Electric Machinery – Fitzgerald & Kingsley [7th Edition] | Solution Manual | Full Solutions Pack | 2025/2026 Updated | Instant Download

SOLUTION MANUAL

Fitzgerald & Kingsley’s Electric Machinery [7th Edition]

Máquinas elétricas de Fitzgeral e Kingsley [7th edição]

, 1


PROBLEM SOLUTIONS: Chapter 1


Problem 1-1


Part (a):
lc lc
Rc = = = 0 A/Wb
µAc µr µ0 Ac


g
Rg = = 5.457 × 106 A/Wb
µ0 Ac

Part (b):

NI
Φ= = 2.437 × 10−5 Wb
Rc + Rg

Part (c):


λ = NΦ = 2.315 × 10−3 Wb


Part (d):

λ
L= = 1.654 mH
I

Problem 1-2


Part (a):
lc lc
Rc = = = 2.419 × 105 A/Wb
µAc µr µ0 Ac


g
Rg = = 5.457 × 106 A/Wb
µ0 Ac


c 2014 by McGraw-Hill Education. This is proprietary material solely for authorized
instructor use. Not authorized for sale or distribution in any manner. This document may
not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in
whole or part.

, 2


Part (b):

NI
Φ= = 2.334 × 10−5 Wb
Rc + Rg

Part (c):


λ = NΦ = 2.217 × 10−3 Wb

Part (d):

λ
L= = 1.584 mH
I

Problem 1-3


Part (a):

s
Lg
N = = 287 turns
µ0 Ac

Part (b):

Bcore
I= = 7.68 A
µ0 N/g

Problem 1-4


Part (a):

s s
L(g + lc µ0 /µ) L(g + lcµ0 /(µr µ0 ))
N= = = 129 turns
µ0 Ac µ0 Ac

Part (b):

Bcore
I= = 20.78 A
µ0 N/(g + lc µ0 /µ)

c 2014 by McGraw-Hill Education. This is proprietary material solely for authorized
instructor use. Not authorized for sale or distribution in any manner. This document may
not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in
whole or part.

, 3


Problem 1-5

Part (a):




Part (b):

Bg = Bm = 2.1 T

For Bm = 2.1 T, µr = 37.88 and thus

Bm lc
  
I= g+ = 158 A
µ0 N µr

Part (c):




Problem 1-6

Part (a):

µ0 NI
Bg =
2g

c 2014 by McGraw-Hill Education. This is proprietary material solely for authorized
instructor use. Not authorized for sale or distribution in any manner. This document may
not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in
whole or part.