ATT TEST 7 EXAM NEWEST 2025 ACTUAL EXAM COMPLETE 100 QUESTIONS AND CORRECT DETAILED
ANSWERS (VERIFIED ANSWERS) |ALREADY GRADED A+
Pulsating DC - Answer-Current that varies in amplitude but does not reverse polarity `Not alt. Current
because polarity remains the same
Protection. - Answer-Optional section in an scr power supply. Prevents damage to power supply from
excess current flow
AC to DC - Answer-Diode reflecters
Power Supply - Answer-AC to DC
Half Wave Diode Reflector - Answer-AC to DC
(VDC=VPeak of secondary x .318)
Full Wave Diode Rectifier - Answer-AC to DC
VAVG= [VPP/2] x .636
If center tapped:
VAVG= [VPP/4] x .636
Diodes preform reflection
180° out of phase
Bridge Diode Rectifier - Answer-Only conducts if forward biased
(VAVG= VPEAK x .636)
Output: pulsating DC
, Half Wave rectifier freq - Answer-Ripple req: same as input freq
Full wave rectifier freq - Answer-Ripple freq: twice input freq
With half VPEAK output
Bridge rectifier freq - Answer-Ripple freq: twice input freq
Output: twice the voltage of a fullwave
Applied voltage is taken across the full potential of the transformer - Answer-Advantage of a Bridge vs
Fullwave
Voltage regulators purpose - Answer-Adjust voltage to maintain Eout at a constant level
Zener diode normal operation - Answer-Fwd biased: low ohms
Rev biased: high ohms
Zener diode - Answer-Series voltage regulator
Efficiency of a full wave vs half wave - Answer-Full wave is more efficient because an output is
developed for entire wave form
Purpose of a series volt regulator - Answer-Maintain constant output voltages to a load
series volt regulator - Answer-Load current increases, r1 square root = er square root
Eout increases, DC increases (OR current of load square rooted) - Answer-In a Parallel volt regulator...
ANSWERS (VERIFIED ANSWERS) |ALREADY GRADED A+
Pulsating DC - Answer-Current that varies in amplitude but does not reverse polarity `Not alt. Current
because polarity remains the same
Protection. - Answer-Optional section in an scr power supply. Prevents damage to power supply from
excess current flow
AC to DC - Answer-Diode reflecters
Power Supply - Answer-AC to DC
Half Wave Diode Reflector - Answer-AC to DC
(VDC=VPeak of secondary x .318)
Full Wave Diode Rectifier - Answer-AC to DC
VAVG= [VPP/2] x .636
If center tapped:
VAVG= [VPP/4] x .636
Diodes preform reflection
180° out of phase
Bridge Diode Rectifier - Answer-Only conducts if forward biased
(VAVG= VPEAK x .636)
Output: pulsating DC
, Half Wave rectifier freq - Answer-Ripple req: same as input freq
Full wave rectifier freq - Answer-Ripple freq: twice input freq
With half VPEAK output
Bridge rectifier freq - Answer-Ripple freq: twice input freq
Output: twice the voltage of a fullwave
Applied voltage is taken across the full potential of the transformer - Answer-Advantage of a Bridge vs
Fullwave
Voltage regulators purpose - Answer-Adjust voltage to maintain Eout at a constant level
Zener diode normal operation - Answer-Fwd biased: low ohms
Rev biased: high ohms
Zener diode - Answer-Series voltage regulator
Efficiency of a full wave vs half wave - Answer-Full wave is more efficient because an output is
developed for entire wave form
Purpose of a series volt regulator - Answer-Maintain constant output voltages to a load
series volt regulator - Answer-Load current increases, r1 square root = er square root
Eout increases, DC increases (OR current of load square rooted) - Answer-In a Parallel volt regulator...
