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MAT-142-X2573 Precalculus with Limits 23EW2 : MAT-142 : 1421222, 1-4 Module One Problem Set
Tracey Delton, 10/27/23 at 1:01:22 PM EDT
Question1: Score 2/2
Solve the compound inequality: 6 ≤ 2 x − 8 < 12 .
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U.
PR
Your response Correct response
[7,10) [7, 10)
Auto graded Grade: 1/1.0
O
Total grade: 1.0×1/1 = 100%
Feedback:
FD
Write two separate inequalities: 6 ≤ 2 x − 8 and 2 x − 8 < 12 . We solve them independently.
6 ≤ 2 x − 8 and 2x − 8 < 12
O
14 ≤ 2 x 2x < 20
C
7 ≤ x x < 10
Therefore, the solution set is 7 ≤ x < 10 , or in interval notation, [7, 10).
Question2: Score 1.6/8
,Solve the inequality involving absolute value.
|x − 3| + 5 ≥ 12
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U.
Your response Correct response
(-infinity,-4]U[10,infinity) (-infinity, -4] U [10, infinity)
Auto graded Grade: 25/25.0
PR
Show your work and explain, in your own words, how you arrived at your answers.
O
|x-3| + 5 >= 12
|x-3| + 5 - 5 >= 12 - 5
|x - 3| >= 7
Case 1:
FD
x - 3 >= 7
x >= 7 + 3
x >= 10
Case 2:
-( x - 3) >= 7
O
-x + 3 >= 7
-x >=4
x <=-4
C
(-infinity,-4]U[10,infinity)
Ungraded Grade: 0/100.0
Total grade: 1.0×25/125 + 0.0×100/125 = 20% + 0%
Question3: Score 2/2
, Solve the inequality involving absolute value.
∣ x−3 ∣
< 3
∣ 5 ∣
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U.
Your response Correct response
(-12,18) (-12, 18)
PR
Auto graded Grade: 1/1.0
Total grade: 1.0×1/1 = 100%
Feedback:
∣ x−3 ∣
< 3
O
∣ 5 ∣
x−3
−3 < < 3
5
FD
−15 < x − 3 < 15
−12 < x < 18
O
Express the inequality in interval notation.
C
(−12, 18)
Question4: Score 2/2
MAT-142-X2573 Precalculus with Limits 23EW2 : MAT-142 : 1421222, 1-4 Module One Problem Set
Tracey Delton, 10/27/23 at 1:01:22 PM EDT
Question1: Score 2/2
Solve the compound inequality: 6 ≤ 2 x − 8 < 12 .
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U.
PR
Your response Correct response
[7,10) [7, 10)
Auto graded Grade: 1/1.0
O
Total grade: 1.0×1/1 = 100%
Feedback:
FD
Write two separate inequalities: 6 ≤ 2 x − 8 and 2 x − 8 < 12 . We solve them independently.
6 ≤ 2 x − 8 and 2x − 8 < 12
O
14 ≤ 2 x 2x < 20
C
7 ≤ x x < 10
Therefore, the solution set is 7 ≤ x < 10 , or in interval notation, [7, 10).
Question2: Score 1.6/8
,Solve the inequality involving absolute value.
|x − 3| + 5 ≥ 12
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U.
Your response Correct response
(-infinity,-4]U[10,infinity) (-infinity, -4] U [10, infinity)
Auto graded Grade: 25/25.0
PR
Show your work and explain, in your own words, how you arrived at your answers.
O
|x-3| + 5 >= 12
|x-3| + 5 - 5 >= 12 - 5
|x - 3| >= 7
Case 1:
FD
x - 3 >= 7
x >= 7 + 3
x >= 10
Case 2:
-( x - 3) >= 7
O
-x + 3 >= 7
-x >=4
x <=-4
C
(-infinity,-4]U[10,infinity)
Ungraded Grade: 0/100.0
Total grade: 1.0×25/125 + 0.0×100/125 = 20% + 0%
Question3: Score 2/2
, Solve the inequality involving absolute value.
∣ x−3 ∣
< 3
∣ 5 ∣
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U.
Your response Correct response
(-12,18) (-12, 18)
PR
Auto graded Grade: 1/1.0
Total grade: 1.0×1/1 = 100%
Feedback:
∣ x−3 ∣
< 3
O
∣ 5 ∣
x−3
−3 < < 3
5
FD
−15 < x − 3 < 15
−12 < x < 18
O
Express the inequality in interval notation.
C
(−12, 18)
Question4: Score 2/2
