Solution Manual for Business Mathematics in Canada (Paperback, 2020) by F. Ernest Jerome & Tracy Worswick – Verified Answers – A+ Grades

Complete Solution Manual for
Business Mathematics In Canada 10th
edition F. Ernest Jerome, Tracy Worswick


1 Review and Applications of
Basic Mathematics
Exercise 1.1
a. 10 + 10 x 0 = 10 + 0 = 10
b. 2x2+4–8=4+4–8=0
c. (10 + 10) x 0 = 20 x 0 = 0
d. 2 x (2 + 4) – 8 = 2 x 6 – 8 = 12 – 8 = 4
e. 0 + 3 x 3 – 32 + 10 = 0 + 9 – 9 + 10 = 10
f. 12 – 2 x 5 + 22 x 0 = 12 – 10 + 4 x 0 = 12 – 10 + 0 = 2
g. 0 + 3 x 3 – (32 + 10) = 0 + 9 – 19 = -10
h. (12 – 2) x (5 + 22) x 0 = 10 x 9 x 0 = 0
22 - 4 4-4 0
i. 2
= 2
= =0
(4- 2) 2 4

(2 - 4)2 (-2)2 4
= = =4
j. 5- 22 5- 4 1

1. 20  4  2  8  20  8  8  4
2. 18  3  6  2  6  12  18
3. 20  4  2  8  16  2  8  32  8  24
4. 18  3  6  2  18  9  2  2  2  4
5. 20  4  2  8  20  8  8  20
6. 18  3  6  2  6  6  2  24
7. 54  36  4  2 2  54  9  4  49

8. 5  32  3 2  9  3  8 2  9  9  3  64  1  3  66

, 9. 54  36  4  2 2  18  6 2  18  36  0.5

10. 5  3 2  3  2
 9  3   5  9  3 2  12  5  36  12  5  3  8

82  42 64  16 48
11.   6
4  2 3
2 3 8

12.
8  42 
42

16
 4
4  23 48 4

13. 36  4 2  517  20 2  3  10 2  5 3 2  3  100  5  9  300  45  255

14. 4  3  22  4  3  2 2   12  22  4  3  4  10 2  4  12  100   8   12.5
15. 20  8  5  7   3  9  20  40  21  9  81  9  9

   
2
16. 5 19  5 2  16   5 19  25  16 2  519  812  5  100 2  50 ,000
2 2
 
17. $1001 0.06  365
45
  $1001 0.00739726  $100.74
$200 $200 $200
18.    $194.17
1  0.09  12 1  0.03 1.03
4


$500 $500 $500
19.    $453.51
1  0.05 2
1.05 2
1.1025
 
20. $1000 1  0.02  $1000 1.023  $1000  1.061208   $1061.21
3


 1  0.042  1  1.04 2  1
  $100
0.0816 
21. $100   $100    $204.00
 0.04   0.04   0.04 
 1   1 
1  2   1 
22. $300 
1  0.03    $300 1.0609   $300 1  0.942596   $574.04
 0.03   0.03   0.03 
   
   

Concept Questions (Section 1.2)
1. You must retain at least one more figure than you require in the answer. To achieve four-
figure accuracy in the answer, you must retain a minimum of five figures in the values
used in the calculations. B)
2. We want six-figure accuracy in the answer. Therefore, values used in the calculations
must be accurate to at least seven figures. B)
3. We want seven-figure accuracy in the answer. Therefore, values used in the calculations
must retain at least eight figures. C)
4. To be accurate to the nearest 0.01%, an interest rate greater than 10% must have four-
figure accuracy. Therefore, five figures must be retained in numbers used in the
calculations. C)

,Exercise 1.2
a. = 0.10 = 10%
b. = 0.40 = 40%
c. = 0.25 = 25%
d. = 0.75 = 75%
e. = 1.50 = 150%
f. = 2.3333 = 233.33%
g. = 2.00 = 200%
h. 5 = 5.6667 = 566.67%
i. 0.25 x 80 = 20
j. 0.20 x 120 = 24
k. Money in Savings = 0.20 x $1000 = $200
Money in TFSA = 0.50 x $200 = $100
1. 7
8
 0.87500  87.500%
2. 65
104
 0.62500  62.500%
3. 47
20
 2.3500  235.00%
4. - 169 = -0.56250 = -56.250%
5.

7
6. 1 25  1.2800  128.00%
7. 25
1000
 0.025000  2.5000%

8. 1000
25
 40.000  4000.0%

9. 2
2 100  2.0200  202.00%
10.  1 32
11
 1.3438  134 .38%

11. 37.5
50
 0.75000  75.000%
12. 22.5
12
  1.8750   187.50%
13. 5
6
 0.83  83. 3%
14.  8
3
 2. 6  266. 6%

15. 7 79  7.7  777.7%
1  1. 09  109. 09%
16. 1 11

, 17. 10
9
 11
.  1111
.%

18. ̅ ̅

19.  270
7
  0.0259   2.592%

20. 37
27
 1. 370  137. 037%
21. 11.3845  11.38
22. 9.6455  9.646
23. 0.5545454  0.5545
24. 1000.49  1000
25. 1.0023456  1.002
26. 0.030405  0.03041
27. 40.09515  40.10
28. 0.0090909  0.009091
29. 1
6
 0.16667  16.667%
30. 7
6
 1.1667  116.67%

31. 1
60
 0.016667  16667
. %
32. 2 59  2.5556  255.56%
33. 250
365
 0.68493  68.493%

34. 15
365
 0.041096  4.1096 %

35. 0 .11  0.0091667  0.91667%
12

36. 0.095
12
 0.0079167  0.79167 %

37. 
$92 1  0.095  112
365

 $92  1.02915  $94.68

38. 
$100 1  0.11  12 
5  $100  1.04583  $104.58


39. 
$454.76 1  0.105  12 
11  $454.76  0.903750  $410.99


40. ( )
= 0.550707 = 0.55


41. ( ) ( ) = $1447 (1.295029) (1.1449) = $2145.44
$790.84 $790.84
42. = = $711.98
1+ 0.13´ 365 1.110767
311