Jianne Marie E. Tapang
I affirm that I have not given or received any unauthorized help on this graded assignment
and this work is my own.
Assignment 4.2 Pearson Product Moment of Correlation
1. The average normal daily temperature ( in degree Celsius) and the corresponding average
monthly precipitation( in inches ) for the month of June are shown below for seven
randomly selected cities. Compute for the value of r, complete the table with the needed
information.
% & %! &! %&
30 3.4 900 11.56 102
27 1.8 729 3.24 48.6
28 3.5 784 12.25 98
32 3.6 1024 12.96 115.2
27 3.7 729 13.69 99.9
23 1.5 529 2.25 35.5
18 0.2 324 0.04 3.6
Σ% = 185 Σy = 17.7 Σ% ! = 5019 Σ& ! = 55.99 Σ%& = 501.8
#Σ%& − (Σ%)(Σy)
!=
+[#(Σ% ! ) − (Σ%)! ] [#(Σ& ! ) − (Σ&)! ]
7(501.8) − (185)(17.7)
!=
+[7(5019) − (185)! ] [7(55.99) − (17.7)! ]
6 = 7. 89: ;6 7. 89
2. A law enforcement officer obtained data on the performance rating of the police offices and
the crime solution efficiency in their respective areas of responsibilities for the last 6
months. The data are shown below, find the value of r by completing the table.
% & %! &! %&
85 89 7225 7921 7565
89 90 7921 8100 8010
91 92 8281 8464 8372
93 92 8649 8464 8556
84 88 7056 7744 7392
89 90 7921 8100 8010
Σ% = 531 Σy = 541 ! ! Σ%& = 47905
Σ% = 47053 Σ& = 48793
6(47905) − (531)(541)
!=
+[6(47053) − (531)! ] [6(48793) − (541)! ]
6 = 7. 9?9 ;6 7. 9@
I affirm that I have not given or received any unauthorized help on this graded assignment
and this work is my own.
Assignment 4.2 Pearson Product Moment of Correlation
1. The average normal daily temperature ( in degree Celsius) and the corresponding average
monthly precipitation( in inches ) for the month of June are shown below for seven
randomly selected cities. Compute for the value of r, complete the table with the needed
information.
% & %! &! %&
30 3.4 900 11.56 102
27 1.8 729 3.24 48.6
28 3.5 784 12.25 98
32 3.6 1024 12.96 115.2
27 3.7 729 13.69 99.9
23 1.5 529 2.25 35.5
18 0.2 324 0.04 3.6
Σ% = 185 Σy = 17.7 Σ% ! = 5019 Σ& ! = 55.99 Σ%& = 501.8
#Σ%& − (Σ%)(Σy)
!=
+[#(Σ% ! ) − (Σ%)! ] [#(Σ& ! ) − (Σ&)! ]
7(501.8) − (185)(17.7)
!=
+[7(5019) − (185)! ] [7(55.99) − (17.7)! ]
6 = 7. 89: ;6 7. 89
2. A law enforcement officer obtained data on the performance rating of the police offices and
the crime solution efficiency in their respective areas of responsibilities for the last 6
months. The data are shown below, find the value of r by completing the table.
% & %! &! %&
85 89 7225 7921 7565
89 90 7921 8100 8010
91 92 8281 8464 8372
93 92 8649 8464 8556
84 88 7056 7744 7392
89 90 7921 8100 8010
Σ% = 531 Σy = 541 ! ! Σ%& = 47905
Σ% = 47053 Σ& = 48793
6(47905) − (531)(541)
!=
+[6(47053) − (531)! ] [6(48793) − (541)! ]
6 = 7. 9?9 ;6 7. 9@
