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ASTRO 7N Exam 2||COMPLETE EXAM WITH QUESTIONS AND VERIFIED ANSWERS||LATEST EXAM!!||

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ASTRO 7N Exam 2||COMPLETE EXAM WITH QUESTIONS AND VERIFIED ANSWERS||LATEST EXAM!!||

Institution
ASTRO 7N
Course
ASTRO 7N

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ASTRO 7N Exam 2||COMPLETE EXAM WITH
QUESTIONS AND VERIFIED ANSWERS||LATEST
EXAM!!||
How much energy is required to cause collisions during
each step of "p-p chain" - ANSWER-a lot of energy


What is generated and released at each step of the "p-p
chain" - ANSWER-energy!!


What is the equation that energy output form the p-p chain
comes from? - ANSWER-E=mc^2


How does the mass of a helium-4 nucleus compare to the
mass of 4 protons - ANSWER-it is much less that the 4
protons


What happens to some of the mass of the helium-4
nucleus? - ANSWER-converted to energy in the form of
gamma-ray photons


The core of the Sun is - ANSWER-at the center; high
density and temperature; where nuclear reactions occur
and gamma rays are produced

,2|Page


Radiative zone of the sun - ANSWER-photons are
repeatedly re-absorbed and re-emitted; the energy of an
individual photon can take on average 170,000 years to
pass through


Convective zone of sun - ANSWER-hot gas rises and cold
gas sinks; light traverses in 1 week


Photosphere of sun - ANSWER-temperature 5,780 K; this
is the "surface" of the sun that we see; photons have been
converted to visible wavelengths; can see "granules" due
to convection bringing material up and down in cells


Chromosphere of sun - ANSWER-red or orange color;
temperature about 4,500 K; we see through this, down to
the photosphere


Flare (sun) - ANSWER-eruption coming out of Sun due to
magnetic activity


Prominence - (of the Sun) - ANSWER-hoop shaped
eruption out of Sun due to magnetic activity

, 3|Page


Corona (sun) - ANSWER-low density; temperature 1
million K; visible during solar eclipse


Solar wind -(of the Sun) - ANSWER-charged particles
coming from Sun's surface, escaping to deep space; the
solar wind permeates the whole solar system


Luminosity ("L") - ANSWER-is the absolute power output,
at the source (e.g. A star's surface)


Brightness ("B") - ANSWER-is apparent output, as
observed as some distance (d) away


What does the inverse square law determine? - ANSWER-
inverse square law determines how bright a star appears,
based upon its luminosity (intrinsic brightness) and its
distance


Inverse-square law - ANSWER-B = L/4𝝅d2 or B ∝ L/d2


If two stars have the same luminosity and one is ten times
father away than the other, it will appear times as bright,
(that is, times fainter) - ANSWER-1/10^2 bright; 100 times
fainter

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