CHEM 120-CHAMBERLAIN EXAM 1 STUDY
GUIDE 2026/2027 COMPLETE QUESTIONS
WITH VERIFIED CORRECT ANSWERS ||
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1. law - ANSWER ✔ concise verbal mathematic statement of a behavior that
seems always to be the same under the same conditions
2. theory - ANSWER ✔ unifying principals that explains a body of facts and
laws based on them
3. macroscopic - ANSWER ✔ samples of matter easily observed
4. particulate - ANSWER ✔ smaller than we can see (even with a microscope)
5. heterogeneous mixture - ANSWER ✔ uneven texture
6. homogeneous mixture - ANSWER ✔ same throughout
7. pure substance - ANSWER ✔ has a set of unique properties that cant be
separated
,8. compounds - ANSWER ✔ pure substances composed of 2 or more elements
that bond together (have properties different than the individual substances)
9. ionic compound - ANSWER ✔ composed of ions (cation and anion)
10.molecular compounds - ANSWER ✔ compound where atoms share
electrons
11.subatomic partials - ANSWER ✔ proton
neutron
electron
12.lavoisier - ANSWER ✔ -law of conservation of mass
13.Proust - ANSWER ✔ -law of definite proportion
14.law of definite proportion - ANSWER ✔ -a given compound always
contains exactly the same proportion of elements by mass
15.Dalton - ANSWER ✔ -beginning of true atomic theory
- elements were composed of tiny particals called atoms
-a given compound would always contain the same combination of elements
16.Daltons atomic theory - ANSWER ✔ 1. each element is composed of tiny
particles called atoms
2. atoms of a given element are identical to eachother
3. chemical compounds are formed when atoms combine
4. chemical reactions involve rearrangement of the atoms
,17.avagadros number - ANSWER ✔ 6.022 x10^23
18.What does a solution consist of? - ANSWER ✔ Solute particles dissolved in
a solvent (majority component of the soln)
19.What is an aqueous solution? - ANSWER ✔ Water serves as the solvent
The (aq) symbol means a species is in the aqueous phase which indicates
that the species is dissolved in water as independently-moving solute
particles
20.What is concentration? - ANSWER ✔ Measure of how much solute exists
per unit volume of the solution.
Core assumption: The solute particles are uniformly distributed through the
solution
21.What do soluble salts dissociate into? - ANSWER ✔ Cations (+) and anions
(-)
22.Molarity - ANSWER ✔ Molar concentration , M
The number of moles of solute particles per unit volume (mol/L)
M = mol of solute / Vol of solution in L
or [M]=mol of solute / Vol of solution
[HCl]=0.20 M indicates a solution with 0.20 mol HCl per liter of solution
, 23.Find the molarity of NO3- in a 1.00 M Ca(NO3)2 solution - ANSWER ✔
2.00 M NO3- because each unit of Ca(NO3)2 carries 2 NO3- ions into the
solution
24.Calculate [C6H12O6] when 50.0g of glucose are dissolved in enough water
to make a final solution with a volume of 200. mL
Mm(C6H12O6) = 180.2 g/mol - ANSWER ✔ [C6H12O6] = mol
C6H12O6/𝑉ol L
=(mass C6H12O6/𝑀𝑀𝑀𝑀(C6H12O6))/𝑉ol L
=(50.0 g/180.2 g/mol)/0.200 L
=1.39 Mol/L
=1.39 M
25.How do you solve for mol when given [M] and Volume? - ANSWER ✔ Mol
x = [X] x Vol in L
26.Calculate the moles of Na+ in 25.0 mL of a 0.0500 M Na2SO4 (aq) solution.
Note that Na2SO4 is a soluble salt - ANSWER ✔ mol Na+ = [Na+] x Vol in
L
Each unit of Na2SO4 dissociates into 2 Na+ ions:
Na2SO4 (aq) → 2 Na+ (aq) + SO42- (aq)
So [Na+] = [Na2SO4] (2 Na+/1 Na2SO4)
[Na+] = [Na2SO4] (2 Na+/ 1 Na2SO4)
= (0.0500 M Na2So4)(2Na+/1 Na2SO4)
= 0.100 M Na+
mol Na+ = [Na+] (Vol L)
=(0.100 mol Na+/L)(0.0250L)
=2.50 x 10^-3 mol Na+
GUIDE 2026/2027 COMPLETE QUESTIONS
WITH VERIFIED CORRECT ANSWERS ||
100% GUARANTEED PASS
<NEWEST VERSION>
1. law - ANSWER ✔ concise verbal mathematic statement of a behavior that
seems always to be the same under the same conditions
2. theory - ANSWER ✔ unifying principals that explains a body of facts and
laws based on them
3. macroscopic - ANSWER ✔ samples of matter easily observed
4. particulate - ANSWER ✔ smaller than we can see (even with a microscope)
5. heterogeneous mixture - ANSWER ✔ uneven texture
6. homogeneous mixture - ANSWER ✔ same throughout
7. pure substance - ANSWER ✔ has a set of unique properties that cant be
separated
,8. compounds - ANSWER ✔ pure substances composed of 2 or more elements
that bond together (have properties different than the individual substances)
9. ionic compound - ANSWER ✔ composed of ions (cation and anion)
10.molecular compounds - ANSWER ✔ compound where atoms share
electrons
11.subatomic partials - ANSWER ✔ proton
neutron
electron
12.lavoisier - ANSWER ✔ -law of conservation of mass
13.Proust - ANSWER ✔ -law of definite proportion
14.law of definite proportion - ANSWER ✔ -a given compound always
contains exactly the same proportion of elements by mass
15.Dalton - ANSWER ✔ -beginning of true atomic theory
- elements were composed of tiny particals called atoms
-a given compound would always contain the same combination of elements
16.Daltons atomic theory - ANSWER ✔ 1. each element is composed of tiny
particles called atoms
2. atoms of a given element are identical to eachother
3. chemical compounds are formed when atoms combine
4. chemical reactions involve rearrangement of the atoms
,17.avagadros number - ANSWER ✔ 6.022 x10^23
18.What does a solution consist of? - ANSWER ✔ Solute particles dissolved in
a solvent (majority component of the soln)
19.What is an aqueous solution? - ANSWER ✔ Water serves as the solvent
The (aq) symbol means a species is in the aqueous phase which indicates
that the species is dissolved in water as independently-moving solute
particles
20.What is concentration? - ANSWER ✔ Measure of how much solute exists
per unit volume of the solution.
Core assumption: The solute particles are uniformly distributed through the
solution
21.What do soluble salts dissociate into? - ANSWER ✔ Cations (+) and anions
(-)
22.Molarity - ANSWER ✔ Molar concentration , M
The number of moles of solute particles per unit volume (mol/L)
M = mol of solute / Vol of solution in L
or [M]=mol of solute / Vol of solution
[HCl]=0.20 M indicates a solution with 0.20 mol HCl per liter of solution
, 23.Find the molarity of NO3- in a 1.00 M Ca(NO3)2 solution - ANSWER ✔
2.00 M NO3- because each unit of Ca(NO3)2 carries 2 NO3- ions into the
solution
24.Calculate [C6H12O6] when 50.0g of glucose are dissolved in enough water
to make a final solution with a volume of 200. mL
Mm(C6H12O6) = 180.2 g/mol - ANSWER ✔ [C6H12O6] = mol
C6H12O6/𝑉ol L
=(mass C6H12O6/𝑀𝑀𝑀𝑀(C6H12O6))/𝑉ol L
=(50.0 g/180.2 g/mol)/0.200 L
=1.39 Mol/L
=1.39 M
25.How do you solve for mol when given [M] and Volume? - ANSWER ✔ Mol
x = [X] x Vol in L
26.Calculate the moles of Na+ in 25.0 mL of a 0.0500 M Na2SO4 (aq) solution.
Note that Na2SO4 is a soluble salt - ANSWER ✔ mol Na+ = [Na+] x Vol in
L
Each unit of Na2SO4 dissociates into 2 Na+ ions:
Na2SO4 (aq) → 2 Na+ (aq) + SO42- (aq)
So [Na+] = [Na2SO4] (2 Na+/1 Na2SO4)
[Na+] = [Na2SO4] (2 Na+/ 1 Na2SO4)
= (0.0500 M Na2So4)(2Na+/1 Na2SO4)
= 0.100 M Na+
mol Na+ = [Na+] (Vol L)
=(0.100 mol Na+/L)(0.0250L)
=2.50 x 10^-3 mol Na+
