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Full chapters Solution manual for Energy, Environment, and Sustainability, 2nd Edition Saeed Moaveni [ Instant Download Solution manual ]

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Full chapters Solution manual for Energy, Environment, and Sustainability, 2nd Edition Saeed Moaveni [ Instant Download Solution manual ]

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,Solution manual for Energy, Environment, and
Sustainability, 2nd Edition Saeed Moaveni
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, Solution and Answer Guide: Moaveni, Energy, Environment, and Sustainability 2e 2023, 9780357676073; Chapter 1:
Introduction to Energy, Environment, and Sustainability



Solution and Answer Guide
Moaveni, Energy, Environment, and Sustainability 2e 2023, 9780357676073; Chapter 1:
Introduction to Energy, Environment, and Sustainability


End of Section Problem Solutions

Note: Some solutions are not provided due to the nature of the problems.



1.18 A gallon (3.8 liters) of gasoline that weighs 6.3 pounds (2.85 kg) can produce 20
pounds (9.1 kg) of carbon dioxide. Yes, 20 pounds (9.1 kg) of carbon dioxide!
Assume 100 million people with cars (with 20 miles/gallon (10.6 km/liters) gasoline
consumption rates) decide to walk 3 miles (4.8 km) a day (approximately an hour)
instead of driving their cars. What would be the reduction in pounds of carbon
dioxide released into the atmosphere on a yearly basis?



Solution
3 miles 365 days 1 gallon 20 pounds of CO2
100,000,000 people × × × ×
day · person year 20 miles gallon
pounds of CO2
= 109.5 × 109
year




© 2023 Cengage. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible 1-1
website, in whole or in part.

, Solution and Answer Guide: Moaveni, Energy, Environment, and Sustainability 2e 2023, 9780357676073; Chapter 2:
Fundamental Dimensions and Systems of Units



Solution and Answer Guide
Moaveni, Energy, Environment, and Sustainability 2e 2023, 9780357676073; Chapter 2:
Fundamental Dimensions and Systems of Units

End of Section Problem Solutions

Note: Some solutions are not provided due to the nature of the problems.



2.1 Convert the information given in the accompanying table from SI units to U.S.
Customary units. Show all steps of your solutions. See Example 2.3.




Solution
 km  1000 m  3.28 ft  1 mile 
120      = 74.5 miles/h
 h  1 km  1 m  5280 ft 


 km  1000 m  3.28 ft  1 h 
120      = 109.3 ft/s
 h  1 km  1 m  3600 s 

3
 3.28 ft 
100 (m 3 )  = 3529 ft
3

 1m 




© 2023 Cengage. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible 2-1
website, in whole or in part.

, Solution and Answer Guide: Moaveni, Energy, Environment, and Sustainability 2e 2023, 9780357676073; Chapter 2:
Fundamental Dimensions and Systems of Units

 2.2046 lbm 
80 (kg )  = 176.4 lbm
 1 kg 


 224.809 × 10-3 lbf 
900 (N )  = 202.3 lbf

 1N 


 m  3.28 ft  ft
9.81  2   = 32.2 2
 s  1 m  s




2.2 Convert the information given in the accompanying table from U.S. Customary to SI
units. Show all steps of your solutions. See Example 2.3.




Solution
 miles  5280 ft  1 km  1 m 
65     = 104.6 km/h
 h  1 mile  1 000 m  3.28 ft 

 km  1000 m  1 h 
104.6     = 29 m/s
 h  1 km  3600 s 

3
 lbm  1 kg   3.28 ft  3
120  3     = 1,920 kg/m
 ft  2.2046 lbm   1 m 

 1 kg 
200 ( lbm )   = 90.7 kg
 2.2046 lbm 




© 2023 Cengage. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible 2-2
website, in whole or in part.

, Solution and Answer Guide: Moaveni, Energy, Environment, and Sustainability 2e 2023, 9780357676073; Chapter 2:
Fundamental Dimensions and Systems of Units


 1N 
200 ( lbf )  -3  = 890 N
 224.809 ×10 lbf 



2.4 A house has a given floor space of 2,000 ft2. Convert this area to m2.



Solution
2
 1m 
2
=A (2000
= ft )   185.9 m 2
 3.28 ft 




2.5 Calculate the volume of water in a large swimming pool with dimensions of 50 m ×
25 m × 2 m. Express your answer in liters, m3, gallons, and ft3.



Solution
V = (50 m)(25 m)(2 m) = 2,500 m 3
3
 100 cm   1 liter 
3
V (2,500
= m )   3 
2,500,000 liters
 1 m   1000 cm 
3
 3.28 ft  3
=V (2,500
= m )  88,219 ft 3
 1 m 
 7.48 gallons 
V (88,219 ft 3 )   ≈ 660,000 gallons
 1 ft 3 




2.6 A 500-sheet ream of copy paper has thickness of 2.25 in. What is the average
thickness of each sheet in mm?



Solution
2.25 in.  25.4 mm 
=Thickness =   0.1143 mm /sheet
500 sheets  1 in. 



© 2023 Cengage. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible 2-3
website, in whole or in part.

, Solution and Answer Guide: Moaveni, Energy, Environment, and Sustainability 2e 2023, 9780357676073; Chapter 2:
Fundamental Dimensions and Systems of Units

2.7 A barrel can hold 42 gallons of oil. How many liters of oil are in the barrel?



Solution
3.78 liters
42 gallons × = 158.76 liters
gallon




2.8 Express the kinetic energy [½ (mass)(speed)2] of a car with a mass of 1,200 kg
moving at a speed of 100 km/h. First, you need to convert the speed from km/h to
the fundamental units of m/s. Show the conversion steps. (Note: We explain the
concept of kinetic energy in Chapter 5.)



Solution
 km   1 h  1 000 m 
speed = (100)    = 27.7 m/s
 h   3600 s  1 km 
1 m 2 m
K. E. = � � (1200 kg) �27.7 � = 4.6 × 105 kg⋅ 2 ⋅m = 4.6 × 105 N⋅m = 4.6 × 105 J
2 s s



5 1 ft⋅lbf 5
K.E. = (4.6 × 10 J) � � = 3.4 × 10 ft⋅lbf
1.3558 J




2.9 A machine shop has a rectangular floor shape with dimensions of 30 ft by 50 ft.
Express the area of the floor in ft2, m2, in2, and cm2. Show the conversion steps.



Solution
A = (30 ft)(50 ft) = 1500 ft 2
2
 1m 
A = (1500 ft 2 )  = 139.4 m
2

 3.28 ft 
2
 12 in 
A = (1500 ft 2 )  = 216,000 in
2

 1 ft 


© 2023 Cengage. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible 2-4
website, in whole or in part.

, Solution and Answer Guide: Moaveni, Energy, Environment, and Sustainability 2e 2023, 9780357676073; Chapter 2:
Fundamental Dimensions and Systems of Units

2
 1 cm 
2
=A (1500 ft )  =  139.4 ×104 cm 2
 0.0328 ft 




2.10 A trunk of a car has a listed luggage capacity of 18 ft3. Express the capacity in in3, m3,
and cm3. Show the conversion steps.



Solution
3
3 12 in 
=V (18
= ft )   31,104 in 3
 1 ft 
3
3 1m 
=V (18
= ft )   0.51 m3
 3.28 ft 
3
 1 cm 
V= (18 ft 3 )  = 51×104 cm3
 0.0328 ft 




2.11 An automobile has a 3.5-liter engine. Express the engine size in in3. Show the
conversion steps. Note that 1 liter is equal to 1,000 cm3.



Solution
3
 1000 cm3   1 in 
V (3.5
= liters)    214 in 3
 1 liter   2.54 cm 


2.12 The density of air that we breathe at standard room conditions is 1.2 kg/m3. Express
the density in U.S. Customary units. Show the conversion steps.



Solution
kg 1m 3 1 lbm lbm
Density = 1.2 � � � � � � = 0.075 3
m 3 3.28 ft 0.4536 kg ft




© 2023 Cengage. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible 2-5
website, in whole or in part.

, Solution and Answer Guide: Moaveni, Energy, Environment, and Sustainability 2e 2023, 9780357676073; Chapter 2:
Fundamental Dimensions and Systems of Units




2.13 On a summer day in Phoenix, Arizona, the inside room temperature is maintained
at 68°F while the outdoor air temperature is a sizzling 110°F. What is the outdoor–
indoor temperature difference in degrees (a) Fahrenheit or (b) Celsius?



Solution
(a) Toutdoor − Tindoor = 110 F − 68 F = 42 F

5 5
(b) Toutdoor (  C) = (Toutdoor (  F) − 32) = (110 − 32) = 43.3 C
9 9
5 5
Tindoor (  C) = (Tindoor (  F) − 32) = (68 − 32) = 20 C
9 9
Toutdoor − Tindoor = 43.3 C − 20  C = 23.3 C




2.14 A person who is 180 cm tall and weighs 750 newtons is driving a car at a speed of 90
kilometers per hour over a distance of 80 kilometers. The outside air temperature is
30°C and has a density of 1.2 kg/m3. Convert all of the values given from SI to U.S.
Customary units.



Solution
Person's height, H

1 ft
H = (180 cm)( ) = 5.9 ft
30.48 cm


Person's weight, W

1 lbf
W = (750 N)( ) = 168.6 lbf
4.448N


Speed of the car, S = 90 km/h = 90,000 m/h

m 1 ft 1 mile
S (90,000
= )( )( ) 55.9 (miles/h)
h 0.3048 m 5280 ft


© 2023 Cengage. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible 2-6
website, in whole or in part.

, Solution and Answer Guide: Moaveni, Energy, Environment, and Sustainability 2e 2023, 9780357676073; Chapter 2:
Fundamental Dimensions and Systems of Units

Distance traveled, D

1000 m 1 ft 1 mile
D (80
= km)( )( )( ) 49.7 miles
1 km 0.3048 m 5280 ft


Temperature of air, T

9
T (°C) = (30) + 32 = 86°F
5


Density of air, ρ
3
kg 1 lbm  0.3048 m  3
ρ (1.2
= 3
)( )  0.075(lbm/ft )
m 0.453 kg  1 ft 




2.15 Convert the given values: (a) area A = 16 in2 to ft2 and (b) volume V = 64 in3 to ft3.



Solution
1 ft 2
(a) (16 in 2 )( 2
) = 0.1111 ft 2
144 in


1 ft 3
(b) (64 in 3 )( ) = 0.037 ft 3
12 in


2.16 The acceleration due to gravity g is 9.81 m/s2. Express the value of g in U.S.
Customary units. Show all conversion steps.



Solution
1 ft
(9.81 m/s 2 )( ) = 32.18 ft/s 2
0.3048 m




© 2023 Cengage. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible 2-7
website, in whole or in part.

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