CHEM103 MODULE 1 TO 6 EXAM QUESTIONS & CORRECT ANSWERS 2025 | PORTAGE LEARNING

CHEM103 MODULE 1 TO 6 EXAM
QUESTIONS & CORRECT
ANSWERS 2025 | PORTAGE
LEARNING
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Chem_103_Module_1_to_6_Exam_answers

MODULE 1 EXAM
Question 1
Click this link to access the Periodic Table. This may be helpful
throughout the exam.
1. Convert 845.3 to exponential form and explain your answer.
2. Convert 3.21 x 10-5 to ordinary form and explain your answer.


1.Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places
= 8.453 x 102
2.Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0.0000321

Question 2
Click this link to access the Periodic Table. This may be helpful throughout the exam.


Using the following information, do the conversions shown below, showing all work:
1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4
quarts
1 mile = 5280 1 ton = 2000
feet pounds 1 quart = 2
pints
kilo (= 1000) milli (= 1/1000) centi (= 1/100) deci (= 1/10)


1. 24.6 grams = ? kg

2. 6.3 ft = ? inches


1. 24.6 grams x 1 kg / 1000 g = 0.0246 kg 2. 6.3 ft x 12 in / 1 ft = 75.6 inches

please always use the correct units in your final answer

Question 3
Click this link to access the Periodic Table. This may be helpful throughout the exam.



1. 2.

, Do the conversions shown below, showing all work:
1. 28oC = ? oK
2. 158oF = ? oC
3. 343oK = ? oF

1. 28oC + 273 = 301 oK oC → oK (make larger) +273
2. 158oF - 32 ÷ 1.8 = 70 oC F → oC (make
o


smaller)
-32 ÷1.8
3. 343oK - 273 = 70 oC x 1.8 + 32 = 158 oF oK → oC → oF

Question 4
Click this link to access the Periodic Table. This may be helpful throughout the exam.


Be sure to show the correct number of significant figures in each calculation.


1. Show the calculation of the mass of a 18.6 ml sample of freon with density of 1.49
g/ml


2. Show the calculation of the density of crude oil if 26.3 g occupies 30.5 ml.

1. M = D x V = 1.49 x 18.6 = 27.7 g
2. D = M / V = 26..5 = 0.862 g/ml


Question 5
Click this link to access the Periodic Table. This may be helpful throughout the exam.


3.0600 contains ? significant figures.
0.0151 contains ? significant figures.


3.0600 ÷ 0.0151 = ? (give answer to correct number of significant figures)

1. 3.0600 contains 5 significant figures.

1. 2.

, 3.


2. 0.0151 contains 3 significant figures.
3. 3.0600 ÷ 0.0151 = 202.649 = 203 (to 3 significant figures for
0.0151)


Question 6
Click this link to access the Periodic Table. This may be helpful throughout the exam.
Classify each of the following as an element, compound, solution or heterogeneous mixture
and explain your answer.
1. Coca cola
2. Calcium
3. Chili


1. Coca cola - is not on periodic table (not element) - no element names (not compound)
appears to be one substance = Solution

2. Calcium - is on periodic table = Element

3. Chili - is not on periodic table (not element) - no element names (not compound)
appears as more than one substance (meat, beans,
sauce) = Hetero Mix

Question 7
Click this link to access the Periodic Table. This may be helpful throughout the exam.


Classify each of the following as a chemical change or a physical change


Charcoal burns
Mixing cake batter with water




1. 2.