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Chsaa Rules Test most recent version Comprehensive 100 questions and verified answers accurate solutions Already graded A+ Get it 100% correct

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Chsaa Rules Test most recent version Comprehensive 100 questions and verified answers accurate solutions Already graded A+ Get it 100% correct

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Chsaa Rules
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Chsaa Rules Test 2025-2026 most recent version
Comprehensive 100 questions and verified
answers accurate solutions Already graded A+
Get it 100% correct
A 1.5V battery connects to a 10 ohm resistor. The power dissipated by the resistor is -
CORRECT ANSWER: P=V^2/R

P=1.5^2/10

P=0.23 W


a 9.0 Vbattery connects to a wire resistor. The wire resistor is tungsten (resistor
5.6x10^-8) 0.5m long has a radius of 1.2x10^-5m. What is the current through the
resistor - CORRECT ANSWER: 0.15 A


A battery connects to a resistor with resistance R and the resulting current is measured.
The resistor is removed and a new resistor with a resistance of 2R is added. As a result
- CORRECT ANSWER: the voltage will double

the current will double

the charge speed will double
none of the above will options are correct!!



a battery connects to a resistor. The rate of energy dissipated by the resistor is 1.44 W
The rate of energy supplied by the battery is - CORRECT ANSWER: equal to 1.44 W



A battery with a potential difference of V connects to a resistor, and the resulting current
is measured. You remove the battery, and a new battery with a potential difference of
2Vis put in its place. As a result - CORRECT ANSWER: the current will double



A battery with an emf of 12V connects in parallel to a 50 ohm and 25 ohm resistor. The
current through the battery is 0.70 A. What is the internal resistance of the battery -
CORRECT ANSWER: 50 x+25 +16.6

,E=I(Req +r)

12=0.7(16.6 +r)

12=11.66 +0.7r

0.333=0.7r
0.54 ohm



A charged particle moving to the right enters a uniform magnetic field directed into the
page. The charged particle experiences a magnetic force. Which of the following is a
true statement (disregard any gravitational effects) - CORRECT ANSWER: The speed
of the of the particle will remain the same



A device plugged into a wall outlet experiences an alternating current. The RMS current
value is 2A. The peak current is - CORRECT ANSWER: 2x sqrt2

=2.8


A light bulb connects to a battery. A second, identical light bulb connects in parallel to
the first light bulb. The connecting wires have negligible resistance. When the switch is
closed, the original light bulb will - CORRECT ANSWER: experience no change in
brightness



A negatively charged particle moves through various electric fields. Which of the
following correctly indicates whether the negatively charged particle gained or lost
energy in each of the following examples - CORRECT ANSWER: gained energy

lost energy

gained energy


A particle with a charge of +2uC is at the position marked by x. Which statement
concerning the particle's energy is most accurate? - CORRECT ANSWER: The particle
will have a positive energy term

, A particle with a mass of 0.01 kg and a net charge of -0.05 C accelerates from rest
through a uniform electric field. If the strength of the field is 2000 V/C, what is the speed
of the particle after traveling for 0.5 m? - CORRECT ANSWER: Fd=1/2mv^2

qEd=1/2mv^2

sqrt(2qEd/m)=v



sqrt(2 (0.05) (2000) (.5)/0.01



100m/s


A particle with a net charge of -2uC is halfway between two particles with a net charge
of +4 uC and +6uC respectively. The two positively charged particles are 10 cm apart.
What is the magnitude of the net force on the negative particle - CORRECT ANSWER:
F=kqq/r^2

9x10^9 (4x10^-6)(4x10^-6)/.1^2

14.4


A particular alternating voltage supply completes one full voltage cycle at a frequency -
CORRECT ANSWER: equal to 10Hz


A positive particle begins at a position near a negative plate and ends at a position near
a positively charged plate. Which statement is most accurate - CORRECT ANSWER:
work is done on the particle so that the particle will end with more energy


A positively charged 2mC particle moving in the upward direction at a speed of 20m/s
enters a 3.0T field directed into the page. The particle path curves with a radius of 6cm.
What is the mass of the particle - CORRECT ANSWER: qvB= mv^2/r

m=qbr/v

m= (2x10^-3) (3T) 0.06)/20
1.8 x10^-5

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Tutordiligent is a Medical Professional with a Bachelor of Medicine and Bachelor of Surgery (MBBS) from Chamberlain College of Nursing of Health Sciences. His academic journey included internships in Radiology, Cardiology, and Neurosurgery. His contributions to medical research extend to two publications in medical journals, solidifying his position as a promising addition to the field.

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