Geschreven door studenten die geslaagd zijn Direct beschikbaar na je betaling Online lezen of als PDF Verkeerd document? Gratis ruilen 4,6 TrustPilot
logo-home
Tentamen (uitwerkingen)

MATH 225N WEEK 6 QUIZ STATISTICS – QUESTION AND ANSWERS

Beoordeling
-
Verkocht
-
Pagina's
25
Cijfer
A+
Geüpload op
05-04-2022
Geschreven in
2021/2022

MATH 225N WEEK 6 QUIZ STATISTICS – QUESTION AND ANSWERS Question 1 A statistics professor recently graded final exams for students in her introductory statistics course. In a review of her grading, she found the mean score out of 100 points was a x¯=77, with a margin of error of 10. Construct a confidence interval for the mean score (out of 100 points) on the final exam. ________________________________________ That is correct! ________________________________________ $$(67, 87) Answer Explanation Correct answers: • $left(67, 87right)$(67, 87) A confidence interval is an interval of values, centered on a point estimate, of the form (pointestimate−marginof error,pointestimate+marginof error) Using the given point estimate for the mean, x¯=77 and margin of error 10, the confidence interval is: (77−10,77+10)(67,87) FEEDBACK • • • • Content attribution- Opens a dialog Question 2 A random sample of adults were asked whether they prefer reading an e-book over a printed book. The survey resulted in a sample proportion of p′=0.14, with a sampling standard deviation of σp′=0.02, who preferred reading an e-book. Use the empirical rule to construct a 95% confidence interval for the true proportion of adults who prefer e-books. ________________________________________ That is correct! ________________________________________ $$(0.1, 0.18) Answer Explanation Correct answers: • $left(0.10, 0.18right)$(0.10, 0.18) By the Empirical Rule, a 95% confidence interval corresponds to a z-score of z=2. Substituting the given values p′=0.14and σp′=0.02, a confidence interval is (p′−z⋅σp′,p′+z⋅σp′)(0.14−2⋅0.02,0.14+2⋅0.02)(0.14−0.04,0.14+0.04)(0.10,0.18) FEEDBACK • • • • Content attribution- Opens a dialog Question 3 The pages per book in a library are normally distributed with an unknown population mean. A random sample of books is taken and results in a 95% confidence interval of (237,293) pages. What is the correct interpretation of the 95% confidence interval? ________________________________________ That is correct! ________________________________________ We estimate with 95% confidence that the sample mean is between 237 and 293 pages. We estimate that 95% of the time a book is selected, there will be between 237 and 293 pages. We estimate with 95% confidence that the true population mean is between 237 and 293 pages. Answer Explanation Correct answer: We estimate with 95% confidence that the true population mean is between 237 and 293 pages. Once a confidence interval is calculated, the interpretation should clearly state the confidence level (CL), explain what population parameter is being estimated, and state the confidence interval. We estimate with 95% confidence that the true population mean is between 237 and 293 pages. FEEDBACK • • • • Content attribution- Opens a dialog Question 4 The population standard deviation for the heights of dogs, in inches, in a city is 3.7 inches. If we want to be 95% confident that the sample mean is within 2 inches of the true population mean, what is the minimum sample size that can be taken? z0.101.282z0.051.645z0.0251.960z0.012.326z0.0052.576 Use the table above for the z-score, and be sure to round up to the nearest integer. ________________________________________ That is correct! ________________________________________ $$14 dog heights Answer Explanation Correct answers: • $14text{ dog heights}$14 dog heights The formula for sample size is n=z2σ2EBM2. In this formula, z=zα2=z0.025=1.96, because the confidence level is 95%. From the problem, we know that σ=3.7 and EBM=2. Therefore, n=z2σ2EBM2=(1.96)2(3.7)222≈13.15. Use n=14 to ensure that the sample size is large enough. Also, the sample size formula shown above is sometimes written using an alternate format of n=(zσE)2. In this formula, E is used to denote margin of error and the entire parentheses is raised to the exponent 2. Therefore, the margin of error for the mean can be denoted by "EBM" or by "E". Either formula for the sample size can be used and these formulas are considered as equivalent. FEEDBACK • • • • Content attribution- Opens a dialog

Meer zien Lees minder
Instelling
Vak

Voorbeeld van de inhoud

MATH 225N WEEK 6 QUIZ STATISTICS –
QUESTION AND ANSWERS
Question 1
A statistics professor recently graded final exams for students in her introductory
statistics course. In a review of her grading, she found the mean score out
of 100 points was a x¯=77, with a margin of error of 10.

Construct a confidence interval for the mean score (out of 100 points) on the final
exam.

That is correct!

$$(67, 87)
Answer Explanation
Correct answers:
 $\left(67,\ 87\right)$(67, 87)


A confidence interval is an interval of values, centered on a point estimate, of the form

(pointestimate−marginof error,pointestimate+marginof
error)

Using the given point estimate for the mean, x¯=77 and margin of error 10, the
confidence interval is:

(77−10,77+10)(67,87)
FEEDBACK







Content attribution- Opens a dialog

Question 2

,A random sample of adults were asked whether they prefer reading an e-book over a
printed book. The survey resulted in a sample proportion of p′=0.14, with a sampling
standard deviation of σp′=0.02, who preferred reading an e-book.

Use the empirical rule to construct a 95% confidence interval for the true proportion of
adults who prefer e-books.

That is correct!

$$(0.1, 0.18)
Answer Explanation
Correct answers:
 $\left(0.10,\ 0.18\right)$(0.10, 0.18)


By the Empirical Rule, a 95% confidence interval corresponds to a z-score of z=2.
Substituting the given values p′=0.14and σp′=0.02, a confidence interval is

(p′−z⋅σp′,p′+z⋅σp′)(0.14−2⋅0.02,0.14+2⋅0.02)
(0.14−0.04,0.14+0.04)(0.10,0.18)
FEEDBACK







Content attribution- Opens a dialog

Question 3
The pages per book in a library are normally distributed with an unknown population
mean. A random sample of books is taken and results in a 95% confidence interval
of (237,293) pages.

What is the correct interpretation of the 95% confidence interval?

That is correct!

, We estimate with 95% confidence that the sample mean is
between 237 and 293 pages.
We estimate that 95% of the time a book is selected, there will be
between 237 and 293 pages.
We estimate with 95% confidence that the true population mean is
between 237 and 293 pages.
Answer Explanation
Correct answer:
We estimate with 95% confidence that the true population mean is
between 237 and 293 pages.

Once a confidence interval is calculated, the interpretation should clearly state the
confidence level (CL), explain what population parameter is being estimated, and state
the confidence interval.

We estimate with 95% confidence that the true population mean is
between 237 and 293 pages.

FEEDBACK







Content attribution- Opens a dialog

Question 4
The population standard deviation for the heights of dogs, in inches, in a city
is 3.7 inches. If we want to be 95% confident that the sample mean is
within 2 inches of the true population mean, what is the minimum sample size that can
be taken?
z0.101.282z0.051.645z0.0251.960z0.012.326z0.0052.576
Use the table above for the z-score, and be sure to round up to the nearest integer.

That is correct!

$$14 dog heights

Geschreven voor

Instelling
Vak

Documentinformatie

Geüpload op
5 april 2022
Aantal pagina's
25
Geschreven in
2021/2022
Type
Tentamen (uitwerkingen)
Bevat
Vragen en antwoorden

Onderwerpen

€9,75
Krijg toegang tot het volledige document:

Verkeerd document? Gratis ruilen Binnen 14 dagen na aankoop en voor het downloaden kun je een ander document kiezen. Je kunt het bedrag gewoon opnieuw besteden.
Geschreven door studenten die geslaagd zijn
Direct beschikbaar na je betaling
Online lezen of als PDF

Maak kennis met de verkoper
Seller avatar
Topesttutor1
1,0
(1)

Maak kennis met de verkoper

Seller avatar
Topesttutor1 Exam Questions
Volgen Je moet ingelogd zijn om studenten of vakken te kunnen volgen
Verkocht
2
Lid sinds
4 jaar
Aantal volgers
4
Documenten
398
Laatst verkocht
2 jaar geleden
Topesttutor1

NURSING, ECONOMICS, MATHEMATICS, BIOLOGY AND HISTORY MATERIALS Q&A MATERIAL, STUDY GUIDE MATERIALS, EXCELLENT TUTORING,EXAMS, TEST WITH ASSURANCE A+ I am a committed medical practitioner with broad and diverse knowledge in matters of Nursing and Mathematics. Besides I possesses knowledge in Mathematics based courses i.e. economics and finance with precise steps and explanations. BEST TUTORING, HOMEWORK HELP, EXAMS, TESTS, AND STUDY GUIDE MATERIALS WITH GUARANTEE OF AN A+ I am a dedicated medical practitioner with diverse knowledge in matters of Nursing and Mathematics. I also have a piece of additional knowledge in Mathematics based courses (finance and economics)

Lees meer Lees minder
1,0

1 beoordelingen

5
0
4
0
3
0
2
0
1
1

Recent door jou bekeken

Waarom studenten kiezen voor Stuvia

Gemaakt door medestudenten, geverifieerd door reviews

Kwaliteit die je kunt vertrouwen: geschreven door studenten die slaagden en beoordeeld door anderen die dit document gebruikten.

Niet tevreden? Kies een ander document

Geen zorgen! Je kunt voor hetzelfde geld direct een ander document kiezen dat beter past bij wat je zoekt.

Betaal zoals je wilt, start meteen met leren

Geen abonnement, geen verplichtingen. Betaal zoals je gewend bent via iDeal of creditcard en download je PDF-document meteen.

Student with book image

“Gekocht, gedownload en geslaagd. Zo makkelijk kan het dus zijn.”

Alisha Student

Bezig met je bronvermelding?

Maak nauwkeurige citaten in APA, MLA en Harvard met onze gratis bronnengenerator.

Bezig met je bronvermelding?

Veelgestelde vragen