George Limbrunner All Chapters 1 to 21 Covered
,Table of contents
1. Introduction
2. Principles of Statics
3. Resultants of Coplanar Force Systems
4. Equilibrium of Coplanar Force Systems
5. Analysis of Structures
6. Friction
7. Centroids and Centers of Gravity
8. Area Moments of Inertia
9. Stresses and Strains
10. Properties of Materials
11. Stress Considerations
12. Torsion in Circular Sections
13. Shear and Bending Moment in Beams
14. Stresses in Beams
15. Deflection of Beams
16. Design of Beams
17. Combined Stresses
18. Columns
19. Connections
20. Pressure Vessels
21. Statically Indeterminate Beams
iv
Copyright © 2020 Pearson Education, Inc.
, Solution Manual FOR APPLIED STATICS AND STRENGTH OF
MATERIALS
Seventh Edition
George F. Limbrunner, P.E., (INACTIVE)
Craig T. D’Allaird, P.E.
NOTES:
1. The solutions presented herein are, in general, somewhat abbreviated to conserve space. Very
little explanation is furnished. Sкetches are кept to a minimum. Few checкs are shown.
2. The solutions follow the procedures developed in the examples in the text.
3. The solutions are based on the limited tables furnished in the text and/or the appendices.
The tables furnished are for the purposes of this text only and should not be used for design.
4. The solutions for the design problems are generally not the only solution nor are they
necessarily the most economical solutions.
5. Please note that problem numbers in the solution manual are depicted with both dashes (‐)
and periods (.) between the chapter and problem numbers. These are interchangeable.
6. It should be noted that the previous editions of the text used lowercase s to denote stresses.
This has changed in the 7th edition, but due to time constraints this solution manual has not
been completely updated to reflect such.
7. If you find errors in this manual or in the text, please forward them to me at
.
Craig T. D’Allaird
Troy,
NYJanuary
2021
iii
Copyright © 2021 Pearson Education, Inc.
, Prob. 1.1
(a) 𝑐 = √102 + 72 = 12.21 ft
(b) 𝑏 = √202 − 162 = 12.00 m
Prob. 1.2
(a) 𝑎 = 25 sin 48° = 18.58 ft
(b) 𝑏 = √252 − 18.582 = 16.73 ft
(c) ℎ = b sin 48° = 16.73 sin 48° = 12.43 ft
Prob. 1.3
𝑎 = √722 − 67.32 = 25.59 ft
A = cos (67.3/72) = 20.8
–1
B = sin (67.3/72) = 69.2°
–1
Prob. 1.4
AB = 28 sin 70° = 26.3 ft
Prob. 1.5
𝑐 = √102 + 62 = 11.6 ft
𝜃 = tan−1(6⁄10) = 31.0°
Prob. 1.6
𝐴𝐵 = √122 + 162 = 20 ft
𝐵𝐶 = √122 + 322 = 34.2 ft
𝐴 = tan−1(12⁄16) = 36.9°
𝐶 = tan−1(12⁄32) = 20.6°
Prob. 1.7
θ = sin−1(5⁄6) = 56.4°
𝑥 = √122 + 102 = 6.63 ft
1-1