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STAT 200 Week 6 9.1.2 Many high school students take the AP tests in different subject areas. In 2007, of the 144,796 students who took the biology exam 84,199 of them were female. In that same year, of the 211,693 students who took the calculus AB exam 102,598 of them were female ("AP exam scores," 2013). Estimate the difference in the proportion of female students taking the biology exam and female students taking the calculus AB exam using a 90% confidence level. 9.1.5 Are there more children diagnosed with Autism Spectrum Disorder (ASD) in states that have larger urban areas over states that are mostly rural? In the state of Pennsylvania, a fairly urban state, there are 245 eight year olds diagnosed with ASD out of 18,440 eight year olds evaluated. In the state of Utah, a fairly rural state, there are 45 eight year olds diagnosed with ASD out of 2,123 eight year olds evaluated ("Autism and developmental," 2008). Is there enough evidence to show that the proportion of children diagnosed with ASD in Pennsylvania is more than the proportion in Utah? Test at the 1% level. 9.2.3 All Fresh Seafood is a wholesale fish company based on the east coast of the U.S. Catalina Offshore Products is a wholesale fish company based on the west coast of the U.S. Table #9.2.5 contains prices from both companies for specific fish types ("Seafood online," 2013) ("Buy sushi grade," 2013). Do the data provide enough evidence to show that a west coast fish wholesaler is more expensive than an east coast wholesaler? Test at the 5% level. 9.2.6 The British Department of Transportation studied to see if people avoid driving on Friday the 13th. They did a traffic count on a Friday and then again on a Friday the 13th at the same two locations ("Friday the 13th," 2013). The data for each location on the two different dates is in table #9.2.6. Estimate the mean difference in traffic count between the 6th and the 13th using a 90% level. 9.3.1 The income of males in each state of the United States, including the District of Columbia and Puerto Rico, are given in table #9.3.3, and the income of females is given in table #9.3.4 ("Median income of," 2013). Is there enough evidence to show that the mean income of males is more than of females? Test at the 1% level. 9.3.3 A study was conducted that measured the total brain volume (TBV) (in mm3 ) of patients that had schizophrenia and patients that are considered normal. Table #9.3.5 contains the TBV of the normal patients and table #9.3.6 contains the TBV of schizophrenia patients ("SOCR data oct2009," 2013). Is there enough evidence to show that the patients with schizophrenia have less TBV on average than a patient that is considered normal? Test at the 10% level. 9.3.4 A study was conducted that measured the total brain volume (TBV) (in mm3 ) of patients that had schizophrenia and patients that are considered normal. Table #9.3.5 contains the TBV of the normal patients and table #9.3.6 contains the TBV of schizophrenia patients ("SOCR data oct2009," 2013). Compute a 90% confidence interval for the difference in TBV of normal patients and patients with Schizophrenia. 9.3.8 The number of cell phones per 100 residents in countries in Europe is given in table #9.3.9 for the year 2010. The number of cell phones per 100 residents in countries of the Americas is given in table #9.3.10 also for the year 2010 ("Population reference bureau," 2013). Find the 98% confidence interval for the different in mean number of cell phones per 100 residents in Europe and the Americas. 11.3.2 Levi-Strauss Co manufactures clothing. The quality control department measures weekly values of different suppliers for the percentage difference of waste between the layout on the computer and the actual waste when the clothing is made (called run-up). The data is in table #11.3.3, and there are some negative values because sometimes the supplier is able to layout the pattern better than the computer ("Waste run up," 2013). Do the data show that there is a difference between some of the suppliers? Test at the 1% level. 11.3.4

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9.1.2

Many high school students take the AP tests in different subject areas. In 2007, of
the 144,796 students who took the biology exam 84,199 of them were female. In
that same year, of the 211,693 students who took the calculus AB exam 102,598 of
them were female ("AP exam scores," 2013). Estimate the difference in the
proportion of female students taking the biology exam and female students taking
the calculus AB exam using a 90% confidence level.

Given that



n1=144796,n2=211693
90% confidence interval for difference in p1-p2
=(0.5815-0.4847)+/-1.645*sqrt((0.5815*(1-0.5815)/144796)+(0.4847*(1-
0.4847)/211693))
=0.0968+/-0.0028
=(0.0941, 0.0996)

9.1.5
Are there more children diagnosed with Autism Spectrum Disorder (ASD) in states
that have larger urban areas over states that are mostly rural? In the state of
Pennsylvania, a fairly urban state, there are 245 eight year olds diagnosed with ASD
out of 18,440 eight year olds evaluated. In the state of Utah, a fairly rural state, there
are 45 eight year olds diagnosed with ASD out of 2,123 eight year olds evaluated
("Autism and developmental," 2008). Is there enough evidence to show that the
proportion of children diagnosed with ASD in Pennsylvania is more than the
proportion in Utah? Test at the 1% level.

Research Question:
Is there enough evidence to show that the proportion of children diagnosed
with ASD in Pennsylvania is more than the proportion in Utah?

Let p1 = Proportion of children diagnosed with ASD in Pennsylvania

p2 = Proportion of children diagnosed with ASD in Utah

Null hypothesis:
H0: There is no significant difference between the proportion of children
diagnosed with ASD between Pennsylvania and Utah, p 1 = p2

, Alternative hypothesis:
H1: The proportion of children diagnosed with ASD in Pennsylvania is more
than the porportion of children diagnosed with ASD in Utah, p 1 > p2

Level of significance:


Critical Region:
Since, the alternative hypothesis is testing on the one-side(researcher is
interseted if proportion in one group is more than the other) the hypothesis is
tested at one tail. Therefore, form the standard normal table for 1% level of
significance the Z-value is given as 2.33. Therefore, the null hypothesis will be
rejected if the Z-test statistic is more than 2.33

Test statistic:




Where
p1 = Proportion of children diagnosed with ASD in Pennsylvania = 245/18440
= 0.0133
p2 = Proportion of children diagnosed with ASD in Utah = 45/2123 = 0.0212
n1 = Number of children in Pennsylvania = 18440
n2 = Number of children in Utah = 2123



x1 = Number of Children diagnosed with ASD in Pennsylvania = 245
x2 = Number of Children diagnosed with ASD in Utah = 45
Therefore,

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