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AAMC FL 2 Questions with Detailed
Verified Answers
Question: Absorption of ultraviolet light by organic molecules always results
in what process?
A.Bond breaking
B.Excitation of bound electrons
C.Vibration of atoms in polar bonds
D.Ejection of bound electrons
Ans: The answer to this question is B. The absorption of ultraviolet light by
organic molecules always results in electronic excitation. Bond breaking
can subsequently result, as can ionization or bond vibration, but none of
these processes are guaranteed to result from the absorption of ultraviolet
light.
Question: Ionization
Ans: the process of adding or removing electrons from an atom or
molecule, which gives the atom or molecule a net charge
Question: Rf equation
Ans: distance moved by substance/distance moved by solvent
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Question: is alcohol or carboxylic acid more polar?
Ans: carboxylic acid
Question: half life of a radioactive material
Ans: the time it takes for half of all the radioactive nuclei to decay into
their daughter nuclei, which may or may not be radioactive
Question: The person is in equilibrium...
Ans: only when the center of mass is directly above their feet. otherwise, if
the person did not lean forward or slide the feet under the chair, the
person would fall backward due to the large torque created by the
combination of the weight of the body (applied at the persons center of
mass) and the distance along the horizontal between the center of mass
and the support point.
Question: ground state
Ans: The lowest energy state of an atom
Question: Based on the relative energy of the absorbed electromagnetic
radiation, which absorber, a peptide bond or an aromatic side chain, exhibits
an electronic excited state that is closer in energy to the ground state?
A.An aromatic side chain; the absorbed photon energy is higher.
B.An aromatic side chain; the absorbed photon energy is lower.
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C.A peptide bond; the absorbed photon energy is higher.
D.A peptide bond; the absorbed photon energy is lower.
Ans: The answer to this question is B because aromatic side chains absorb
in the near UV region of the electromagnetic spectrum, which has longer
wavelengths, and hence lower energy, than peptide bonds. Because the
energy of the photon matches the energy gap between the ground and the
excited state, this implies that the aromatic side chain has more closely
spaced energy levels.
Question: In designing the experiment, the researchers used which type of
32P labeled ATP?
A.α32P-ATP
B.β32P-ATP
C.γ32P-ATP
D.δ32P-ATP
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Ans: The answer to this question is C because the phosphoryl transfer
from kinases comes from the γ-phosphate of ATP. Therefore, the
experiment should require γ32P-ATP.
In an ATP molecule, the phosphate attached to the ribose sugar is the
alpha phosphate. After that, it's the beta, and then the gamma. Since the
gamma phosphate is what kinases attach to proteins, that's the one which
the researchers would want to label.
Question: When used in place of spHM, which peptide would be most likely to
achieve the same experimental results?
A.FLGFAY
B.FLGFQY
C.FLGFGY
D.FLGFEY
AAMC FL 2 Questions with Detailed
Verified Answers
Question: Absorption of ultraviolet light by organic molecules always results
in what process?
A.Bond breaking
B.Excitation of bound electrons
C.Vibration of atoms in polar bonds
D.Ejection of bound electrons
Ans: The answer to this question is B. The absorption of ultraviolet light by
organic molecules always results in electronic excitation. Bond breaking
can subsequently result, as can ionization or bond vibration, but none of
these processes are guaranteed to result from the absorption of ultraviolet
light.
Question: Ionization
Ans: the process of adding or removing electrons from an atom or
molecule, which gives the atom or molecule a net charge
Question: Rf equation
Ans: distance moved by substance/distance moved by solvent
, Page | 2
Question: is alcohol or carboxylic acid more polar?
Ans: carboxylic acid
Question: half life of a radioactive material
Ans: the time it takes for half of all the radioactive nuclei to decay into
their daughter nuclei, which may or may not be radioactive
Question: The person is in equilibrium...
Ans: only when the center of mass is directly above their feet. otherwise, if
the person did not lean forward or slide the feet under the chair, the
person would fall backward due to the large torque created by the
combination of the weight of the body (applied at the persons center of
mass) and the distance along the horizontal between the center of mass
and the support point.
Question: ground state
Ans: The lowest energy state of an atom
Question: Based on the relative energy of the absorbed electromagnetic
radiation, which absorber, a peptide bond or an aromatic side chain, exhibits
an electronic excited state that is closer in energy to the ground state?
A.An aromatic side chain; the absorbed photon energy is higher.
B.An aromatic side chain; the absorbed photon energy is lower.
, Page | 3
C.A peptide bond; the absorbed photon energy is higher.
D.A peptide bond; the absorbed photon energy is lower.
Ans: The answer to this question is B because aromatic side chains absorb
in the near UV region of the electromagnetic spectrum, which has longer
wavelengths, and hence lower energy, than peptide bonds. Because the
energy of the photon matches the energy gap between the ground and the
excited state, this implies that the aromatic side chain has more closely
spaced energy levels.
Question: In designing the experiment, the researchers used which type of
32P labeled ATP?
A.α32P-ATP
B.β32P-ATP
C.γ32P-ATP
D.δ32P-ATP
, Page | 4
Ans: The answer to this question is C because the phosphoryl transfer
from kinases comes from the γ-phosphate of ATP. Therefore, the
experiment should require γ32P-ATP.
In an ATP molecule, the phosphate attached to the ribose sugar is the
alpha phosphate. After that, it's the beta, and then the gamma. Since the
gamma phosphate is what kinases attach to proteins, that's the one which
the researchers would want to label.
Question: When used in place of spHM, which peptide would be most likely to
achieve the same experimental results?
A.FLGFAY
B.FLGFQY
C.FLGFGY
D.FLGFEY
