1. The zeroth law of thermodynamics establishes the concept of:
A) Internal energy
B) Temperature
C) Entropy
D) Enthalpy
Answer: B
Explanation: It states that if A is in thermal equilibrium with B and B with C, then A is
with C, defining temperature as a measurable property.
2. A closed system is one in which:
A) No mass or energy crosses the boundary
B) Energy crosses but not mass
C) Mass crosses but not energy
D) Both mass and energy cross
Answer: B
Explanation: Closed systems exchange energy (heat/work) but not mass; isolated systems
exchange neither.
3. An isolated system:
A) Exchanges heat only
B) Exchanges work only
C) Exchanges both heat and work
D) Exchanges neither heat nor work nor mass
Answer: D
Explanation: Isolated systems are cut off from surroundings for both mass and energy.
4. Specific heat at constant pressure is defined as:
A) cp = (∂u/∂T)p
B) cp = (∂h/∂T)p
C) cp = (∂u/∂p)T
D) cp = (∂h/∂p)T
Answer: B
Explanation: By definition, cp is the rate of change of enthalpy with temperature at
constant pressure.
5. For an ideal gas, the difference cp − cv equals:
A) R
B) 0
C) γ
,2
D) 1/R
Answer: A
Explanation: Mayer’s relation: cp − cv = R for ideal gases.
6. Enthalpy h is defined as:
A) u + pv
B) u − pv
C) pv − u
D) Tds
Answer: A
Explanation: h = u + pv, a convenient property for constant-pressure processes.
7. The first law of thermodynamics for a closed system undergoing a process is:
A) δQ = du + δW
B) δQ = du − δW
C) δW = du + δQ
D) dU = δW − δQ
Answer: A
Explanation: Energy conservation: δQ − δW = du ⇒ δQ = du + δW.
8. Work done during a quasi-static expansion of a gas is:
A) ∫ v dp
B) ∫ p dv
C) ∫ T ds
D) ∫ u dv
Answer: B
Explanation: Boundary work for a quasi-equilibrium process is the area under the p–v
curve: ∫ p dv.
9. For an ideal gas, internal energy depends on:
A) Pressure only
B) Volume only
C) Temperature only
D) Both pressure and volume
Answer: C
Explanation: For ideal gases, u = u(T) and h = h(T).
10. The Kelvin–Planck statement of the second law prohibits:
A) Heat flow from hot to cold
B) Complete conversion of heat from a single reservoir into work
C) Work to heat conversion
,3
D) Heat engines
Answer: B
Explanation: No heat engine can convert all heat from one reservoir into work in a cyclic
process.
11. The Clausius statement of the second law prohibits:
A) Heat engines
B) Refrigerators
C) Spontaneous heat flow from cold to hot
D) Spontaneous heat flow from hot to cold
Answer: C
Explanation: Heat cannot spontaneously flow from a colder to a hotter body.
12. Entropy is defined for a reversible process by:
A) ds = δQ/T
B) ds = δW/T
C) ds = du/T
D) ds = dh/T
Answer: A
Explanation: For reversible heat transfer, δQrev = T ds.
13. For any adiabatic reversible process in an isolated system, entropy:
A) Increases
B) Decreases
C) Remains constant
D) Is undefined
Answer: C
Explanation: Reversible adiabatic process is isentropic; in isolated systems entropy is
constant if reversible.
14. The entropy of the universe for any real process:
A) Decreases
B) Remains constant
C) Increases
D) Is conserved
Answer: C
Explanation: Second law: total entropy increases for irreversible processes.
15. The Carnot cycle efficiency depends on:
A) Working fluid
B) Pressures
, 4
C) Reservoir temperatures
D) Compression ratio
Answer: C
Explanation: ηCarnot = 1 − TL/TH, independent of working substance.
16. The thermal efficiency of a heat engine is:
A) Wout/Qin
B) Qin/Wout
C) Wout/Win
D) Qout/Qin
Answer: A
Explanation: Efficiency is the fraction of input heat converted to net work.
17. A process at constant temperature is:
A) Isobaric
B) Isochoric
C) Isothermal
D) Isentropic
Answer: C
Explanation: Isothermal means constant T.
18. A process with no heat transfer is:
A) Isothermal
B) Adiabatic
C) Isentropic
D) Isobaric
Answer: B
Explanation: Adiabatic means δQ = 0.
19. For an ideal gas undergoing a reversible adiabatic process, p v^γ is:
A) Constant
B) Proportional to T
C) Zero
D) Increasing
Answer: A
Explanation: Isentropic relation: p v^γ = constant.
20. Polytropic process definition:
A) p v = constant
B) p v^n = constant
C) T v = constant