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By what factor is the proton concentration increased in the experiments
shown in Figure 1B from those shown in Figure 1A?
A.2
B.10
C.200
D.1000
"The solution contained either a pH 7 buffer (A) or a pH 4 buffer (B)" -
correct answer -They are 3 units away. Ph is in bases of 10. 10^3= 1000
Which structure represents a phosphorylated subunit of glycogen as
described in the passage?
,Passage: It was discovered that approximately one out of every 600-
1500 glucose molecules in muscle glycogen contains phosphate groups
covalently linked to the C2 and C3 positions as monoesters. - correct
answer -Gotta look for the molecule with phosphates at C2 and c3!
Which type of bond is formed by glycogen synthase upon release of
UDP?
A.α-1,4-Glycosidic bond
B.α-1,6-Glycosidic bond
C.β-1,4-Glycosidic bond
D.β-1,6-Glycosidic bond - correct answer -The answer is A because the
bond that is formed by glycogen synthase is the main chain linkage of
glycogen, which is an α-1,4-glycosidic bond. UDP release means that
only glucose was added.
In addition to glucose, what other monosaccharide is part of the UDP-
glucose structure?
A.Xylose
B.Fructose
,C.Ribose
D.Arabinose - correct answer -UDP-------> uracil
C) ribose
Addition of laforin to the reaction mixtures used to generate the data in
Figure 2 will result in:
A.a decrease in the intensity of the band representing WT without
glucosidase when visualized with 14C decay.
B.an increase in the intensity of the band representing WT without
glucosidase when visualized with 14C decay.
C.a decrease in the intensity of the band representing WT without
glucosidase when visualized with 32P decay.
D.an increase in the intensity of the band representing WT without
glucosidase when visualized with 32P decay.
Passage: LBs contain a much larger amount of covalently-linked
phosphate compared to normal glycogen. The abundance of phosphate
has been linked to a mutation in the gene for laforin, a phosphatase
, specific to carbohydrates. - correct answer -***ALL ABOUT
PHOSPHATASE (bye A and B)
Phosphatases REMOVE phosphates.
C.
The radioactive decay described in the passage results in the formation
of which two atoms?
A.N and S
B.B and Si
C.B and S
D.N and Si
Beta decay is talked about in the passage.
passage: SDS-PAGE analysis from muscle extracts visualized with either
14C or 32P - correct answer -The answer to this question is A because
the type of radioactive decay is b-1 so a neutron is converted into a
proton