Portage Learning Chemistry CHEM 103 Unit 5
As33 (nonmetal = gain electrons) 1s2
What will be the charge of the ion formed 2s2 2p6 3s2 3p6 4s2 3d10 4p3
from each of these atoms? Explain your gain 3 ’ As-3
answer.
Ge32 (metal = lose electrons) 1s2 2s2
As33, Ge32 2p6 3s2 3p6 4s2 3d10 4p2
lose 4 ’ Ge+4
1) Cl-O bond electronegativity difference
= 3.5 - 3.0 = 0.5
(1.6 - 0.5 bond is Polar)
H-O bond electronegativity difference =
3.5 - 2.1 = 1.4
(1.6 - 0.5 bond is Polar)
2) CaN bond electronegativity difference =
Using the electronegativity values from 3.0 - 2.5 = 0.5
the equation bank, show the determina- (1.6 - 0.5 bond is Polar)
tion of the polarity of each different type H-C bond electronegativity difference =
of bond in the following molecules: 2.5 - 2.1 = 0.4
(< 0.5 bond is Nonpolar)
Your Answer:
NH3
N = 5, H = 3, 8 total
H
..
H:N:H
..
SO2
S = 6, O = 12, total = 18
.. .. ..
: O : S :: O
.. ..
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, Portage Learning Chemistry CHEM 103 Unit 5
CH3OH
C = 4, H = 4, O = 6, total = 14
H
.. ..
H:C:O:H
Write Lewis dot structures for the follow-
.. ..
ing molecules:
H
HNO2
NH3
H = 1, N = 5, O = 12, total = 18
SO2
.. .. ..
CH3OH
H:O:N::O:
HNO2
..
N2
N2
CH2O
N = 10
: N ::: N :
CH2O
C = 4, H = 2, O = 6, total = 12
.. ..
H : C :: O : H
1.) PH3 4 Groups of electrons around P
= Tetrahedral Electron Geometry
Tetrahedral Electron Geometry = sp3 Hy-
bridization of P
3 atoms around central Tetrahedral atom
Determine and explain for each of the = Triangular pyramid shape
materials below (a) Electron geometry P-H bond (2.1-2.1) is nonpolar = all non-
of a Central atom, (b) Hybridization of a polar bonds = Nonpolar molecular polar-
Central atom, (c) Shape of the Molecule, ity
(d) Molecular Polarity
2.) HCN 2 Groups of electrons around C
1.) PH3 = Linear Electron Geometry
Linear Electron Geometry = sp Hy-
2.) HCN bridization of C
2 atoms around central Linear atom =
Linear shape
CH bond (2.5-2.1) is nonpolar
CaN bond (3.0-2.5) is polar = at least one
polar bonds = Polar molecular polarity
2/5
As33 (nonmetal = gain electrons) 1s2
What will be the charge of the ion formed 2s2 2p6 3s2 3p6 4s2 3d10 4p3
from each of these atoms? Explain your gain 3 ’ As-3
answer.
Ge32 (metal = lose electrons) 1s2 2s2
As33, Ge32 2p6 3s2 3p6 4s2 3d10 4p2
lose 4 ’ Ge+4
1) Cl-O bond electronegativity difference
= 3.5 - 3.0 = 0.5
(1.6 - 0.5 bond is Polar)
H-O bond electronegativity difference =
3.5 - 2.1 = 1.4
(1.6 - 0.5 bond is Polar)
2) CaN bond electronegativity difference =
Using the electronegativity values from 3.0 - 2.5 = 0.5
the equation bank, show the determina- (1.6 - 0.5 bond is Polar)
tion of the polarity of each different type H-C bond electronegativity difference =
of bond in the following molecules: 2.5 - 2.1 = 0.4
(< 0.5 bond is Nonpolar)
Your Answer:
NH3
N = 5, H = 3, 8 total
H
..
H:N:H
..
SO2
S = 6, O = 12, total = 18
.. .. ..
: O : S :: O
.. ..
1/5
, Portage Learning Chemistry CHEM 103 Unit 5
CH3OH
C = 4, H = 4, O = 6, total = 14
H
.. ..
H:C:O:H
Write Lewis dot structures for the follow-
.. ..
ing molecules:
H
HNO2
NH3
H = 1, N = 5, O = 12, total = 18
SO2
.. .. ..
CH3OH
H:O:N::O:
HNO2
..
N2
N2
CH2O
N = 10
: N ::: N :
CH2O
C = 4, H = 2, O = 6, total = 12
.. ..
H : C :: O : H
1.) PH3 4 Groups of electrons around P
= Tetrahedral Electron Geometry
Tetrahedral Electron Geometry = sp3 Hy-
bridization of P
3 atoms around central Tetrahedral atom
Determine and explain for each of the = Triangular pyramid shape
materials below (a) Electron geometry P-H bond (2.1-2.1) is nonpolar = all non-
of a Central atom, (b) Hybridization of a polar bonds = Nonpolar molecular polar-
Central atom, (c) Shape of the Molecule, ity
(d) Molecular Polarity
2.) HCN 2 Groups of electrons around C
1.) PH3 = Linear Electron Geometry
Linear Electron Geometry = sp Hy-
2.) HCN bridization of C
2 atoms around central Linear atom =
Linear shape
CH bond (2.5-2.1) is nonpolar
CaN bond (3.0-2.5) is polar = at least one
polar bonds = Polar molecular polarity
2/5
