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HOW TO PASS ENGR 391 - Numerical Methods in Engineering Past_finals-merged solution Concordia University

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HOW TO PASS ENGR 391 - Numerical Methods in Engineering Past_finals-merged solution Concordia University

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HOW TO PASS ENGR 391 - Numerical Methods in Engineering Past_finals-merged solution Concordia University


Home ► My courses ► ENGR-391-2201-AA ► Topic 4 ► Final exam



Started on Tuesday, 23 June 2020, 7:00 PM
State Finished
Completed on Tuesday, 23 June 2020, 9:59 PM
Time taken 2 hours 59 mins
Grade 25.33 out of 35.00 (72%)


Question 1 By checking the "yes" answer below I confirm
Complete 1. that I have neither given nor received unauthorized aid to answer the questions of this
Not graded assignment.
2. I agree to follow the rules in regard of online assignments as they are posted in the
announcement forum of this class and sent to me by email via moodle

Select one:
a. Yes I agree

b. No I do not agree



Your answer is correct.
The correct answer is: Yes I agree



Question 2 A first order initial value problem is solved using Euler’s method.
Correct If we reduce the step size h = xi+1 − xi to half of it’s previous value, how do you expect
Mark 1.00 out of the local and global truncation errors of the solution to change?
1.00
Select one:
a. local and global errors will be about a quarter of their previous values

b. local and global errors will be about a half of their previous values

c. local and global error will be a quarter and a half of their previous values,
respectively
d. local and global errors will be a half and a quarter of their previous values,
respectively



Your answer is correct.
The correct answer is: local and global error will be a quarter and a half of their previous
values, respectively

/

,Question 3 We want to approximate the defined integral I = ∫ 35 f(x)dx.
Incorrect
≃ 153.7.
When using the trapezoidal rule in its single version we get I
Knowing that f(4) = 24.2, how much will be the approximation of I if we use the
Mark 0.00 out of

composite trapezoidal rule with m = 2 sub-intervals ?
1.00



Select one:
a. Not enough information to answer the question

b. None of them
c. 101.05
d. 104.2

e. 94.9
f. 145.6



Your answer is incorrect.
f(3)+f(5)
We have that (5 − 3) = f(3) + f(5) =
Using the composite trapezoidal rule with m = 2 we have (h = 5−3 = 1):
I≃ 1 [f(3) + f(5) + 2 ⋅ f(4)] =
The correct answer is: 101.05



Question 4 The numerical stability of a method for solving initial value problems depends on
Correct
Select one:
Mark 1.00 out of
1.00 a. only the numerical method
b. only on the number of significant digits used

c. both the numerical method and the differential equation
d. only the differential equation



Your answer is correct.
It depends on the differential equation and as well on the chosen method (different methods
can lead to stable or unstable solutions for a same differential equation). It depends as well
on how the algorithm is used (for example which step size is chosen.
The correct answer is: both the numerical method and the differential equation




/

,Question 5 The Lagrange polynomial that passes through the 3 data points is given by
Incorrect

Mark 0.00 out of yi | 9.2 | 9.9 | 2.3
1.00



How much is the value of L1 (x) in x = 7.6 ?
Give at least 4 significant figures


Answer: 1.067



L1 (x) is given by


Reference: lecture on Lagrange interpolation of topic 4 "Regression and interpolation"


The correct answer is: 3.977



Question 6 Consider the linear equation ax = b with solution r = b
a.
Correct
How much is the maximal relative error magnification factor for this equation for the
Mark 1.00 out of approximation xr of the solution r?
1.00
Select one:
a.
b. |axr|
c. 1

d.



Your answer is correct.
Written in matrix form the system writes: [a]x = [b]. Here the coefficient matrix A is a 1x1
matrix.
The maximal error magnification factor is given by the conditioning number of the coefficient
matrix A.
In our case the coefficient matrix A is [a].



The correct answer is: 1




/

, Question 7 Choose the correct statement
Correct
Select one:
Mark 1.00 out of
1.00 a. The order of convergence for the bisection method is 1
2
b. For a given equation, every algorithm will converge eventually but with different
orders of convergence

c. The asymptotic error constant λ for the newton method is − 1


d. The fixed-point method converges linearly



Your answer is correct.
The correct answer is: The fixed-point method converges linearly



Question 8
Consider the following data set:
Correct
x | 1.0| 2.0| 5.0| 7.0
Mark 1.00 out of
y | 2.1| 2.9| 6.1| 8.3
1.00

The linear least square fitting will give the following model:

Select one:




Your answer is correct.
Reference: lectures on least square regression of topic 4
The correct answer is:




/

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