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MATH 110 Final exam SUMMER 2025 Portage learning

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The following pie chart shows the percentages of total items sold in a month in a certain fast food restaurant. A total of 5300 fast food items were sold during the month. a.)How many were burgers? b.) How many were chickens? Your Answer: a) burgers 5300 (.27) = 1431 b) chickens 5300 (.23) = 1219 a.) Burgers : 5300(.27) = 1431 b.)Chicken : 5300(.23) = 1219

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Institution
MATH 110
Course
MATH 110

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Question 1
Not yet graded / 10 pts
You may find the following files helpful throughout the exam:
Statistics_Equation_SheetLinks to an external site.


The following pie chart shows the percentages of total items sold in a month
in a certain fast food restaurant.




A total of 5300 fast food items were sold during the month.

a.)How many were burgers?

b.) How many were chickens?
Your Answer:
a) burgers 5300 (.27) = 1431
b) chickens 5300 (.23) = 1219
a.) Burgers : 5300(.27) = 1431

b.)Chicken : 5300(.23) = 1219


Question 2
Not yet graded / 10 pts
You may find the following files helpful throughout the exam:
Statistics_Equation_SheetLinks to an external site.

, Consider the following data:
27 46 74 40 44 65 33 76 50 58 31 37 70 41 61 51 56 73 48 53
Find the 30th percentile of this data.
Your Answer:
27,31,33,37,40,41,44,46,48,50,51,53,56,58,61,65,70,73,74,76
i(p/100)n = (30/100) 20 = 6
the 30th percentile is the the 6 observation is 41
There are a total of twenty numbers, so n= 20. In order to find the
percentiles, we must put the numbers in ascending order:
27 31 33 37 40 41 44 46 48 50 51 53 56 58 61 65
70 73 74 76
For the 30th percentile:


Therefore, the 30th percentile index for this data set is the 6th
observation. In the list above, the 6th observation is 41.


Question 3
Not yet graded / 10 pts
You may find the following files helpful throughout the exam:
Statistics_Equation_SheetLinks to an external site.


In a tri-state conference, 40% attendees are from California, 10% from
Oregon, and 50% from Washington. As it turns out 8 % of the attendees from
California, 11% of the attendees from Oregon, and 13% of the attendees
from Washington came to the conference by train. If an attendee is selected
at random and found to have arrived by train, what is the probability that the
person is from California?
Your Answer:
Bayes Theorum
P(c) = .40 P(T|c) = .08
P(o) = .10 P(T|o) = .11
P(w) = .50 P(T|w) = .13

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