Complex Number JEE Main 2024 January Question Bank
Questions with Answer Keys MathonGo
Q1 - 2024 (01 Feb Shift 1)
LetS = {z ∈ C : |z − 1| = 1 and (√2 − 1)(z + z̄ ) − i(z − z̄ ) = 2√2}. Let z 1, z2 ∈ S be such that
2
|z1 | = maxz∈s |z| and |z 2| = minz∈S |z| . Then ∣∣√2z 1 − z2 ∣
∣ equals :
(1) 1
(2) 4
(3) 3
(4) 2
Q2 - 2024 (01 Feb Shift 1)
Let P = {z ∈ C : |z + 2 − 3i| ≤ 1} and Q = {z ∈ C : z(1 + i) + z̄ (1 − i) ≤ −8}. Let in P ∩ Q, |z − 3 + 2i|
be maximum and minimum at z and z respectively. If |z , where α, β are integers,
2 2
1 2 1| + 2|z| = α + β √2
then α + β equals
Q3 - 2024 (01 Feb Shift 2)
If z is a complex number such that |z| ≥ 1, then the minimum value of ∣∣z + is:
1
(3 + 4i)∣
∣
2
[We changed options. In official NTA paper no option was correct.]
(1)
5
2
(2) 2
(3) 3
(4) 0
Q4 - 2024 (27 Jan Shift 1)
If S = {z ∈ C : |z − i| = |z + i| = |z − 1|} , then, n(S) is:
(1) 1
(2) 0
(3) 3
(4) 2
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, Complex Number JEE Main 2024 January Question Bank
Questions with Answer Keys MathonGo
Q5 - 2024 (27 Jan Shift 1)
If α satisfies the equation x 2
+ x + 1 = 0 and (1 + α) 7 2
= A + Bα + C , A, B, C ≥ 0 , then
5(3 A − 2 B − C) is equal to_____
Q6 - 2024 (27 Jan Shift 2)
Let the complex numbers α and 1
ᾱ
lie on the circles |z − z 0|
2
= 4 and |z − z 0|
2
= 16 respectively, where
z0 = 1 + i . Then, the value of 100|α| is. 2
Q7 - 2024 (29 Jan Shift 1)
If z = 1
2
− 2i , is such that |z + 1| = αz + β(1 + i), i = √−1 and α, β ∈ R , then α + β is equal to
(1) -4
(2) 3
(3) 2
(4) -1
Q8 - 2024 (29 Jan Shift 1)
Let α, β be the roots of the equation x 2
− x + 2 = 0 with Im(α) > Im(β). Then α 6
+ α
4
+ β
4
− 5α
2
is equal
to
Q9 - 2024 (29 Jan Shift 2)
Let r and θ respectively be the modulus and amplitude of the complex number z = 2 − i (2 tan 5π
8
) , then
(r, θ) is equal to
(1) (2 sec 3π
8
,
3π
8
)
(2) (2 sec 3π
8
,
5π
8
)
(3) (2 sec 5π
8
,
3π
8
)
(4) (2 sec 11π
8
,
11π
8
)
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Questions with Answer Keys MathonGo
Q1 - 2024 (01 Feb Shift 1)
LetS = {z ∈ C : |z − 1| = 1 and (√2 − 1)(z + z̄ ) − i(z − z̄ ) = 2√2}. Let z 1, z2 ∈ S be such that
2
|z1 | = maxz∈s |z| and |z 2| = minz∈S |z| . Then ∣∣√2z 1 − z2 ∣
∣ equals :
(1) 1
(2) 4
(3) 3
(4) 2
Q2 - 2024 (01 Feb Shift 1)
Let P = {z ∈ C : |z + 2 − 3i| ≤ 1} and Q = {z ∈ C : z(1 + i) + z̄ (1 − i) ≤ −8}. Let in P ∩ Q, |z − 3 + 2i|
be maximum and minimum at z and z respectively. If |z , where α, β are integers,
2 2
1 2 1| + 2|z| = α + β √2
then α + β equals
Q3 - 2024 (01 Feb Shift 2)
If z is a complex number such that |z| ≥ 1, then the minimum value of ∣∣z + is:
1
(3 + 4i)∣
∣
2
[We changed options. In official NTA paper no option was correct.]
(1)
5
2
(2) 2
(3) 3
(4) 0
Q4 - 2024 (27 Jan Shift 1)
If S = {z ∈ C : |z − i| = |z + i| = |z − 1|} , then, n(S) is:
(1) 1
(2) 0
(3) 3
(4) 2
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, Complex Number JEE Main 2024 January Question Bank
Questions with Answer Keys MathonGo
Q5 - 2024 (27 Jan Shift 1)
If α satisfies the equation x 2
+ x + 1 = 0 and (1 + α) 7 2
= A + Bα + C , A, B, C ≥ 0 , then
5(3 A − 2 B − C) is equal to_____
Q6 - 2024 (27 Jan Shift 2)
Let the complex numbers α and 1
ᾱ
lie on the circles |z − z 0|
2
= 4 and |z − z 0|
2
= 16 respectively, where
z0 = 1 + i . Then, the value of 100|α| is. 2
Q7 - 2024 (29 Jan Shift 1)
If z = 1
2
− 2i , is such that |z + 1| = αz + β(1 + i), i = √−1 and α, β ∈ R , then α + β is equal to
(1) -4
(2) 3
(3) 2
(4) -1
Q8 - 2024 (29 Jan Shift 1)
Let α, β be the roots of the equation x 2
− x + 2 = 0 with Im(α) > Im(β). Then α 6
+ α
4
+ β
4
− 5α
2
is equal
to
Q9 - 2024 (29 Jan Shift 2)
Let r and θ respectively be the modulus and amplitude of the complex number z = 2 − i (2 tan 5π
8
) , then
(r, θ) is equal to
(1) (2 sec 3π
8
,
3π
8
)
(2) (2 sec 3π
8
,
5π
8
)
(3) (2 sec 5π
8
,
3π
8
)
(4) (2 sec 11π
8
,
11π
8
)
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