Business Mathematics In Canada
11th Edition By F. Ernest Jerome Ch 1 to 17
Solution Manual
,Table of Contents
Chapter 1: Review and Applications of Basic Mathematics
Chapter 2: Review and Applications of Algebra
Chapter 3: Percent and Percent Change
Chapter 4: Ratios and Proportions
Chapter 5: Mathematics of Merchandising
Chapter 6: Applications of Linear Equations
Chapter 7: Simple Interest
Chapter 8: Applications of Simple Interest
Chapter 9: Compound Interest: Future Value and Present Value
Chapter 10: Compound Interest: Further Topics and Applications
Chapter 11: Ordinary Annuities: Future Value and Present Value
Chapter 12: Ordinary Annuities: Periodic Payment, Number of
Payments, and Interest Rate
Chapter 13: Annuities Due
Chapter 14: Annuities: Special Situations
Chapter 15: Loan Amortization: Mortgages
Chapter 16: Bonds and Sinking Funds
Chapter 17: Business Investment Decisions
,1 Review and Applications of
Basic Mathematics
Exercise 1.1
a. 10 + 10 x 0 = 10 + 0 = 10
b. 2x2+ 4– 8 =4 +4– 8 =0
c. (10 + 10) x 0 = 20 x 0 = 0
d. 2 x (2 + 4) – 8 = 2 x 6 – 8 = 12 – 8 = 4
e. 0 + 3 x 3 – 3 2 + 10 = 0 + 9 – 9 + 10 = 10
f. 12 – 2 x 5 + 22 x 0 = 12 – 10 + 4 x 0 = 12 – 10 + 0 = 2
g. 0 + 3 x 3 – (3 2 + 10) = 0 + 9 – 19 = -10
h. (12 – 2) x (5 + 22) x 0 = 10 x 9 x 0 = 0
22 4 4 4 0
i. 0
(4 2)2 22 4
(2 4)2 ( 2)2 4
4
j. 5 4 1
5
22
1. 20 4 2 8 20 8 8 4
2. 18 3 6 2 6 12 18
3. 20 4 2 8 16 2 8 32 8 24
4. 18 3 6 2 18 9 2 2 2 4
5. 20 4 2 8 20 8 8 20
6. 18 3 6 2 6 6 2 24
7. 54 36 4 22 54 9 4 49
2
8. 5 3 32 9 3 82 9 9 3 64 1 3 66
, 2
9. 54 36 4 2 18 62 18 36 0.5
2
10. 5 32 3 9 3 5 9 3 2 12 5 36 12 5 3 8
11. 82 42 64 16 48
6
3 23 8
4 2
8 4 2 42 16
12. 4
4 23 4 8 4
2 2 2
13. 3 6 4 5 17 20 3 102 5 3 3 100 5 9 300 45 255
2 2
14. 4 3 2 4 3 22 12 2 4 3 4 102 4 12 100 8 12.5
15. 20 8 5 7 3 9 20 40 21 9 81 9 9
2 2
5 19 2 2 2
16. 52 16 5 19 25 16 5 19 81 5 100 2 50,000
17. $100 1 0.06 45 $100 1 0.00739726 $100.74
365
$200 $200 $200
18. 1 0.03 $194.17
1 0.09 12 1.03
4
$500 $500
19. $453.51
1 0.05
2
1.052
$500 1.1025
3
20. $1000 1 0.02$1000 1.023 $1000 1.061208 $1061.21
2
1 0.04 1 1.04 2 1 0.0816
21. $100 0.04 $100 0.04 $100 0.04 $204.00
1 1
1 1 1 1.0609 1 0.942596
2
0.03
22. $300 $300 $300 $574.04
0.03 0.03 0.03
Concept Questions (Section 1.2)
1. Ỵou must retain at least one more figure than ỵou require in the answer. To achieve four-figure
accuracỵ in the answer, ỵou must retain a minimum of five figures in the values used in the
calculations. B)
2. We want six-figure accuracỵ in the answer. Therefore, values used in the calculationsmust be
accurate to at least seven figures. B)
3. We want seven-figure accuracỵ in the answer. Therefore, values used in the calculationsmust
retain at least eight figures. C)
4. To be accurate to the nearest 0.01%, an interest rate greater than 10% must have four- figure
accuracỵ. Therefore, five figures must be retained in numbers used in the calculations. C)
11th Edition By F. Ernest Jerome Ch 1 to 17
Solution Manual
,Table of Contents
Chapter 1: Review and Applications of Basic Mathematics
Chapter 2: Review and Applications of Algebra
Chapter 3: Percent and Percent Change
Chapter 4: Ratios and Proportions
Chapter 5: Mathematics of Merchandising
Chapter 6: Applications of Linear Equations
Chapter 7: Simple Interest
Chapter 8: Applications of Simple Interest
Chapter 9: Compound Interest: Future Value and Present Value
Chapter 10: Compound Interest: Further Topics and Applications
Chapter 11: Ordinary Annuities: Future Value and Present Value
Chapter 12: Ordinary Annuities: Periodic Payment, Number of
Payments, and Interest Rate
Chapter 13: Annuities Due
Chapter 14: Annuities: Special Situations
Chapter 15: Loan Amortization: Mortgages
Chapter 16: Bonds and Sinking Funds
Chapter 17: Business Investment Decisions
,1 Review and Applications of
Basic Mathematics
Exercise 1.1
a. 10 + 10 x 0 = 10 + 0 = 10
b. 2x2+ 4– 8 =4 +4– 8 =0
c. (10 + 10) x 0 = 20 x 0 = 0
d. 2 x (2 + 4) – 8 = 2 x 6 – 8 = 12 – 8 = 4
e. 0 + 3 x 3 – 3 2 + 10 = 0 + 9 – 9 + 10 = 10
f. 12 – 2 x 5 + 22 x 0 = 12 – 10 + 4 x 0 = 12 – 10 + 0 = 2
g. 0 + 3 x 3 – (3 2 + 10) = 0 + 9 – 19 = -10
h. (12 – 2) x (5 + 22) x 0 = 10 x 9 x 0 = 0
22 4 4 4 0
i. 0
(4 2)2 22 4
(2 4)2 ( 2)2 4
4
j. 5 4 1
5
22
1. 20 4 2 8 20 8 8 4
2. 18 3 6 2 6 12 18
3. 20 4 2 8 16 2 8 32 8 24
4. 18 3 6 2 18 9 2 2 2 4
5. 20 4 2 8 20 8 8 20
6. 18 3 6 2 6 6 2 24
7. 54 36 4 22 54 9 4 49
2
8. 5 3 32 9 3 82 9 9 3 64 1 3 66
, 2
9. 54 36 4 2 18 62 18 36 0.5
2
10. 5 32 3 9 3 5 9 3 2 12 5 36 12 5 3 8
11. 82 42 64 16 48
6
3 23 8
4 2
8 4 2 42 16
12. 4
4 23 4 8 4
2 2 2
13. 3 6 4 5 17 20 3 102 5 3 3 100 5 9 300 45 255
2 2
14. 4 3 2 4 3 22 12 2 4 3 4 102 4 12 100 8 12.5
15. 20 8 5 7 3 9 20 40 21 9 81 9 9
2 2
5 19 2 2 2
16. 52 16 5 19 25 16 5 19 81 5 100 2 50,000
17. $100 1 0.06 45 $100 1 0.00739726 $100.74
365
$200 $200 $200
18. 1 0.03 $194.17
1 0.09 12 1.03
4
$500 $500
19. $453.51
1 0.05
2
1.052
$500 1.1025
3
20. $1000 1 0.02$1000 1.023 $1000 1.061208 $1061.21
2
1 0.04 1 1.04 2 1 0.0816
21. $100 0.04 $100 0.04 $100 0.04 $204.00
1 1
1 1 1 1.0609 1 0.942596
2
0.03
22. $300 $300 $300 $574.04
0.03 0.03 0.03
Concept Questions (Section 1.2)
1. Ỵou must retain at least one more figure than ỵou require in the answer. To achieve four-figure
accuracỵ in the answer, ỵou must retain a minimum of five figures in the values used in the
calculations. B)
2. We want six-figure accuracỵ in the answer. Therefore, values used in the calculationsmust be
accurate to at least seven figures. B)
3. We want seven-figure accuracỵ in the answer. Therefore, values used in the calculationsmust
retain at least eight figures. C)
4. To be accurate to the nearest 0.01%, an interest rate greater than 10% must have four- figure
accuracỵ. Therefore, five figures must be retained in numbers used in the calculations. C)
