CALC II EXAM #9 REVIEW QUESTIONS AND ANSWERS
With limit comparison - correct answer find a compariable function then , divide by that
function, then find a limit, after limit, bigger then 0 then it acts the same.
In geometric series of( 5/6)^-n power , what shell you do? - correct answer reverse the
number
(2/7^n) is actually same geometric series as - correct answer (1/7)^n
Alternating series have (-1)^n part , how do you treat them - correct answer remove (-
1)^n all together and compare it as a normal series.
If Alter series has (-1)^n+1 what do you do? - correct answer same remove (-1)^n+1
What groes faster e^n or n!? - correct answer n!
For root test - correct answer take "n" root, then take a limit, if limit is less then ZERO
then series acts LIKE its root
RATIO TEST, what do you need to replace n with? - correct answer N+1, and then
what?
For ratio test then divide by original formula - correct answer
How to cancel n! And (n+1)! - correct answer once you cancel you get (n+1) left
What happen if root test , limit goes to one? - correct answer
Integral test n= 2, to ∞∑ 1/(n(lnn)) = - correct answer from 2 to ∞∫1/xlnn
In 1/( x ln(x)) what is u? - correct answer ln of x
Du of ln(x) - correct answer is derivetive of ln(x) which is 1/x
One you finish integral test - correct answer - take limit of the integral
1/u^2 us sane as - correct answer u^(-2)
What is integral of u^-2 - correct answer -1 times u^-1 what is -1/u
Wath out for ( (n+1)/n) ) n power is is like root test, what does it convergies into> -
correct answer e^1, or if -n then e^-1
In series arctan(n) is same as - correct answer pi/2
With limit comparison - correct answer find a compariable function then , divide by that
function, then find a limit, after limit, bigger then 0 then it acts the same.
In geometric series of( 5/6)^-n power , what shell you do? - correct answer reverse the
number
(2/7^n) is actually same geometric series as - correct answer (1/7)^n
Alternating series have (-1)^n part , how do you treat them - correct answer remove (-
1)^n all together and compare it as a normal series.
If Alter series has (-1)^n+1 what do you do? - correct answer same remove (-1)^n+1
What groes faster e^n or n!? - correct answer n!
For root test - correct answer take "n" root, then take a limit, if limit is less then ZERO
then series acts LIKE its root
RATIO TEST, what do you need to replace n with? - correct answer N+1, and then
what?
For ratio test then divide by original formula - correct answer
How to cancel n! And (n+1)! - correct answer once you cancel you get (n+1) left
What happen if root test , limit goes to one? - correct answer
Integral test n= 2, to ∞∑ 1/(n(lnn)) = - correct answer from 2 to ∞∫1/xlnn
In 1/( x ln(x)) what is u? - correct answer ln of x
Du of ln(x) - correct answer is derivetive of ln(x) which is 1/x
One you finish integral test - correct answer - take limit of the integral
1/u^2 us sane as - correct answer u^(-2)
What is integral of u^-2 - correct answer -1 times u^-1 what is -1/u
Wath out for ( (n+1)/n) ) n power is is like root test, what does it convergies into> -
correct answer e^1, or if -n then e^-1
In series arctan(n) is same as - correct answer pi/2
