NRRPT Prep Complete Exam Questions
and Answers (Solved Papers)
Question Number: 1
Fundamentals of Radiation Protection
A low energy alpha detector is usually effective if the detector is distant from
the source.
A) 1/4 inch
B) 1/2 inch
C) 1 inch
D) 1 1/2 inches
E) 2 inches - Correct Answers ✅The correct answer is: A
Low energy alpha particles can only travel less than 1/2 inch in air. Therefore,
one must be closer than this to detect them.
Question Number: 2
Fundamentals of Radiation Protection
A sample of I-131 (half life = 8 days) is kept for 80 days, at which time the
activity is 1 µCi . What was the original activity?
A) 2.0 mCi
B) 1.0 mCi
C) 1.5 mCi
D) 3.5 mCi
E) 4.0 mCi - Correct Answers ✅The correct answer is: B
,NRRPT Prep Complete Exam Questions
and Answers (Solved Papers)
After 10 half lives, the remaining activity is approximately 1000th of the
original amount. Therefore, if there was 1µCi left after 10 half lives, then
there must have been 1000 times more to start with. Hence, 1 µCi * 1000 =
1 mCi.
Question Number: 3
Fundamentals of Radiation Protection
A sample of radioactive material is reported to contain 2000 picocuries of
activity. Express this value as disintegrations per minute.
A) 370 dpm
B) 900 dpm
C) 3770 dpm
D) 4440 dpm
E) 5320 dpm - Correct Answers ✅The correct answer is: D
dps = (2000 pCi)(1 x 10-12Ci/pi )(3.7x1010 dps/Ci) dps = 74
dpm = (74 dps) (60 sec/min)
dpm = 4440
Remember to convert to disintegrations per minute not DISINTEGRATIONS
PER SECOND.
Question Number: 1
Fundamentals of Radiation Protection
A low energy alpha detector is usually effective if the detector is distant from
the source.
,NRRPT Prep Complete Exam Questions
and Answers (Solved Papers)
A) 1/4 inch
B) 1/2 inch
C) 1 inch
D) 1 1/2 inches
E) 2 inches - Correct Answers ✅The correct answer is: A
Low energy alpha particles can only travel less than 1/2 inch in air. Therefore,
one must be closer than this to detect them.
Question Number: 2
Fundamentals of Radiation Protection
A sample of I-131 (half life = 8 days) is kept for 80 days, at which time the
activity is 1 µCi . What was the original activity?
A) 2.0 mCi
B) 1.0 mCi
C) 1.5 mCi
D) 3.5 mCi
E) 4.0 mCi - Correct Answers ✅The correct answer is: B
After 10 half lives, the remaining activity is approximately 1000th of the
original amount. Therefore, if there was 1
µCi left after 10 half lives, then there must have been 1000 times more to
start with. Hence, 1 µCi * 1000 = 1 mCi.
Question Number: 3
, NRRPT Prep Complete Exam Questions
and Answers (Solved Papers)
Fundamentals of Radiation Protection
A sample of radioactive material is reported to contain 2000 picocuries of
activity. Express this value as
disintegrations per minute.
A) 370 dpm
B) 900 dpm
C) 3770 dpm
D) 4440 dpm
E) 5320 dpm - Correct Answers ✅The correct answer is: D
dps = (2000 pCi)(1 x 10-12Ci/pi )(3.7x1010 dps/Ci) dps = 74
dpm = (74 dps) (60 sec/min)
dpm = 4440
Remember to convert to disintegrations per minute not DISINTEGRATIONS
PER SECOND.
Question Number: 4
Fundamentals of Radiation Protection
A sample of wood from an ancient forest showed 93.75% of the Carbon-14
decayed. How many half lives did the carbon go through?
A) 1
B) 2
and Answers (Solved Papers)
Question Number: 1
Fundamentals of Radiation Protection
A low energy alpha detector is usually effective if the detector is distant from
the source.
A) 1/4 inch
B) 1/2 inch
C) 1 inch
D) 1 1/2 inches
E) 2 inches - Correct Answers ✅The correct answer is: A
Low energy alpha particles can only travel less than 1/2 inch in air. Therefore,
one must be closer than this to detect them.
Question Number: 2
Fundamentals of Radiation Protection
A sample of I-131 (half life = 8 days) is kept for 80 days, at which time the
activity is 1 µCi . What was the original activity?
A) 2.0 mCi
B) 1.0 mCi
C) 1.5 mCi
D) 3.5 mCi
E) 4.0 mCi - Correct Answers ✅The correct answer is: B
,NRRPT Prep Complete Exam Questions
and Answers (Solved Papers)
After 10 half lives, the remaining activity is approximately 1000th of the
original amount. Therefore, if there was 1µCi left after 10 half lives, then
there must have been 1000 times more to start with. Hence, 1 µCi * 1000 =
1 mCi.
Question Number: 3
Fundamentals of Radiation Protection
A sample of radioactive material is reported to contain 2000 picocuries of
activity. Express this value as disintegrations per minute.
A) 370 dpm
B) 900 dpm
C) 3770 dpm
D) 4440 dpm
E) 5320 dpm - Correct Answers ✅The correct answer is: D
dps = (2000 pCi)(1 x 10-12Ci/pi )(3.7x1010 dps/Ci) dps = 74
dpm = (74 dps) (60 sec/min)
dpm = 4440
Remember to convert to disintegrations per minute not DISINTEGRATIONS
PER SECOND.
Question Number: 1
Fundamentals of Radiation Protection
A low energy alpha detector is usually effective if the detector is distant from
the source.
,NRRPT Prep Complete Exam Questions
and Answers (Solved Papers)
A) 1/4 inch
B) 1/2 inch
C) 1 inch
D) 1 1/2 inches
E) 2 inches - Correct Answers ✅The correct answer is: A
Low energy alpha particles can only travel less than 1/2 inch in air. Therefore,
one must be closer than this to detect them.
Question Number: 2
Fundamentals of Radiation Protection
A sample of I-131 (half life = 8 days) is kept for 80 days, at which time the
activity is 1 µCi . What was the original activity?
A) 2.0 mCi
B) 1.0 mCi
C) 1.5 mCi
D) 3.5 mCi
E) 4.0 mCi - Correct Answers ✅The correct answer is: B
After 10 half lives, the remaining activity is approximately 1000th of the
original amount. Therefore, if there was 1
µCi left after 10 half lives, then there must have been 1000 times more to
start with. Hence, 1 µCi * 1000 = 1 mCi.
Question Number: 3
, NRRPT Prep Complete Exam Questions
and Answers (Solved Papers)
Fundamentals of Radiation Protection
A sample of radioactive material is reported to contain 2000 picocuries of
activity. Express this value as
disintegrations per minute.
A) 370 dpm
B) 900 dpm
C) 3770 dpm
D) 4440 dpm
E) 5320 dpm - Correct Answers ✅The correct answer is: D
dps = (2000 pCi)(1 x 10-12Ci/pi )(3.7x1010 dps/Ci) dps = 74
dpm = (74 dps) (60 sec/min)
dpm = 4440
Remember to convert to disintegrations per minute not DISINTEGRATIONS
PER SECOND.
Question Number: 4
Fundamentals of Radiation Protection
A sample of wood from an ancient forest showed 93.75% of the Carbon-14
decayed. How many half lives did the carbon go through?
A) 1
B) 2
