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Bio 182 Module 2 – Genetics exam with questions and answers| well-structured for revision| rated 100% correct| 2025 latest update.

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Bio 182 Module 2 – Genetics exam with questions and answers| well-structured for revision| rated 100% correct| 2025 latest update.

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BIO182
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BIO182

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Bio 182 Module 2 – Genetics exam with
questions and answers| well-structured for
revision| rated 100% correct| 2025 latest
update.
T/F Dominance results from biochemical processes involving enzymes associated with the gene.
- ANSWER ✔✔ True

T/F If a heterozygote (Aa) makes some enzymes, but not enough to catalyze as many reactions
as a homozygote (AA) can, all genotypes would have the same phenotype (AA=Aa=aa)? -
ANSWER ✔✔ False

Unit of heritable information on chromosome and consisting of a sequence of DNA. - ANSWER
✔✔ Gene

A heritable feature, such as flower color. - ANSWER ✔✔ Character

A variant of a character, such as purple or white flowers. - ANSWER ✔✔ Trait

T/F Each trait carries two copies of a gene, one inherited from the mother and the other from the
father. - ANSWER ✔✔ True

Probability - ANSWER ✔✔ Describes our certainty about an outcome or event

Independent Events - ANSWER ✔✔ The outcome of one event does not affect the outcome of
the second event

Joint Probability - ANSWER ✔✔ The probability of two events occurring together

P(A and B) = P(A) · P(B) - ANSWER ✔✔ Joint Probability Calculation

P(A OR B) = P(A) + P(B) - P(A AND B) - ANSWER ✔✔ Probability that either event occurs

-Each parent in the monohybrid cross contributed one of two alleles to each offspring
-Every combination of alleles was equally likely - ANSWER ✔✔ Mendels postulated the
following rules of inheritance

Different phenotypes for a single trait - ANSWER ✔✔ Monohybrid cross

T/F A probability of 0.98 means that an event occurs rarely. - ANSWER ✔✔ False

, T/F When a parent is heterozygous, the probability of passing the dominant allele to its offspring
is 25%. - ANSWER ✔✔ False

T/F When both parents are heterozygous (Aa), the probability of an offspring being homozygous
recessive (aa) equals 0.25. - ANSWER ✔✔ True

T/F A Punnett square enables one to determine the frequency of observed genotypes without
using a mathematical formula to calculate the joint probability. - ANSWER ✔✔ True

T/F When both parents are heterozygous (Aa), the probability of an offspring being heterozygous
(Aa) equals 0.75. - ANSWER ✔✔ False

Why do experiments? - ANSWER ✔✔ 1. Replicate Observations
2. Control Conditions
3. Randomize Subjects

T/F If two heterozygotes mate to produce two offspring, the chance that both offspring are
homozygous equals 50%. - ANSWER ✔✔ False

The probability of the observed deviation or a greater deviation, when the model is correct -
ANSWER ✔✔ P Value

A statistical test used to determine the probability of obtaining observed proportions by chance,
under a specific hypothesis. - ANSWER ✔✔ Chi-square test

T/F Given a P value less than 0.01, our model of genetics probably fails to explain the observed
phenotypes. - ANSWER ✔✔ True

T/F A statistical test estimates the probability of obtaining a certain deviation from predictions
based on sampling error. - ANSWER ✔✔ True

T/F We cannot use Mendel's model alone to explain variation in continuous traits, such as height.
- ANSWER ✔✔ True

T/F Mendel's model applies only to discrete traits, which have only two or three phenotypes
(e.g., round or wrinkled peas; or red, pink, and white flowers). - ANSWER ✔✔ True

T/F Fisher's revised model of inheritance started the field of quantitative genetics, which focuses
on continuous traits. - ANSWER ✔✔ True

The resulting theory of evolution grew during a period from 1920-1940 is known as - ANSWER
✔✔ Modern Synthesis

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