ASCP Hematology Laboratory Exam Test Questions With 100% Verified Solutions

ASCP Hematology Laboratory Exam Test Questions With 100% Verified Solutions Which of the following is the formula to calculate a manual white cell count? A. (number of cells counted x dilution x10) number of squares counted B.(number of cells counted x dilution) / 10 x number of squares C. (number of cells counted x dilution D. (number of cells counted x number of squares counted - ANSWER A. (number of cells counted x dilution x10) number of squares counted If a WBC count is performed on a 1:100 dilution and the number of cells counted in 8 squares is 50, the total WBC count is? A. 5,000/uL B. 6,250/uL C. 50,000/uL D. 62,500/uL - ANSWER B. 6,250/uL A total leukocyte count is 10.0 x 10(3)/uL and 25 NRBCs are seen per 100 leukocytes on the differential. What is the corrected leukocyte count? A. 2,000/uL B. 8,000/uL C. 10,000/uL D. 12,000/uL - ANSWER B. 8,000/uL A flag of immature granulocytes (IG) is reported from a hematology analyzer. The next step is to perform a(an): A. Auto Verification B. Smear review C. Manual differential D. Pathology review - ANSWER C. Manual differential. Any automated differential result flag (to include an IG flag) should be confirmed with a manual differential In an automated hematology analyzer, the WBC printed result is +++. The next step is to: A. Repeat after warming the sample to 37C B. Make an appropriate dilution of the sample C. Recalibrate the machine from pooled samples D. Request a new sample immediately - ANSWER B. Make an appropriate dilution of the sample. +++ is an indicator that the WBC count exceeds the upper limit of established reportable range. A specimen analyzed on an automated hematology instrument has a platelet count of 19 x 10(3)/uL. the first procedure to follow is: A. Report the count after the batch run is completed B. Request a new specimen C. review the stained blood smear D. Notify the laboratory manager - ANSWER C. review the stained blood smear. Low platelet counts should be verified with a slide estimate. The electrical resistance method of cell counting requires: A. Equal-sized particles B. A conductive liquid C. 2 internal electrodes for current D. 3 apertures for counting - ANSWER B. A conductive liquid. Coulter principle of particle counting An automated hematology analyzer, if the RBC is erroneously increased, how will other parameters be effected? A. Increased MCHC B. Increased Hemoglobin C. Decreased MCH D. Increased MCV - ANSWER 251C. Decreased MCH. The formula for calculating the CH uses the RBC. On the initial start-up of the automated hematology analyzer, one of the controls is slightly below the range for the MCV. Which of the following is indicated? A. Call for service B. Adjust the MCV up slightly C. Shut down the instrument D. Repeat the control - ANSWER D. Repeat the control. Repeat of one out of range control is the first appropriate course of action. Which of the following will cause erroneous results when using a phase optical system for enumerating platelets? A. Lysed RBCs B. Aggretgated platelets C. Diluted Sample D. Intact leukocytes - ANSWER B. Aggretgated platelets. When evaluating a peripheral blood smear for reticulocyte count, the red blood cells are observed to overlap throughout the entire slide. The most likely explanation is: A. grease on the slide prevented even spreading B. Improper proportions of blood ad stain were used C. the slide was dried too quickly D. The drop used for the slide preparation was too large - ANSWER D. The drop used for the slide preparation was too large Blood collected in EDTA undergoes which of the following changes if kept at room temperature for 6-24 hours? A. Increased hematocrit and MCV B. Increased ESR and MCV C. Increased MCHC and MCV D. Decreased reticulocyte count and hematocrit - ANSWER A. Increased hematocrit and MCV Tubes that remian at room temp for more than 5 hours have unacceptable blood cell artifacts. This will affect the HCT and the MCV. A platelet determination was performed on an automated instrument and a very low value was obtained. The platelets appeared adequate when estimated from the stained blood film. The best explanation for this discrepancy is: A. Many platelets are abnormally large B. Blood sample is hemolyzed C. White cell fragments are present in the blood D. Red cell fragments are present in the blood - ANSWER A. Many platelets are abnormally large. Instruments count particles within defined size limits. The upper limit is to separate large platelets from erytherocytes. Small or fragmented RBCs may be counted as platelets. Blood is diluted 1:200, and a plt count is performed. 180 plts were counted in the center square mm on one side of the hemacytometer and 186 on the other side. The total plt count is: A. 146 x 10^3/µL (146 x 10^9/L)(146,000) B. 183 x 10^3/µL (183 x 10^9/L)(183,000) C. 366 x 10^3/µL (366 x 10^9/L)(366,000) D. 732 x 10^3/µL (732 x 10^9/L)(732,000) - ANSWER C. 366 x 10^3/µL (366 x 10^9/L)(366,000) A phase-platelet count was performed and the total plt count was 356 x 10^3/µL (356 x 10^9/L). 10 fields on the stained blood smear were examined for plts and the results per field were: -16, 18, 15, 20, 19, 17, 19, 18, 20, 16 The next step would be to: A. report the phase-plt count since it correlated well with th