Average Speed and Velocity
total displacement total distance
Average velocity= Average speed=
timeinterval totaltime
∆d d total
v av = sav =
∆t t total
d 2−d 1 d 1 +d 2 +…+d n
v av = sav =
t 2−t 1 t 1+ t 2 +…+t n
Sample problems:
1. A track and field runner warming up for a game runs along a track. He runs 50 meters North
and then runs 30 meters back toward the starting point before stopping to talk to the coach. If
he runs 20 seconds, determine the following:
a. Runner’s average velocity
Given:
d 2 = 20m North d1 = 0 t 2 = 20 seconds t1 = 0
Computation:
20−0 = 20 m
v av = =1 North
20−0 20 s
Answer:
The runner’s average velocity is 1.0 m/s going in the positive direction or expressed as 1.0 m/s
North.
b. Runner’s average speed
Given:
d 2 = + 50m d 1 = -30m t 2 = 20 seconds t1 = 0
Computation:
50+30 80
v av = = =4 m/s
20+0 20
Answer:
The runner’s average is 4 m/s.
total displacement total distance
Average velocity= Average speed=
timeinterval totaltime
∆d d total
v av = sav =
∆t t total
d 2−d 1 d 1 +d 2 +…+d n
v av = sav =
t 2−t 1 t 1+ t 2 +…+t n
Sample problems:
1. A track and field runner warming up for a game runs along a track. He runs 50 meters North
and then runs 30 meters back toward the starting point before stopping to talk to the coach. If
he runs 20 seconds, determine the following:
a. Runner’s average velocity
Given:
d 2 = 20m North d1 = 0 t 2 = 20 seconds t1 = 0
Computation:
20−0 = 20 m
v av = =1 North
20−0 20 s
Answer:
The runner’s average velocity is 1.0 m/s going in the positive direction or expressed as 1.0 m/s
North.
b. Runner’s average speed
Given:
d 2 = + 50m d 1 = -30m t 2 = 20 seconds t1 = 0
Computation:
50+30 80
v av = = =4 m/s
20+0 20
Answer:
The runner’s average is 4 m/s.