MATH 110 MODULE 4 EXAM PORTAGE LEARNING
Module 4 Exam
Exam Page 1
A factory has eight safety systems. During an emergency, the probability of any one of the safety
systems failing is .08. What is the probability that six or more safety systems will fail during an
emergency?
f(x) = ( (n!) / (x!(n-x)!) ) x ( (p^x) x ((1-p)^n-x)) )
n=8
x = 6, 7, 8 (number of failures)
p = 0.08
6 failures:
n=8
x=6
p = 0.8
n-x = 8-6 = 2
( (8!) / (6!(2)!) ) x ( (0.08^6) x ((1-0.08)^2)) ) = 6.2 x 10^-6
7 failures:
n=8
x=7
p = 0.8
n-x = 8-7 = 1
( (8!) / (7!(1)!) ) x ( (0.08^7) x ((1-0.08)^1)) ) = 1.54 x 10^-7
8 failures:
n=8
x=8
p = 0.8
n-x = 8-8 = 0
( (8!) / (8!(0)!) ) x ( (0.08^8) x ((1-0.08)^0)) ) = 1.68 x 10^-9
This study source was downloaded by 100000841138256 from CourseHero.com on 07-27-2022 02:58:01 GMT -05:00
https://www.coursehero.com/file/32343987/Module-4-Examdocx/
, MATH 110 MODULE 4 EXAM PORTAGE LEARNING
f(6) = 6.21 x 10^-6
This study source was downloaded by 100000841138256 from CourseHero.com on 07-27-2022 02:58:01 GMT -05:00
https://www.coursehero.com/file/32343987/Module-4-Examdocx/