Portage Learning Chemistry CHEM 103 Unit 3 Exam With Correct Answers 2025/2026

Portage Learning Chemistry CHEM 103 Unit 3 Exam With Correct Answers 2025/2026 Heat temp change = qtemp change = m x c x ∆t -(40.5 x 4.184 x (∆t - 85.7)) = 36.8 x 4.184 x (∆t - 26.3) -(169.452 x (∆t - 85.7)) = 153.9712 x (∆t - 26.3) -(169.452∆t - 14522.0364) = 153.9712∆t - 4049.44256 -169.452∆t + 14522.0364 = 153.9712∆t - 4049.44256 18571.479 = 323.423∆t 57.4 C = ∆t - Correct Answer 1. Show the calculation of the final temperature of the mixture when a 40.5 gram sample of water at 85.7C is added to a 36.8 gram sample of water at 26.3C in a coffee cup calorimeter. c (water) = 4.184 J/g C qs↔l = mass x Heat of Fusion = m x ∆Hfusion 120 x 0.334 = 40.08 kJ - Correct Answer 2. Show the calculation of the energy involved in melting 120 grams of ice at 0oC if the Heat of Fusion for water is 0.334 kJ/g. moles = grams/molecular weight moles (S) = 42.8/32.07 = 1.335 mols S