Pipe and Excavation Contracting Exam
Verified 2025 Rated A+
_____ testing is NOT a type of testing that is usually specified for pipeline testing.
A. Visual
B. Water
C. Air
D. Hydrostatic - ANSWER-D. Hydrostatic
248/249
A .75 percent rise indicates?
A. A rise of 75 feet in 100 feet
B. A rise of 7.5 feet in 100 feet
C. A rise of .75 feet in 100 feet
D. A rise of 75 inches in 100 feet - ANSWER-C. A rise of 0.75 feet in 100 feet
119
A 0.75 percent rise indicates?
A. A rise of 75 feet in 100 feet
B. A rise of 7.5 feet in 100 feet
C. A rise of 0.75 feet in 100 feet
D. A rise of 0.75 inches in 100 feet - ANSWER-C. A rise of 0.75 feet in 100 feet
120
A 300 cubic yard volume of loose soil with a load factor of 0.769 is to be moved. The
average hourly production rate to be expected is cubic yards.
A. 390.1 bank
B. 390.1 loose
C. 230.7 bank
D. 230.7 loose - ANSWER-C. 300 x .769 = 230.7
66
A 480' long run of 21" PVC is placed between two manholes. The invert elevation of the
pipe at manhole Number One is 100.00'. The grade from the Number Two manhole
is .42 percent. The low end invert has a?
,A. 2.01 Fall
B. 2.01 Rise
C. 0.42 Fall
D. 0.42 Rise - ANSWER-A. 2.01 Fall
120
A 6 foot sheepsfoot roller is traveling at a speed of 1.25 miles per hour. The 12 inch lifts
take 8 passes of the roller for 8 inch compaction. The human efficiency is 83 percent
and the operator correction factor is 75 percent. The hourly production is?
A. Less than 30 cubic yards
B. Between 30 and 60 cubic yards
C. Between 60 and 90 cubic yards
D. More than 90 cubic yards - ANSWER-C. 6' wide x 1.25 mph x 8" lift x 16.3 = 978
978/8 passes = 122.25 CCY per hour production rate
122.25 x .83 human efficiency x .75 operator correction = 76.1 CCY per hr.
192/193
A 6 foot wide sheepsfoot roller travels at 1.25 miles per hour. The 12 inch lifts will be
compacted to 8 inches. There will be 8 passes of the roller. Machine efficiency is 83
percent and there is an operator correction factor of 75 percent. Hourly production
should be how many cubic yards?
A. 115
B. 102
C. 51
D. 77 - ANSWER-D. 6 x 1.25 x 8 x 16.3/8 x 83% x 75% Yields 76.1
192/193
A backhoe is best when working within what percent of its maximum digging depth?
A. 50
B. 60
C. 70
D. 80 - ANSWER-C. 70
150
A backhoe is most efficient when working within a maximum digging depth of ______?
A. 60 percent
B. 70 percent
C. 6 feet
,D. 7 feet - ANSWER-B. 70 percent
150
A backhoe is used for the following excavation:
Four foot deep by 2-foot wide trench
Moist sandy soil swell conditions of 17 percent
Cycle time is 12 seconds
Machine cycle time is 15 seconds
Heaped bucket capacity is 8 loose cubic feet
Eight-foot sets
The linear feet of trench production per hour is?
A. 200
B. 236
C. 210
D. 214 - ANSWER-B. Set = length of trench a backhoe can excavate from one position
= 8 ft
Bank cubic feet = 4ft x 2ft x 8ft (length of set) = 64 ft^3
Loose cubic feet = 4ft x 2ft x 8ft x 1.17 = 74.88 ft^3
Volume of dirt in set / dirt moved per cycle = digging cycles per set
74.88 ft^ft^3 = 9.36 digging cycles per set
Digging cycles per set x average cycle time = time required to excavate a set
9.36 x 12 seconds/cycle = 112.32 seconds add 15 seconds to move the machine
112.32 + 15 = 127.32 sec / 60 sec per minute = 2.122 minutes
How many sets in an hour = 60 minutes per hour / 2.122 minutes each set = 28.27
sets/hour
28.27 sets/hour x 8 ft per set = 226.16 ft per hour
146/147
A backhoe is used for the following excavation:
Six foot deep by 3 foot wide trench loamy soil conditions
Cycle time is 15 seconds
Machine cycle time 20 seconds
Heaped bucket capacity is 8 loose cubic feet
Ten-foot sets
The linear feet of trench production per hour is?
A. 78.4
B. 82.6
C. 91.8
, D. 99.3 - ANSWER-A. Set = length of a trench a backhoe can excavate from one
position = 10ft
Swell Factor for loamy soil = 30%
Bank cubic feet = 6ft x 3ft x 10ft (length of set) = 180 ft^3
Loose cubic feet = 6ft x 3ft x 10ft x 1.3 = 234 ft^3
Volume of dirt in set/dirt moved per cycle = digging cycles per set
234 ft^3/8 ft^3 = 29.25 digging cycles per set
Digging cycles per set x average cycle time = time required to excavate a set
29.25 x 15 seconds/cycle = 438.75 seconds add 20 seconds to move machine
438.74+20 = 458.75 seconds / 60 seconds per minute = 7.65 minutes
How many sets in an hour = 60 minutes per hour / 7.65 minutes each set = 7.84
sets/hour
7.84 sets/hour x 10ft per set = 7.84 ft per hour
A benchmark is a/an _______?
A. Point of known distance
B. Point of known elevation
C. Grade stake gradient
D. Topographic mark - ANSWER-B. Point of known elevation
111
A bulldozer going downhill at a 30 percent grade should push how much dirt?
A. Double the normal amount
B. One half the normal amount
C. One third the normal amount
D. 150 percent more - ANSWER-D. 150 percent more
84
A common test used to determine if a pipe has flattened or deflected under backfill and
compaction is the _____ test.
A. Mandrake
B. Pull
C. Compression
D. Mandrel - ANSWER-D. Mandrel
248
A common visual test is called ______?
A. Lamping
B. Shinning
Verified 2025 Rated A+
_____ testing is NOT a type of testing that is usually specified for pipeline testing.
A. Visual
B. Water
C. Air
D. Hydrostatic - ANSWER-D. Hydrostatic
248/249
A .75 percent rise indicates?
A. A rise of 75 feet in 100 feet
B. A rise of 7.5 feet in 100 feet
C. A rise of .75 feet in 100 feet
D. A rise of 75 inches in 100 feet - ANSWER-C. A rise of 0.75 feet in 100 feet
119
A 0.75 percent rise indicates?
A. A rise of 75 feet in 100 feet
B. A rise of 7.5 feet in 100 feet
C. A rise of 0.75 feet in 100 feet
D. A rise of 0.75 inches in 100 feet - ANSWER-C. A rise of 0.75 feet in 100 feet
120
A 300 cubic yard volume of loose soil with a load factor of 0.769 is to be moved. The
average hourly production rate to be expected is cubic yards.
A. 390.1 bank
B. 390.1 loose
C. 230.7 bank
D. 230.7 loose - ANSWER-C. 300 x .769 = 230.7
66
A 480' long run of 21" PVC is placed between two manholes. The invert elevation of the
pipe at manhole Number One is 100.00'. The grade from the Number Two manhole
is .42 percent. The low end invert has a?
,A. 2.01 Fall
B. 2.01 Rise
C. 0.42 Fall
D. 0.42 Rise - ANSWER-A. 2.01 Fall
120
A 6 foot sheepsfoot roller is traveling at a speed of 1.25 miles per hour. The 12 inch lifts
take 8 passes of the roller for 8 inch compaction. The human efficiency is 83 percent
and the operator correction factor is 75 percent. The hourly production is?
A. Less than 30 cubic yards
B. Between 30 and 60 cubic yards
C. Between 60 and 90 cubic yards
D. More than 90 cubic yards - ANSWER-C. 6' wide x 1.25 mph x 8" lift x 16.3 = 978
978/8 passes = 122.25 CCY per hour production rate
122.25 x .83 human efficiency x .75 operator correction = 76.1 CCY per hr.
192/193
A 6 foot wide sheepsfoot roller travels at 1.25 miles per hour. The 12 inch lifts will be
compacted to 8 inches. There will be 8 passes of the roller. Machine efficiency is 83
percent and there is an operator correction factor of 75 percent. Hourly production
should be how many cubic yards?
A. 115
B. 102
C. 51
D. 77 - ANSWER-D. 6 x 1.25 x 8 x 16.3/8 x 83% x 75% Yields 76.1
192/193
A backhoe is best when working within what percent of its maximum digging depth?
A. 50
B. 60
C. 70
D. 80 - ANSWER-C. 70
150
A backhoe is most efficient when working within a maximum digging depth of ______?
A. 60 percent
B. 70 percent
C. 6 feet
,D. 7 feet - ANSWER-B. 70 percent
150
A backhoe is used for the following excavation:
Four foot deep by 2-foot wide trench
Moist sandy soil swell conditions of 17 percent
Cycle time is 12 seconds
Machine cycle time is 15 seconds
Heaped bucket capacity is 8 loose cubic feet
Eight-foot sets
The linear feet of trench production per hour is?
A. 200
B. 236
C. 210
D. 214 - ANSWER-B. Set = length of trench a backhoe can excavate from one position
= 8 ft
Bank cubic feet = 4ft x 2ft x 8ft (length of set) = 64 ft^3
Loose cubic feet = 4ft x 2ft x 8ft x 1.17 = 74.88 ft^3
Volume of dirt in set / dirt moved per cycle = digging cycles per set
74.88 ft^ft^3 = 9.36 digging cycles per set
Digging cycles per set x average cycle time = time required to excavate a set
9.36 x 12 seconds/cycle = 112.32 seconds add 15 seconds to move the machine
112.32 + 15 = 127.32 sec / 60 sec per minute = 2.122 minutes
How many sets in an hour = 60 minutes per hour / 2.122 minutes each set = 28.27
sets/hour
28.27 sets/hour x 8 ft per set = 226.16 ft per hour
146/147
A backhoe is used for the following excavation:
Six foot deep by 3 foot wide trench loamy soil conditions
Cycle time is 15 seconds
Machine cycle time 20 seconds
Heaped bucket capacity is 8 loose cubic feet
Ten-foot sets
The linear feet of trench production per hour is?
A. 78.4
B. 82.6
C. 91.8
, D. 99.3 - ANSWER-A. Set = length of a trench a backhoe can excavate from one
position = 10ft
Swell Factor for loamy soil = 30%
Bank cubic feet = 6ft x 3ft x 10ft (length of set) = 180 ft^3
Loose cubic feet = 6ft x 3ft x 10ft x 1.3 = 234 ft^3
Volume of dirt in set/dirt moved per cycle = digging cycles per set
234 ft^3/8 ft^3 = 29.25 digging cycles per set
Digging cycles per set x average cycle time = time required to excavate a set
29.25 x 15 seconds/cycle = 438.75 seconds add 20 seconds to move machine
438.74+20 = 458.75 seconds / 60 seconds per minute = 7.65 minutes
How many sets in an hour = 60 minutes per hour / 7.65 minutes each set = 7.84
sets/hour
7.84 sets/hour x 10ft per set = 7.84 ft per hour
A benchmark is a/an _______?
A. Point of known distance
B. Point of known elevation
C. Grade stake gradient
D. Topographic mark - ANSWER-B. Point of known elevation
111
A bulldozer going downhill at a 30 percent grade should push how much dirt?
A. Double the normal amount
B. One half the normal amount
C. One third the normal amount
D. 150 percent more - ANSWER-D. 150 percent more
84
A common test used to determine if a pipe has flattened or deflected under backfill and
compaction is the _____ test.
A. Mandrake
B. Pull
C. Compression
D. Mandrel - ANSWER-D. Mandrel
248
A common visual test is called ______?
A. Lamping
B. Shinning
