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1. If sec = and  is an acute angle, then the value of 8(cosec – cot)
63
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;fn sec = gS vkSj  न्यून dks.k gS] rks 8(cosec–cot) dk eku Kkr djsaA SSC CHSL PRE 2022
63

(a) 8
(b) 4
(c) 2
(d) 1
2. If 𝒄𝒐𝒔𝒆𝒄𝟐𝜽 = 𝐬𝐞𝐜⁡(𝟑𝜽 − 𝟏𝟓°), then  is equal to:
यदि 𝒄𝒐𝒔𝒆𝒄𝟐𝜽 = 𝐬𝐞𝐜⁡(𝟑𝜽 − 𝟏𝟓°), तो  बराबर है. SSC CGL PRE 2021
(a) 220 (b) 200 (c) 250 (d) 210

(1 − sin  ) (sec  + tan  ) tan 
3. If 0o < 𝜃 < 90o, then =? SSC CGL PRE 2022
(ten  + sec  + 1) (cot  − cos e c  + 1)
(1 − sin  ) (sec  + tan  ) tan 
यदि 0o < 𝜃 < 90o rks dk eku Kkr djsAa
(ten  + sec  + 1) (cot  − cos e c  + 1)
(a) sin𝜃
𝒔𝒊𝒏 𝜃
(a)
2

(b) sin 𝜃
(c) cos𝜃
𝒄𝒐𝒔 𝜃
(d)
2
𝒔𝒊𝒏 33° 𝒄𝒐𝒔 57°+𝒔𝒆𝒄 62° 𝒔𝒊𝒏 28°+𝒄𝒐𝒔 33° 𝒔𝒊𝒏 57°+𝒄𝒐𝒔 𝑒𝑐62° 𝒄𝒐𝒔 28°
4. What is the value of ?
𝒕𝒂𝒏 15° 𝒕𝒂𝒏 35° 𝒕𝒂𝒏 60° 𝒕𝒂𝒏 55° 𝒕𝒂𝒏 75°
𝒔𝒊𝒏 33° 𝒄𝒐𝒔 57°+𝒔𝒆𝒄 62° 𝒔𝒊𝒏 28°+𝒄𝒐𝒔 33° 𝒔𝒊𝒏 57°+𝒄𝒐𝒔 𝑒𝑐62° 𝒄𝒐𝒔 28°
dk eku Kkr djsaA
𝒕𝒂𝒏 15° 𝒕𝒂𝒏 35° 𝒕𝒂𝒏 60° 𝒕𝒂𝒏 55° 𝒕𝒂𝒏 75°
√3
(a) ⁡⁡⁡⁡⁡⁡⁡⁡⁡⁡⁡⁡(b)2 (c)2√3⁡⁡⁡⁡⁡⁡⁡⁡⁡⁡⁡⁡⁡⁡(d)√3
3
𝒔𝒊𝒏 𝜃(1+𝒄𝒐𝒔 𝜃)
5. (√𝒔𝒆𝒄2 𝜃 + 𝒄𝒐𝒔 𝑒 𝑐 2 𝜃) ( ), 0° <  < 90° is equal to:
1+𝒄𝒐𝒔 𝜃−𝒔𝒊𝒏2 𝜃
𝒔𝒊𝒏 𝜃(1+𝒄𝒐𝒔 𝜃)
(√𝒔𝒆𝒄2 𝜃 + 𝒄𝒐𝒔 𝑒 𝑐 2 𝜃) ( ), __________ ds cjkcj gS] tgka 0° <  < 90° gSA. SSC CHSL,CGL PRE 2022
1+𝒄𝒐𝒔 𝜃−𝒔𝒊𝒏2 𝜃

(a)cot (b)cosec² (c)sec² (d)tan
6. If cosec 𝛉 + cosec2 𝛉 = 1 then cot12𝛉 – 3 cot10𝛉 +3 cot8𝛉-cot6𝛉 = ?
a)-2 b)-1 c)0 d)1
cosec 𝟐 θ+sec 𝟐 𝜽
7. If tan = √5, then the value of is:
cosec𝟐 θ-sec 𝟐 𝜽
cosec 𝟐 θ+sec 𝟐 𝜽
;fn tan = √5gS] rks dk eku Kkr djaAs
cosec 𝟐 θ-sec 𝟐 𝜽

SSC CHSL PRE 2023
𝟑
(a)
𝟐
𝟑
(b) −
𝟐
𝟕
(c) −
𝟓
𝟕
(d)
𝟓
𝟏 𝒔𝒊𝒏𝑨(𝒄𝒐𝒔𝑪+𝒄𝒐𝒔𝑨)
8. In ABC, right angled at B, if cot A= , then the value of is
𝟐 𝒄𝒐𝒔𝑪(𝒔𝒊𝒏𝑪−𝒔𝒊𝒏𝑨)
𝟏 𝒔𝒊𝒏𝑨(𝒄𝒐𝒔𝑪+𝒄𝒐𝒔𝑨)
ABC eas, B ledks.k gS] ;fn cot A= gS] rks dk eku Kkr djsAa . SSC CGL PRE 2023
𝟐 𝒄𝒐𝒔𝑪(𝒔𝒊𝒏𝑪−𝒔𝒊𝒏𝑨)

(a) –3
(b) 2
(c) 3
(d) –2

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