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Summary Shorts notes and MINDMAP

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Short notes and MINDMAP for neet 2026 based on full ncert

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INERTIA NEWTON‛S THIRD LAW Inclined Forces
A body cannot change its state of rest or -To every action, there is always an equal Fsin If,Fsinθ<Mg
PULLEY-BLOCK SYSTE
uniform motion along a straight line. This (in magnitude ) and opposite (in direction) reaction. N a blockremainsin
F contactwithground Ideal pulley
property is called inertia.Inertia has no - Forces in nature always occur in pairs. &accelerateshorizontally
unit and no dimension. M1 > M 2
- A single isolated force is not possible. M Fcos
If,Fsinθ=Mg F M 1- M
INERTIA - Counter force experienced by a body- reaction blockjustleaves a= =
contactwithground
M M1 + M
- Action and reaction never act on the same body Mg
2M1M2
If, Fsinθ >Mg T = g
Inertia Inertia Inertia of * Force exerted on body A by body B (action ) M1 + M2
Direction
the block leaves contact with ground and
of Rest of Motion * force exerted on body B by body A (reaction)
it begins to accelerate obliquily.
- Inertia of Rest Reaction(onA)

Inability to change state of rest by itself. FAction=-FReaction MOTION OF CONNECTED BODIES
A
- Inertia of Motion
B a
Inability of a body to change its state of Some common forces Action(onB) F 1 > F2
uniform motion by itself. 1.Normal Reaction F1 - F2 = Ma M
F2 F1
- Inertia of Direction - Occurs when two surfaces are in contact with
each other F1 -F2
a=
Inability of a body to change direction of Always perpendicular to the surface. M
motion by itself.
NBW
Newton‛s Second Law NBg=NgB NBg NBW=NWB
(normalon NWB
Fnet= Rate of change of linear momentum.
blockby
ground) NWg=NgW
NWg
(normalon
Instantaneous Average NgB
groundby

Tension block)

NgW
F=dp p = pf-pi
Fav=
dt t t
INCLINED PLANE + P
T Restoring force developed
MOMENTUM T F
when a longitudnal force is
P=mv applied on a body
-It is a vector quantity having direction
same as that of velocity
-Unit is kg m/s. Ideal Rope
T here,f,f1 andf2 are
normalreactions
LIQUID JETS
*Massless T
betweenblocks
When jet is stopped at wall *Tension is same everywhere
u
wall
*Opposes only elongation
Area=A m *On compression it becomes slack. F
x MOTION OF BLOCKS CONNECTED BY MASSLESS STRING
v=0
*Tension always acts away from the object.
Pf-Pi mx0-mu Rod
Fjet= =
Δt Δt
T F T F
-mu Δx
= =-ρAu2 (m=ρAΔx, Δt
= u)
Δt
Elongation Compressive
Fwall = ρAu2
can support both elongation and compression
THICK ROPE
When liquid jet bounce back
+ve Tension will be diff
Pf-Pi -2mu
Fjet= =
Δt Δt u

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