6/9/25, 12:14 PM Jeremy Clark - MATH302 1005 Spring 2025 - APEI
MATH 302 WEEK 5 TEST | QUESTIONS AND ANSWERS | LATEST 2025/2026 UPDATE | 100%
CORRECT - AMERICAN PUBLIC UNIVERSITY
Week 5 Knowledge Check Homework Practice Questions - Results x
Attempt 2 of 4
Written Jun 9, 2025 1 2:32 PM -Jun 9, 2025 1 :14 PM
Attempt Score 1
Overall Grade (Highest Attempt)
Question 1 point
There is no prior information about the proportion of Americans who support gun control in 201
8. If we want to estimate 95% confidence interval for the true proportion of Americans who
support gun control in 201 8 with a 0.36 margin of error, how many randomly selected Americans
must be surveyed? Answer: (Round up your answer to nearest whole number)
v Hide question 1 feedback
Z-Critical Value = I .96
n
Question 2 1 / I point
A researcher would like to estimate the proportion of all children that have been diagnosed with
Autism Spectrum Disorder (ASD) in their county. They are using 95% confidence level and the CDC
national estimate that 1 in 68 0.01 47 children are diagnosed with ASD. What sample size should
the researcher use to get a margin of error to be within 2%? Round up to the nearest integer.
Answer
V Hide question 2 feedback
Z-Critical Value - — NORM.S.lNV(.975) = 1 .96
, 6/9/25, 12:14 PM Jeremy Clark - MATH302 1005 Spring 2025 - APEI
Question 3 point The population standard deviation for the height of college baseball players
is 3.2 inches. If we want to estimate 90% confidence interval for the population mean height of these
players with a 0.7 margin of error, how many randomly selected players must be surveyed? (Round
up your answer to nearest whole number) Answer: -51---
v Hide question 3 feedback
Z-Critical Value = NORM.S.lNV(.95) = I .645
Question 4 point
There is no prior information about the proportion of Americans who support free trade in 201
8. If we want to estimate a 97.5% confidence interval for the true proportion of Americans who
support free trade in 201 8 with a 0.1 6 margin of error, how many randomly selected Americans
must be surveyed? Answer: (Round up your answer to nearest whole number)
v Hide question 4 feedback
Z-Critical Value = NORM.S.lNV(.9875) = 2.241 403
Question 5 point Suppose a marketing company wants to determine the current proportion of
customers who click on ads on their smartphones. It was estimated that the current proportion of
customers who click on ads on their smartphones is 0.68. How many customers should the company
survey in order to be 97% confident that the margin of error is 0.29 for the confidence interval of
true proportion of customers who click on ads on their smartphones? Answer: (Round up your
answer to nearest whole number)
MATH 302 WEEK 5 TEST | QUESTIONS AND ANSWERS | LATEST 2025/2026 UPDATE | 100%
CORRECT - AMERICAN PUBLIC UNIVERSITY
Week 5 Knowledge Check Homework Practice Questions - Results x
Attempt 2 of 4
Written Jun 9, 2025 1 2:32 PM -Jun 9, 2025 1 :14 PM
Attempt Score 1
Overall Grade (Highest Attempt)
Question 1 point
There is no prior information about the proportion of Americans who support gun control in 201
8. If we want to estimate 95% confidence interval for the true proportion of Americans who
support gun control in 201 8 with a 0.36 margin of error, how many randomly selected Americans
must be surveyed? Answer: (Round up your answer to nearest whole number)
v Hide question 1 feedback
Z-Critical Value = I .96
n
Question 2 1 / I point
A researcher would like to estimate the proportion of all children that have been diagnosed with
Autism Spectrum Disorder (ASD) in their county. They are using 95% confidence level and the CDC
national estimate that 1 in 68 0.01 47 children are diagnosed with ASD. What sample size should
the researcher use to get a margin of error to be within 2%? Round up to the nearest integer.
Answer
V Hide question 2 feedback
Z-Critical Value - — NORM.S.lNV(.975) = 1 .96
, 6/9/25, 12:14 PM Jeremy Clark - MATH302 1005 Spring 2025 - APEI
Question 3 point The population standard deviation for the height of college baseball players
is 3.2 inches. If we want to estimate 90% confidence interval for the population mean height of these
players with a 0.7 margin of error, how many randomly selected players must be surveyed? (Round
up your answer to nearest whole number) Answer: -51---
v Hide question 3 feedback
Z-Critical Value = NORM.S.lNV(.95) = I .645
Question 4 point
There is no prior information about the proportion of Americans who support free trade in 201
8. If we want to estimate a 97.5% confidence interval for the true proportion of Americans who
support free trade in 201 8 with a 0.1 6 margin of error, how many randomly selected Americans
must be surveyed? Answer: (Round up your answer to nearest whole number)
v Hide question 4 feedback
Z-Critical Value = NORM.S.lNV(.9875) = 2.241 403
Question 5 point Suppose a marketing company wants to determine the current proportion of
customers who click on ads on their smartphones. It was estimated that the current proportion of
customers who click on ads on their smartphones is 0.68. How many customers should the company
survey in order to be 97% confident that the margin of error is 0.29 for the confidence interval of
true proportion of customers who click on ads on their smartphones? Answer: (Round up your
answer to nearest whole number)
