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Struggling to keep up with the pace of Organic Chem 1? These comprehensive, student-friendly notes are your shortcut to success. Designed by a top-performing student, these notes cover all the essential concepts, mechanisms, and reactions you need to master for exams. What’s inside: Clear explanations of major topics: hybridization, resonance, acid-base chemistry, reaction mechanisms, stereochemistry, substitution/elimination (SN1/SN2, E1/E2), and more Easy-to-follow reaction summaries and mechanism step breakdowns Diagrams, tables, and visual aids to simplify complex topics Highlighted tips, mnemonics, and tricks for remembering key points Organized by chapter or topic for quick review before tests Perfect for pre-meds, chemistry majors, or anyone aiming for an A in Organic Chemistry 1. Download instantly. Study smarter, not harder.

Meer zien Lees minder
Instelling
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Voorbeeld van de inhoud

Second
Notes

, Chapter 1- Structure and Bonding
·

Octect rule is ESSENTIAL to understanding bonding 3 molecules

-Group number informs you about the bonding capacity = now much covalent bonds can be formed
↳ 4 bonds (Tetravelent) ,
3 bonds (trivalent) ,
2 bonds (divalent) , I bond (monovalent)

·

Hydrocarbons-made from CBH-carbon bond to another carbon forms carbon chains



FUNCTIONAL GROUPS Constitutional isomer (Structural isomer) -

Alkane all single bonds c -
c -
C compounds w/ the same formula but dif. Structure

Alkene one or more double bond C= c -
C


Alkyne one or more triple bond C= C -
C When figuring out the dif . Isomer start w the

bond at the end of the chain
your way down
Alcohol OH C-C-OH longest chain work

Ether 0 the middle of the chain c- c C Make sure you don't repeat any (symmetrical
-

in
-
-




.
Aldenyde O double bond at the end of the chain C -
c -

C -
H chains)
G


Ketone O double bond i n the middle of the c- Try dif. functional (alcohol Bester ,
c
groups
-
-




chain aldenyde Ketones)

Alkyl halide Any halogen bond to the carbon chain C -
c -
C
-

Y


Arene Carbon circle , with 3 double 33

single bonds C formal charges
11


Esters carbon double bond to an oxygen c
-
c -
o -
C formal charge = valence e-dots-lines

single bond to an o in the middle -
Number assign to an atom to reflect the

Carboxylic carbon double bond to an0 3 C -
C -

OH number of valence electron

acid single bond to of lat the end) If
you take away a H the formal charge becomes

Amine carbon bond to any N C -
C -

Ny negative
Amide Carbon double bond to an bond C -
- NHe
C If you add the
a formal charge become positive
to NHZ Carbocation -
Carbon with a positive formal charge

Carbanion-Carbon with a negative formal charge


Molecular Representation

Full-write out all the , H
C , est with bond lines Bond-line Structure

partial condensed -
wo need to show bond lines w/H make sure that is goes with the molecular

Bond line- Each angle is one carbon ,
don't write H
geometry
but write out all dif .
atoms eX . Hz) =
CHCHz((CH3) 3

eX .




Full or


- only way to draw because its
In
-




H etrahedral (can't
+ have both

condensed branches pointing down
CH3COzCH3 ex .
CH3C = CCHzCH3

Bond line

i Try to make the its linear so theres no


- angles 1200 angle from carbon 1- 4




Electronegativity EN Difference

the relative ability to attract shared e 4 EN <O . S nonpolar covalent bund

EN : F > 0xC1 > N > Br > S > . . . ) H >>> metals -EN o S-1
.
. 7
polar covalent bund

Atom w/ the stronger EN gets 5- and the DEN) 1 7
.
IOniC bond

weaker gets St in a
polar covalent bond
-
label the atom w/ a + or-based on the


Non polar covalent -
equal En con sign

lonic bond-an atom lose an e ibond between metal nonmetal

,eX . Molecular Polarity Polar v .
Nonpolar solvents
A molecule will be nonpolar Dielectric constant (5) the



-
-




1) When a molecule has no polar bonds polarity per unt volume (size)
2) When a molecule has polar bond , but it is The smaller the molecule , the




symmetrical dipoles cancel out more powerful the polar group
ex-
so the
-




-
Polar solvents-water , acetone
-11)
H eX 0 = c = 0 Medium Polar solvents -
H H
.




nonpolar polar ethyl acetate , acetic acid

Hydrocarbons are usually nonpolar Nonpolar solvent-diethyl ether ,

nexane




Dissolving compounds in a solvent

Dissolving NaCl in water

Na has a positive charge so attracted to the 8 8

3
it
-

is on
6 molecules usually surround the o n
-
CI has a
negative charge so it is attracted to the Ston H

-
the bond between them is on-dipole interactions

H -




o. HH ci----
*
molecules surround
Dissolving NaOCH3 In acetone
08
CHzCOCH3
#
H20 the lons
+
- I

"H
* "
5
Na ---- St
>


Na + 0
- -
-
H
they disappear a
o
CH3
-




until -




* 'd

o !--- -
O




o
Na---
=0


%g

, Chapter 2- Molecular
How

Representation
Valence

1
do atoms form



covalent
Bond

bond
Theory
a covalent bond




is formed when
?


two half
Hybridization
ex .
CH4-shape
Sp3
is tetrahedral DC USEPR

filled orbitals overlap unhybridized C Hybridized C

2 . The greater the overlap , the stronger F
1 1




I
Energy levels is between
more stable the bond
Sp
PX Py P2 HV



+
-
O bond : head to head relatively stronger
No place 1
-
it bond : side to side
for 4H + O
Sp3 Sp3 Sp3 Sp3
Doesn't explain molecular geometry , bonding pattern 2S gs
same energy Shape
-
It CH4-carbon doesn't have 4 half filled for 4
space
.


& has H

orbitals there would be an H bonded to 25


B3 bonded to 2p Sp3


ex .
H20- >
sp3 hybridized
Hybridization sp2
molecular geometry : Trigonal planar unhybridized o Hybridized O
>
ex .
C2H
-




Two lone HL
pairs
E -1177
unhybridized C Hybridized C Hybridized C -
These make a it bond PX Py P2 1uju
1v 15
1
Sp3 Sp3
11 H H
1 HL HV Sp3 Sp3
+
1
I
PX Py P2 1v1 -
7 P2
11 HV
Sp2 Sp2 Spz Sp2 Spa
Sp2
11 1V
2S T 1V
11
O
V
~ These two 11


ja
Orbitals bond H
3) make o bond
1 -
i bond

H11 Hybridization sp
H
C
C
H1)
H ex-C2Hz-molecular geometry : linear


o bond
unhybridized C


E1
11
PX Py PL
characteristic of sp , Sp
>
&Sp3
11
2S

S orbital = short 3 fat Hybridized C Hybridized C

porbital =
long & thin
1 1
11 11
PY P2 H Py
H P2
S +
p
=
Sp (50 % S) closes to nucleus

14 1
spa (33 % 5)
P
+ =
S p
+
p
Sp Sp
s
+
p +
p +
p
=
sp3(25y S) .
farthest to nucleus




single bond-longest bond length weakest , -bond/ V

triple bond-shortest bond length , strongest
H C 11 C 11 H


L
n

. abond
1 ↓

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