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BIOS 1700 EXAM 1 NEWEST 2025/2026 COMPLETE 100 QUESTIONS AND CORRECT DETAILED ANSWERS (VERIFIED ANSWERS) |ALREADY GRADED A+||BRAND NEW VERSION!!

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BIOS 1700 EXAM 1 NEWEST 2025/2026 COMPLETE 100 QUESTIONS AND CORRECT DETAILED ANSWERS (VERIFIED ANSWERS) |ALREADY GRADED A+||BRAND NEW VERSION!! You cross two purple monkeys which are heterozygous (Bb). An enzyme on (B) produces blue pigment while (b) produces red pigment. If blended inheritance were true what are they expected phenotype/genotype ratios? - Correct Answer Phenotypes: 1 Blue, 2 Purple, 1 red... Genotypes: 1-BB, 2-Bb, 1-bb Part I:In pea plants yellow is dominant. Wrinkled seed shape is recessive. Suppose you crossed a true breeding yellow, wrinkled plant with a true breeding green round seed shape. What would phenotype/genotype ratios are to be expected? Part II: Suppose you performed a F1 self fertilization afterwards, what would you expect to see in terms of genotype/phenotype ratios? Use a punnett square to solve to limit mistakes. - Correct Answer-Part I: Phenotype: all Yellow, round seeds. Genotype: all AaBb.... Part II: Phenotypes: 9 Round Yellow Seeds... 3 Wrinkled Yellow... 3 Round Green... 1 Wrinkled Green.... Hint: When laying out a punnett square simply take each parental genotype and FOIL (First Outter Inner Last). Ex. Parental Genotype AaBb = gametes AB, Ab, aB, ab Describe Independent Assortment and its relationship with meiosis - Correct Answer-The separation of alleles of TWO genes. Same idea as Equal Segregation, only times two. Remember the "FOIL" method and their relationship with gametes. Ex. Parent genotype: AaBB... Gametes: AB, AB, aB, aB Describe genetic epistasis. - Correct Answer-When the product of one gene affects the function of another. Example: Chicken feather color. Even if the pigment necessary for brown feather color is present it can be inhibited by the presence of another gene. Therefore the only way for a chicken to have brown feathers is for 2 | Page Bios 1700 exam 1 NEWEST the chicken to have an active brown pigment gene as well as an inactive inhibitor gene. Keeping the idea of genetic epistasis in mind determine genotype and phenotype ratios for the following cross of chickens.. CcIi x ccii. Remembering that (I) is an active inhibitor and (C) is a functional enzyme. - Correct Answer-Phenotype: 4 Brown 12-White, reduced to 1-Brown 3-White. Genotype: 4-CcIi.. 4-Ccii.. 4-ccIc... 4-ccii... Reduces to 1:1:1:1 ratio... Hint: Remember to FOIL breeding genotypes to represent Mendel's Law of Independent Assortment. A genotype to phenotype "translation key" could limit silly mistakes when deterring phenotype. Describe Variable Expressivity - Correct Answer-100% of individuals with a certain genotype display the trait but to VARYING intensity. The VARIATION is the result of either the effects of other genes (epistasis) or environmental factors, or both. Recall the emphysema mutation and the effects on lung function. Recall the effects of both a mutation and cigarette smoking leading to more severe lung deficiency. Describe expressivity - Correct Answer-The level of trait expression of a particular genotype. Describe Penetrance - Correct Answer-Number of individuals that display the expected results of a particular genotype. Describe Incomplete Penetrance - Correct Answer-When less than 100% of a certain genotype display the expected trait. Example: BRCA1. A mutated form of the gene (BRCA1+/BRCA1-) drastically increases the chances that the individual 3 | Page Bios 1700 exam 1 NEWEST will develop breast or ovarian cancer. HOWEVER it does not mean these people are certain to develop cancer.

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Bios 1700 exam 1 NEWEST


BIOS 1700 EXAM 1 NEWEST 2025/2026 COMPLETE 100 QUESTIONS
AND CORRECT DETAILED ANSWERS (VERIFIED ANSWERS) |ALREADY
GRADED A+||BRAND NEW VERSION!!
You cross two purple monkeys which are heterozygous (Bb). An enzyme on (B)
produces blue pigment while (b) produces red pigment. If blended inheritance
were true what are they expected phenotype/genotype ratios? - Correct Answer-
Phenotypes: 1 Blue, 2 Purple, 1 red... Genotypes: 1-BB, 2-Bb, 1-bb


Part I:In pea plants yellow is dominant. Wrinkled seed shape is recessive. Suppose
you crossed a true breeding yellow, wrinkled plant with a true breeding green
round seed shape. What would phenotype/genotype ratios are to be expected?
Part II: Suppose you performed a F1 self fertilization afterwards, what would you
expect to see in terms of genotype/phenotype ratios? Use a punnett square to
solve to limit mistakes. - Correct Answer-Part I: Phenotype: all Yellow, round seeds.
Genotype: all AaBb.... Part II: Phenotypes: 9 Round Yellow Seeds... 3 Wrinkled
Yellow... 3 Round Green... 1 Wrinkled Green.... Hint: When laying out a punnett
square simply take each parental genotype and FOIL (First Outter Inner Last). Ex.
Parental Genotype AaBb = gametes AB, Ab, aB, ab


Describe Independent Assortment and its relationship with meiosis - Correct
Answer-The separation of alleles of TWO genes. Same idea as Equal Segregation,
only times two. Remember the "FOIL" method and their relationship with
gametes. Ex. Parent genotype: AaBB... Gametes: AB, AB, aB, aB


Describe genetic epistasis. - Correct Answer-When the product of one gene affects
the function of another. Example: Chicken feather color. Even if the pigment
necessary for brown feather color is present it can be inhibited by the presence of
another gene. Therefore the only way for a chicken to have brown feathers is for

1|Page

, Bios 1700 exam 1 NEWEST

the chicken to have an active brown pigment gene as well as an inactive inhibitor
gene.


Keeping the idea of genetic epistasis in mind determine genotype and phenotype
ratios for the following cross of chickens.. CcIi x ccii. Remembering that (I) is an
active inhibitor and (C) is a functional enzyme. - Correct Answer-Phenotype: 4-
Brown 12-White, reduced to 1-Brown 3-White.
Genotype: 4-CcIi.. 4-Ccii.. 4-ccIc... 4-ccii... Reduces to 1:1:1:1 ratio... Hint:
Remember to FOIL breeding genotypes to represent Mendel's Law of Independent
Assortment. A genotype to phenotype "translation key" could limit silly mistakes
when deterring phenotype.


Describe Variable Expressivity - Correct Answer-100% of individuals with a certain
genotype display the trait but to VARYING intensity. The VARIATION is the result of
either the effects of other genes (epistasis) or environmental factors, or both.
Recall the emphysema mutation and the effects on lung function. Recall the
effects of both a mutation and cigarette smoking leading to more severe lung
deficiency.


Describe expressivity - Correct Answer-The level of trait expression of a particular
genotype.


Describe Penetrance - Correct Answer-Number of individuals that display the
expected results of a particular genotype.


Describe Incomplete Penetrance - Correct Answer-When less than 100% of a
certain genotype display the expected trait. Example: BRCA1. A mutated form of
the gene (BRCA1+/BRCA1-) drastically increases the chances that the individual
2|Page

, Bios 1700 exam 1 NEWEST

will develop breast or ovarian cancer. HOWEVER it does not mean these people
are certain to develop cancer.


A mutation of the OCA2 gene is associated with ________. Which affects the
production of _______ which is the precursor of pigment. This mutation often
skips generations, meaning the trait is ______. - Correct Answer-Albinism...
Melanin... Recessive.... Other thoughts on Albinism: Parents are often
heterozygous (unaffected).


________ is a disorder which results in short fingers due to a lack of growth of the
middle finger bone (middle phalange). This trait is inherited in a _____ fashion. -
Correct Answer-Brachydactyly.. Dominant fashion


What is a dominant negative trait? - Correct Answer-A trait which dominant that
inhibits the wild type function of a gene


What is the role of the SRY gene? - Correct Answer-SRY- Sex-determining Region of
the Y chromosome... Crucial for male development.


We describe the X chromosome of males as ____ meaning it has only one copy of
most genes - Correct Answer-Hemizygous... This makes sense as males are XY, in
comparison to females which are XX. It is for this reason that men are more prone
to X linked mutations compared to women which have a "backup" copy of the X
chromosome. It is for this reason that women can have one mutated X
chromosome but not display the mutation.




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