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MATH 255 - Probability and Statistics Solutions to Midterm Exam II

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MATH 255 - Probability and Statistics Solutions to Midterm Exam II Problem 1. [10pt] A stick is broken into three pieces by picking two points independently and uniformly along the stick, and breaking the stick at those two points. What is the probability that the three pieces can be assembled into a triangle? Solution: Consider the case where x y without loss of generality. Then, the segments have lengths: y, x − y, and 1 − x. To form a triangle, they must satisfy the triangle inequality that (+3pt) (x − y) + y 1 − x, y + (1 − x) x − y, (x − y) + (1 − x) y. This yields that if x 1/2, y 1/2 and x − y 1/2, then the segments form a triangle conditioned on x y (+3pt). The following figure illustrates th

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Bilkent University Fall 2022


MATH 255 - Probability and Statistics

Solutions to Midterm Exam II


Problem 1. [10pt] A stick is broken into three pieces by picking two points independently and
uniformly along the stick, and breaking the stick at those two points. What is the probability
that the three pieces can be assembled into a triangle?

Solution: Consider the case where x > y without loss of generality. Then, the segments have
lengths: y, x − y, and 1 − x. To form a triangle, they must satisfy the triangle inequality that
(+3pt)

(x − y) + y > 1 − x,
y + (1 − x) > x − y,
(x − y) + (1 − x) > y.

This yields that if x > 1/2, y < 1/2 and x − y < 1/2, then the segments form a triangle
conditioned on x > y (+3pt). The following figure illustrates the event of interest and the
conditioned event.




Hence, the conditional probability is 1/4 (+4pt). 




1 09-25-2025 13:39:15 GMT -05:00
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