WGU | BIOD 210
OBJECTIVE ASSESSMENT - EXAM
BIOD 210 Genetics
Final Exam
BIOD 210 | Genetics 2026/2027
50 100% 2026/2027
QUESTIONS VERIFIED ANSWERS EDITION
TOPICS COVERED
• Mendelian Genetics & Inheritance • Population Genetics & Evolution
• Molecular Genetics & DNA Structure • Genetic Mutations & Disorders
• Gene Expression & Regulation • Genetic Testing & Technology
COVER PAGE - 1
, SECTION 1 | Mendelian Genetics & Inheritance | Q1-Q10 | BIOD 210 Genetics 2026/2027
Q1 Question 1 of 50
A 28-year-old woman with brown eyes (heterozygous Bb) and a 30-year-old man with blue
eyes (bb) are planning to have children. What is the probability that their first child will have
blue eyes?
A. 0%
B. 25%
C. 50%
D. 75%
Correct Answer: C
Rationale:
The mother is Bb and the father is bb. A Punnett square shows 50% Bb (brown eyes) and 50% bb (blue
eyes). The blue-eyed phenotype requires two recessive alleles, which occurs in half of the offspring. 25%
would be incorrect because that would require both parents to be heterozygous carriers.
Q2 Question 2 of 50
A 45-year-old male patient presents with a family history of Huntington disease, an
autosomal dominant disorder. His father was affected but his mother was not. What is the
probability that this patient inherited the Huntington allele from his father?
A. 0%
B. 25%
C. 50%
D. 100%
Correct Answer: C
Rationale:
Huntington disease is autosomal dominant with complete penetrance. An affected heterozygous parent has
a 50% chance of passing the dominant allele to each offspring. The unaffected mother contributes no
disease alleles. 100% would only apply if the father were homozygous dominant, which is extremely rare for
Huntington disease.
, Q3 Question 3 of 50
A 35-year-old woman is a known carrier of hemophilia A, an X-linked recessive disorder.
She and her unaffected husband are expecting a child. What is the probability that a male
child will be affected with hemophilia A?
A. 0%
B. 25%
C. 50%
D. 100%
Correct Answer: C
Rationale:
The mother is a carrier (X^H X^h) and the father is unaffected (X^H Y). A male child receives his only X
chromosome from his mother. There is a 50% chance he receives the mutant X^h allele and will be affected.
Female children have a 50% chance of being carriers but are typically unaffected.
Q4 Question 4 of 50
In a genetics clinic, a 32-year-old woman with type A blood and a 34-year-old man with
type B blood have a child with type O blood. What must be true about the parents'
genotypes?
A. Both parents are homozygous dominant
B. Both parents are heterozygous
C. Only the mother is heterozygous
D. Only the father is heterozygous
Correct Answer: B
Rationale:
Type O blood requires the genotype OO (two recessive i alleles). For a type A parent to produce an O child,
they must be genotype I^A i. For a type B parent to produce an O child, they must be genotype I^B i. Both
must be heterozygous to each contribute an i allele. Homozygous parents (I^A I^A or I^B I^B) cannot
produce type O offspring.
OBJECTIVE ASSESSMENT - EXAM
BIOD 210 Genetics
Final Exam
BIOD 210 | Genetics 2026/2027
50 100% 2026/2027
QUESTIONS VERIFIED ANSWERS EDITION
TOPICS COVERED
• Mendelian Genetics & Inheritance • Population Genetics & Evolution
• Molecular Genetics & DNA Structure • Genetic Mutations & Disorders
• Gene Expression & Regulation • Genetic Testing & Technology
COVER PAGE - 1
, SECTION 1 | Mendelian Genetics & Inheritance | Q1-Q10 | BIOD 210 Genetics 2026/2027
Q1 Question 1 of 50
A 28-year-old woman with brown eyes (heterozygous Bb) and a 30-year-old man with blue
eyes (bb) are planning to have children. What is the probability that their first child will have
blue eyes?
A. 0%
B. 25%
C. 50%
D. 75%
Correct Answer: C
Rationale:
The mother is Bb and the father is bb. A Punnett square shows 50% Bb (brown eyes) and 50% bb (blue
eyes). The blue-eyed phenotype requires two recessive alleles, which occurs in half of the offspring. 25%
would be incorrect because that would require both parents to be heterozygous carriers.
Q2 Question 2 of 50
A 45-year-old male patient presents with a family history of Huntington disease, an
autosomal dominant disorder. His father was affected but his mother was not. What is the
probability that this patient inherited the Huntington allele from his father?
A. 0%
B. 25%
C. 50%
D. 100%
Correct Answer: C
Rationale:
Huntington disease is autosomal dominant with complete penetrance. An affected heterozygous parent has
a 50% chance of passing the dominant allele to each offspring. The unaffected mother contributes no
disease alleles. 100% would only apply if the father were homozygous dominant, which is extremely rare for
Huntington disease.
, Q3 Question 3 of 50
A 35-year-old woman is a known carrier of hemophilia A, an X-linked recessive disorder.
She and her unaffected husband are expecting a child. What is the probability that a male
child will be affected with hemophilia A?
A. 0%
B. 25%
C. 50%
D. 100%
Correct Answer: C
Rationale:
The mother is a carrier (X^H X^h) and the father is unaffected (X^H Y). A male child receives his only X
chromosome from his mother. There is a 50% chance he receives the mutant X^h allele and will be affected.
Female children have a 50% chance of being carriers but are typically unaffected.
Q4 Question 4 of 50
In a genetics clinic, a 32-year-old woman with type A blood and a 34-year-old man with
type B blood have a child with type O blood. What must be true about the parents'
genotypes?
A. Both parents are homozygous dominant
B. Both parents are heterozygous
C. Only the mother is heterozygous
D. Only the father is heterozygous
Correct Answer: B
Rationale:
Type O blood requires the genotype OO (two recessive i alleles). For a type A parent to produce an O child,
they must be genotype I^A i. For a type B parent to produce an O child, they must be genotype I^B i. Both
must be heterozygous to each contribute an i allele. Homozygous parents (I^A I^A or I^B I^B) cannot
produce type O offspring.
