Biochemistry I Module of the MCAT Self Prep
eCourse: Lesson 3: Enzyme Kinetics (Pro)
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Lesson 3: Enzyme Kinetics Lesson 3: Enzyme Kinetics
Rate= k [A][B]
Rate is the change in concentration per unit time.
k is the rate constant (depends on the reaction).
[A] and [B] are the concentrations of reactants A and B.
Write the rate law for the
following reaction: A+B -> AB
*Struggling to keep your MCAT equations straight? Simply
conquer the 100 most important equations using Andrew's 100
Most Essential Equations Mastery Course @
https://mcatselfprep.com/course/andrews-equation-mastery-
course/
In Michaelis-Menten Kinetics (B) III Only
experiments, which of the
following is assumed to be true? In Michaelis-Menten Kinetics
experiments:
I. Substrate concentration is
constant. - ENZYME concentration is held
II. Increasing the Enzyme constant as we increase the substrate
concentration will not change concentration.
Vmax. - If you were to increase the enzyme
III. The enzymes are saturated at concentration, the Vmax would
Vmax. increase.
- The enzymes are saturated at Vmax.
(A) I Only
(B) III Only
(C) I and II Only
(D) I, II, and III
,In Michaelis-Menten Kinetics (C) I and II Only
experiments, which of the
following is assumed to be true? In Michaelis-Menten Kinetics experiments, we assume that:
I. Our Solutions are behaving - Our Solutions are behaving ideally.
ideally. - Our constants ([E] and k) are not changing during the
II. Our constants ([E] and k) are experiment.
not changing during the - Substrate CANNOT be converted into product without the
experiment. enzyme.
III. Substrate can be converted
into product with or without the
enzyme.
(A) I Only
(B) III Only
(C) I and II Only
(D) I, II, and III
How can we increase the rate of (B) I and II Only
a reaction assuming the rate
constant (k) is constant? We can increase the rate of reaction
by increasing the substrate or enzyme
I. Increase Substrate concentration.
Concentration
II. Increase Enzyme Adding any type of inhibitor will not
Concentration increase the rate of a reaction.
III. Increase Mixed Inhibitor
Concentration
(A) I Only
(B) I and II Only
(C) II and III Only
(D) I, II, and III
False. Adding more catalyst after a catalytic amount has already
True or false? Adding more
been added will NOT AFFECT the rate of reaction.
catalyst after a catalytic amount
has already been added will
You only need a small amount ("a catalytic amount") of catalyst
increase the rate of reaction.
for it to do its job. Adding more will not do anything.
What does it mean if the rate of (D) The enzymes no longer have
reaction has reached maximum available active sites.
velocity (Vmax)?
When the rate of reaction reaches
(A) There are more products Vmax, it means that the enzymes are
than reactants. saturated and will not be able to react
(B) The substrates are no longer any more quickly since all active sites
able to get any closer to the are filled up with substrates.
enzymes.
(C) The substrates are no longer
able to get in any better of an
orientation.
(D) The enzymes no longer have
available active sites.
, If a reaction has reached Vmax, (B) It would remain the same
what would happen to the rate
of reaction if we increase the Increasing the substrate concentration
substrate concentration? would have no effect on the rate of the
reaction because all active sites are
(A) It would increase already occupied at Vmax.
(B) It would remain the same
(C) It would decrease
(D) It would stop
What is the one way to increase (B) Increase Enzyme Concentration
the Vmax of a reaction?
The only way to increase Vmax is by increasing the enzyme
(A) Increase Substrate concentration.
Concentration
(B) Increase Enzyme
Concentration
(C) Increase Inhibitor
Concentration
(D) Increase Product
Concentration
E + S => ES => E + P
Rate1 = k1 [E][S]
These are the two steps of
enzyme catalysis: Rate2 = k2 [ES]
E + S => ES => E + P Struggling to keep your MCAT
equations straight? Simply conquer
What are the respective reaction the 100 most important equations
rate formulas? using Andrew's 100 Most Essential
Equations Mastery Course @
https://mcatselfprep.com/course/and
rews-equation-mastery-course/
What is the steady-state (A) [ES] is constant
assumption when talking about
enzyme kinetics? The steady state assumption means that the concentration of the
enzyme-substrate complex (ES) is constant, which means that the
(A) [ES] is constant formation of ES is equal to the dissociation of ES.
(B) [S] is constant
(C) [P] is constant
(D) [I] is constant
eCourse: Lesson 3: Enzyme Kinetics (Pro)
Save
Students also studied
Flashcard sets Study guides
MCAT Psych/Sociology from 132 Sc... ED Course 1: Past Histories and ED F... BIO81 Chapter 8 amp
822 terms Teacher 94 terms 58 terms
quizuserlet23244 Preview SAEducation Preview aryoussefi
Lesson 3: Enzyme Kinetics Lesson 3: Enzyme Kinetics
Rate= k [A][B]
Rate is the change in concentration per unit time.
k is the rate constant (depends on the reaction).
[A] and [B] are the concentrations of reactants A and B.
Write the rate law for the
following reaction: A+B -> AB
*Struggling to keep your MCAT equations straight? Simply
conquer the 100 most important equations using Andrew's 100
Most Essential Equations Mastery Course @
https://mcatselfprep.com/course/andrews-equation-mastery-
course/
In Michaelis-Menten Kinetics (B) III Only
experiments, which of the
following is assumed to be true? In Michaelis-Menten Kinetics
experiments:
I. Substrate concentration is
constant. - ENZYME concentration is held
II. Increasing the Enzyme constant as we increase the substrate
concentration will not change concentration.
Vmax. - If you were to increase the enzyme
III. The enzymes are saturated at concentration, the Vmax would
Vmax. increase.
- The enzymes are saturated at Vmax.
(A) I Only
(B) III Only
(C) I and II Only
(D) I, II, and III
,In Michaelis-Menten Kinetics (C) I and II Only
experiments, which of the
following is assumed to be true? In Michaelis-Menten Kinetics experiments, we assume that:
I. Our Solutions are behaving - Our Solutions are behaving ideally.
ideally. - Our constants ([E] and k) are not changing during the
II. Our constants ([E] and k) are experiment.
not changing during the - Substrate CANNOT be converted into product without the
experiment. enzyme.
III. Substrate can be converted
into product with or without the
enzyme.
(A) I Only
(B) III Only
(C) I and II Only
(D) I, II, and III
How can we increase the rate of (B) I and II Only
a reaction assuming the rate
constant (k) is constant? We can increase the rate of reaction
by increasing the substrate or enzyme
I. Increase Substrate concentration.
Concentration
II. Increase Enzyme Adding any type of inhibitor will not
Concentration increase the rate of a reaction.
III. Increase Mixed Inhibitor
Concentration
(A) I Only
(B) I and II Only
(C) II and III Only
(D) I, II, and III
False. Adding more catalyst after a catalytic amount has already
True or false? Adding more
been added will NOT AFFECT the rate of reaction.
catalyst after a catalytic amount
has already been added will
You only need a small amount ("a catalytic amount") of catalyst
increase the rate of reaction.
for it to do its job. Adding more will not do anything.
What does it mean if the rate of (D) The enzymes no longer have
reaction has reached maximum available active sites.
velocity (Vmax)?
When the rate of reaction reaches
(A) There are more products Vmax, it means that the enzymes are
than reactants. saturated and will not be able to react
(B) The substrates are no longer any more quickly since all active sites
able to get any closer to the are filled up with substrates.
enzymes.
(C) The substrates are no longer
able to get in any better of an
orientation.
(D) The enzymes no longer have
available active sites.
, If a reaction has reached Vmax, (B) It would remain the same
what would happen to the rate
of reaction if we increase the Increasing the substrate concentration
substrate concentration? would have no effect on the rate of the
reaction because all active sites are
(A) It would increase already occupied at Vmax.
(B) It would remain the same
(C) It would decrease
(D) It would stop
What is the one way to increase (B) Increase Enzyme Concentration
the Vmax of a reaction?
The only way to increase Vmax is by increasing the enzyme
(A) Increase Substrate concentration.
Concentration
(B) Increase Enzyme
Concentration
(C) Increase Inhibitor
Concentration
(D) Increase Product
Concentration
E + S => ES => E + P
Rate1 = k1 [E][S]
These are the two steps of
enzyme catalysis: Rate2 = k2 [ES]
E + S => ES => E + P Struggling to keep your MCAT
equations straight? Simply conquer
What are the respective reaction the 100 most important equations
rate formulas? using Andrew's 100 Most Essential
Equations Mastery Course @
https://mcatselfprep.com/course/and
rews-equation-mastery-course/
What is the steady-state (A) [ES] is constant
assumption when talking about
enzyme kinetics? The steady state assumption means that the concentration of the
enzyme-substrate complex (ES) is constant, which means that the
(A) [ES] is constant formation of ES is equal to the dissociation of ES.
(B) [S] is constant
(C) [P] is constant
(D) [I] is constant
