Mathematics Sums with Solutions (Class 5, 6, 7)
Class 5
Q1. Add: 3/4 + 5/6
Solution: LCM of 4 and 6 = 12 → 9/12 + 10/12 = 19/12 = 1 7/12
Q2. Convert 2.75 into fraction.
Solution: 2.75 = 275/100 = 11/4
Q3. Find perimeter of square with side 8 cm.
Solution: Perimeter = 4 × 8 = 32 cm
Q4. If a book costs ■45, what is cost of 7 books?
Solution: 45 × 7 = ■315
Class 6
Q1. Simplify: 2/3 ÷ 4/5
Solution: 2/3 ÷ 4/5 = 2/3 × 5/4 = 10/12 = 5/6
Q2. Solve: x + 7 = 15
Solution: x = 15 – 7 = 8
Q3. Find area of rectangle length=12 cm, breadth=8 cm.
Solution: Area = 12 × 8 = 96 cm²
Q4. Ratio of 20:60 in simplest form?
Solution: 20/60 = 1/3 → Ratio = 1:3
Class 7
Q1. Simplify: (-7) + 12
Solution: = 5
Q2. Solve: 2x – 5 = 9
Solution: 2x = 9+5 = 14 → x = 7
Q3. Perimeter of circle radius 7 cm (π=22/7)?
Solution: 2πr = 2×22/7×7 = 44 cm
Q4. The marks of 5 students: 20, 25, 30, 35, 40. Find mean.
Solution: Sum = 150, Mean = 150/5 = 30
Class 5
Q1. Add: 3/4 + 5/6
Solution: LCM of 4 and 6 = 12 → 9/12 + 10/12 = 19/12 = 1 7/12
Q2. Convert 2.75 into fraction.
Solution: 2.75 = 275/100 = 11/4
Q3. Find perimeter of square with side 8 cm.
Solution: Perimeter = 4 × 8 = 32 cm
Q4. If a book costs ■45, what is cost of 7 books?
Solution: 45 × 7 = ■315
Class 6
Q1. Simplify: 2/3 ÷ 4/5
Solution: 2/3 ÷ 4/5 = 2/3 × 5/4 = 10/12 = 5/6
Q2. Solve: x + 7 = 15
Solution: x = 15 – 7 = 8
Q3. Find area of rectangle length=12 cm, breadth=8 cm.
Solution: Area = 12 × 8 = 96 cm²
Q4. Ratio of 20:60 in simplest form?
Solution: 20/60 = 1/3 → Ratio = 1:3
Class 7
Q1. Simplify: (-7) + 12
Solution: = 5
Q2. Solve: 2x – 5 = 9
Solution: 2x = 9+5 = 14 → x = 7
Q3. Perimeter of circle radius 7 cm (π=22/7)?
Solution: 2πr = 2×22/7×7 = 44 cm
Q4. The marks of 5 students: 20, 25, 30, 35, 40. Find mean.
Solution: Sum = 150, Mean = 150/5 = 30
