelihood
of events and to make an
idea of random events

18. The uniform distribution means that each
outcome has different probability False

19. When tossing a fair coin (the outcomes of a head and 1/2
a tail are equally likely) once, the probability of
getting a head is

20. Assume there are 365 days in a year. If a
room has 100 people, and all the birthdays (1/365)*(1/365)
occur with the same probability, which is
1/365. Then, the probability that 2 give
people have their birthdate on January 1st is

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,Cryptography Final Exam Study Set fully solved
already passed
21. true




4/
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Institution
Cryptography
Course
Cryptography

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