NATE EXAM: CORE ESSENTIALS / STUDY GUIDE / LATEST VERSION /QUESTIONS
AND CORRECT ANSWERS / A GRADE SCORE SOLUTION.
Question 1
The ability to utilize all types of communication skills is _________ to the HVACR technician.
A) not as important as "hands-on" technical skills
B) somewhat important
C) unimportant
D) very important
Correct Answer: D) very important
Rationale: Effective communication is crucial for diagnosing problems, explaining work to
customers, and documenting service, making it a very important skill for technicians.
Question 2
It is important to be _________ in filling out service orders so that office staff, other technicians,
and customers will know what work you completed on the job.
A) clear
B) complete
C) concise
D) all of the above
Correct Answer: D) all of the above
Rationale: Service orders must be clear, complete, and concise to ensure that all parties
involved have an accurate and understandable record of the work performed.
Question 3
When explaining to a customer that you have adjusted the system charge, which of the
following terms is the most professional and appropriate to use?
A) Freon
B) Gas
C) Juice
D) Refrigerant
Correct Answer: D) Refrigerant
,Rationale: "Refrigerant" is the correct technical term. Terms like "Freon" (a brand name),
"gas," or "juice" are slang and sound unprofessional.
Question 4
Listening carefully to what a customer is telling you _________.
A) can help you diagnose the problem
B) is a waste of time
C) is not necessary
D) often will only confuse you
Correct Answer: A) can help you diagnose the problem
Rationale: The customer's description of the problem, including when it started and what it
sounds or feels like, can provide valuable clues to help diagnose the issue.
Question 5
When you arrive at a service call and meet the customer, you should _________.
A) ask questions first, then listen to what the customer has to say
B) listen to the customer first, then ask questions
C) avoid discussion with the customer
D) remind the customer that you are the professional and get on with your work
Correct Answer: B) listen to the customer first, then ask questions
Rationale: Allowing the customer to describe the problem in their own words first shows
respect and can provide a lot of information. The technician can then ask clarifying questions.
Question 6
What is the volume of a room that measures 10 ft by 20 ft with an 8-ft ceiling?
A) 800 ft³
B) 1,600 ft³
C) 2,400 ft³
D) 3,200 ft³
Correct Answer: B) 1,600 ft³
,Rationale: Volume is calculated by multiplying length by width by height: 10 ft * 20 ft * 8 ft =
1,600 ft³.
Question 7
What is the CFM requirement for an 1,800-ft² house with 8-ft ceilings, if five air changes per
hour are needed?
A) 400 CFM
B) 1,200 CFM
C) 1,600 CFM
D) 2,400 CFM
Correct Answer: B) 1,200 CFM
Rationale: 1. Calculate the volume: 1,800 ft² * 8 ft = 14,400 ft³. 2. Calculate the total hourly
volume needed: 14,400 ft³ * 5 air changes/hr = 72,000 ft³/hr. 3. Convert to CFM: 72,000 ft³/hr /
60 min/hr = 1,200 CFM.
Question 8
What is the CFM requirement for a 2,400-ft² house with 8-ft ceilings, if five air changes per hour
are needed?
A) 400 CFM
B) 1,200 CFM
C) 1,600 CFM
D) 2,400 CFM
Correct Answer: C) 1,600 CFM
Rationale: 1. Calculate the volume: 2,400 ft² * 8 ft = 19,200 ft³. 2. Calculate the total hourly
volume needed: 19,200 ft³ * 5 air changes/hr = 96,000 ft³/hr. 3. Convert to CFM: 96,000 ft³/hr /
60 min/hr = 1,600 CFM.
Question 9
What is the cross-sectional area of a 10-in round metal duct?
A) 79 in²
B) 200 in²
, C) 314 in²
D) 418 in²
Correct Answer: A) 79 in²
Rationale: The radius is half the diameter, so the radius is 5 inches. Area = π * radius² =
3.14159 * (5 in)² = 3.14159 * 25 in² ≈ 78.5 in², which rounds to 79 in².
Question 10
How fast does air with a velocity pressure of 0.20 in. w.g. move through a round duct?
A) 400 ft/min
B) 1,200 ft/min
C) 1,600 ft/min
D) 1,800 ft/min
Correct Answer: D) 1,800 ft/min
Rationale: Velocity = 4005 * √Velocity Pressure = 4005 * √0.20 ≈ 4005 * 0.447 ≈ 1790 ft/min,
which rounds to 1,800 ft/min.
Question 11
How fast does air with a velocity pressure of 0.20 in w.g. move through a square duct?
A) 400 ft/min
B) 1,200 ft/min
C) 1,600 ft/min
D) 1,800 ft/min
Correct Answer: D) 1,800 ft/min
Rationale: The formula for calculating air velocity from velocity pressure is the same
regardless of the duct shape. Velocity = 4005 * √Velocity Pressure ≈ 1,800 ft/min.
Question 12
Customers depend on you to be _________.
A) honest
B) loyal
C) patient
AND CORRECT ANSWERS / A GRADE SCORE SOLUTION.
Question 1
The ability to utilize all types of communication skills is _________ to the HVACR technician.
A) not as important as "hands-on" technical skills
B) somewhat important
C) unimportant
D) very important
Correct Answer: D) very important
Rationale: Effective communication is crucial for diagnosing problems, explaining work to
customers, and documenting service, making it a very important skill for technicians.
Question 2
It is important to be _________ in filling out service orders so that office staff, other technicians,
and customers will know what work you completed on the job.
A) clear
B) complete
C) concise
D) all of the above
Correct Answer: D) all of the above
Rationale: Service orders must be clear, complete, and concise to ensure that all parties
involved have an accurate and understandable record of the work performed.
Question 3
When explaining to a customer that you have adjusted the system charge, which of the
following terms is the most professional and appropriate to use?
A) Freon
B) Gas
C) Juice
D) Refrigerant
Correct Answer: D) Refrigerant
,Rationale: "Refrigerant" is the correct technical term. Terms like "Freon" (a brand name),
"gas," or "juice" are slang and sound unprofessional.
Question 4
Listening carefully to what a customer is telling you _________.
A) can help you diagnose the problem
B) is a waste of time
C) is not necessary
D) often will only confuse you
Correct Answer: A) can help you diagnose the problem
Rationale: The customer's description of the problem, including when it started and what it
sounds or feels like, can provide valuable clues to help diagnose the issue.
Question 5
When you arrive at a service call and meet the customer, you should _________.
A) ask questions first, then listen to what the customer has to say
B) listen to the customer first, then ask questions
C) avoid discussion with the customer
D) remind the customer that you are the professional and get on with your work
Correct Answer: B) listen to the customer first, then ask questions
Rationale: Allowing the customer to describe the problem in their own words first shows
respect and can provide a lot of information. The technician can then ask clarifying questions.
Question 6
What is the volume of a room that measures 10 ft by 20 ft with an 8-ft ceiling?
A) 800 ft³
B) 1,600 ft³
C) 2,400 ft³
D) 3,200 ft³
Correct Answer: B) 1,600 ft³
,Rationale: Volume is calculated by multiplying length by width by height: 10 ft * 20 ft * 8 ft =
1,600 ft³.
Question 7
What is the CFM requirement for an 1,800-ft² house with 8-ft ceilings, if five air changes per
hour are needed?
A) 400 CFM
B) 1,200 CFM
C) 1,600 CFM
D) 2,400 CFM
Correct Answer: B) 1,200 CFM
Rationale: 1. Calculate the volume: 1,800 ft² * 8 ft = 14,400 ft³. 2. Calculate the total hourly
volume needed: 14,400 ft³ * 5 air changes/hr = 72,000 ft³/hr. 3. Convert to CFM: 72,000 ft³/hr /
60 min/hr = 1,200 CFM.
Question 8
What is the CFM requirement for a 2,400-ft² house with 8-ft ceilings, if five air changes per hour
are needed?
A) 400 CFM
B) 1,200 CFM
C) 1,600 CFM
D) 2,400 CFM
Correct Answer: C) 1,600 CFM
Rationale: 1. Calculate the volume: 2,400 ft² * 8 ft = 19,200 ft³. 2. Calculate the total hourly
volume needed: 19,200 ft³ * 5 air changes/hr = 96,000 ft³/hr. 3. Convert to CFM: 96,000 ft³/hr /
60 min/hr = 1,600 CFM.
Question 9
What is the cross-sectional area of a 10-in round metal duct?
A) 79 in²
B) 200 in²
, C) 314 in²
D) 418 in²
Correct Answer: A) 79 in²
Rationale: The radius is half the diameter, so the radius is 5 inches. Area = π * radius² =
3.14159 * (5 in)² = 3.14159 * 25 in² ≈ 78.5 in², which rounds to 79 in².
Question 10
How fast does air with a velocity pressure of 0.20 in. w.g. move through a round duct?
A) 400 ft/min
B) 1,200 ft/min
C) 1,600 ft/min
D) 1,800 ft/min
Correct Answer: D) 1,800 ft/min
Rationale: Velocity = 4005 * √Velocity Pressure = 4005 * √0.20 ≈ 4005 * 0.447 ≈ 1790 ft/min,
which rounds to 1,800 ft/min.
Question 11
How fast does air with a velocity pressure of 0.20 in w.g. move through a square duct?
A) 400 ft/min
B) 1,200 ft/min
C) 1,600 ft/min
D) 1,800 ft/min
Correct Answer: D) 1,800 ft/min
Rationale: The formula for calculating air velocity from velocity pressure is the same
regardless of the duct shape. Velocity = 4005 * √Velocity Pressure ≈ 1,800 ft/min.
Question 12
Customers depend on you to be _________.
A) honest
B) loyal
C) patient
