Integration
Satyabrat Sahu
February 2024
Integration Problem
Q1 Prove that:
5 Z π
X 4 cos x − sin x π3
logk 4 + 5π 2
I= dx =
−π cos x + sin x 32
k=1 4
√
n √
sin x − n cos x
Z
Q2 Ω(n) = √
n √ √ √ dx(n ∈ N, n ≥ 2)
( sin x + n
cos x)( 2n sin x + n cos x)
Q3 Find:
∞ ∞
log3 (x) log2 (x)
Z Z
3
Ω(a, b) = − log(ab) , a, b > 0
0 (x + a)(x + b) 2 0 (x + a)(x + b)
Q4 Prove the integral relation:
Z πs √ p√ !
csc y2 + π4
3 ( 4 2 + 1)( 2 + 2 − 1)
y
√ dy = 2 4 log √ p√
0 2 cos 2 + 2 ( 4 2 − 1)( 2 + 2 + 1)
Q5 Find:
"n+1 k1 # " n 1 #!−1
X 1 X 1 k+1
Ω = lim 1− · 1+ , [∗] − GIF
n→∞ k k
k=2 k=1
Q6 Prove that:
1
√ !
1 + 1 − x2
Z
1+x 1
16G − π 2
Ω= log log √ dx =
0 1−x 1− 1−x 2 2
1
Satyabrat Sahu
February 2024
Integration Problem
Q1 Prove that:
5 Z π
X 4 cos x − sin x π3
logk 4 + 5π 2
I= dx =
−π cos x + sin x 32
k=1 4
√
n √
sin x − n cos x
Z
Q2 Ω(n) = √
n √ √ √ dx(n ∈ N, n ≥ 2)
( sin x + n
cos x)( 2n sin x + n cos x)
Q3 Find:
∞ ∞
log3 (x) log2 (x)
Z Z
3
Ω(a, b) = − log(ab) , a, b > 0
0 (x + a)(x + b) 2 0 (x + a)(x + b)
Q4 Prove the integral relation:
Z πs √ p√ !
csc y2 + π4
3 ( 4 2 + 1)( 2 + 2 − 1)
y
√ dy = 2 4 log √ p√
0 2 cos 2 + 2 ( 4 2 − 1)( 2 + 2 + 1)
Q5 Find:
"n+1 k1 # " n 1 #!−1
X 1 X 1 k+1
Ω = lim 1− · 1+ , [∗] − GIF
n→∞ k k
k=2 k=1
Q6 Prove that:
1
√ !
1 + 1 − x2
Z
1+x 1
16G − π 2
Ω= log log √ dx =
0 1−x 1− 1−x 2 2
1