Lecture 3: If-Else, While loop & Lots of Patterns (Part-1)
In this 3rd lecture, we will learn the syntax of conditional statements in
CPP. We will make a simple program , where we will ask computer to print
A if A is bigger than B , else print B. Coding Ninjas has supported us in
providing this free DSA course. If you are given a number A , and you are
told that print +ve if A is positive, otherwise, print not +ve. If a block is not
executed, then 'else ' block will be executed. If A is 5 , then 'if A is -2 and if a
is -5, then it will print anything. If I enter -5 , then it did n't print anything
because if block was not executed this time. But if I add a 'else' block here,
then this block is executed. Cin. get ( ) takes input in the form of characters.
It took ' 1 ' as a character but we are assigning this value to an integer so
that 's why it printed ASCII value of that character. Cin do n't read SPACE ,
TAB , ENTER and TAB. But we have an another method to take input. Let 's
code that tells us which number is greater.
If ( a > 0) { print +ve } else { if ( a < 0 ) { print negative } , otherwise print 0 } }
Let 's run it again. Entered A as 15 It printed A is positive This time I
entered -1. A is negative. Correct output. We solved it using loop using loop
to understand loops clearly. You just have to enter a condition and the
statements which you want to execute. You can check your answer by
applying this formula Bhaiya. Here is your homework question. Q1- Find
sum of all even numbers from 1 to N. We have to tell whether n is prime or
not prime number is a number which has only 1 and N as it 's factor We will
use this % operator for this question. % tells us remainder when we divide 2
numbers. If any of these numbers gave modules as 0, then N is not prime. If
no such number exists, then it is a prime number.
We will run a loop from 1 to n , ( for all rows ) We declared a variable i to
keep the track of the row number and then we are simply printing star in
1
In this 3rd lecture, we will learn the syntax of conditional statements in
CPP. We will make a simple program , where we will ask computer to print
A if A is bigger than B , else print B. Coding Ninjas has supported us in
providing this free DSA course. If you are given a number A , and you are
told that print +ve if A is positive, otherwise, print not +ve. If a block is not
executed, then 'else ' block will be executed. If A is 5 , then 'if A is -2 and if a
is -5, then it will print anything. If I enter -5 , then it did n't print anything
because if block was not executed this time. But if I add a 'else' block here,
then this block is executed. Cin. get ( ) takes input in the form of characters.
It took ' 1 ' as a character but we are assigning this value to an integer so
that 's why it printed ASCII value of that character. Cin do n't read SPACE ,
TAB , ENTER and TAB. But we have an another method to take input. Let 's
code that tells us which number is greater.
If ( a > 0) { print +ve } else { if ( a < 0 ) { print negative } , otherwise print 0 } }
Let 's run it again. Entered A as 15 It printed A is positive This time I
entered -1. A is negative. Correct output. We solved it using loop using loop
to understand loops clearly. You just have to enter a condition and the
statements which you want to execute. You can check your answer by
applying this formula Bhaiya. Here is your homework question. Q1- Find
sum of all even numbers from 1 to N. We have to tell whether n is prime or
not prime number is a number which has only 1 and N as it 's factor We will
use this % operator for this question. % tells us remainder when we divide 2
numbers. If any of these numbers gave modules as 0, then N is not prime. If
no such number exists, then it is a prime number.
We will run a loop from 1 to n , ( for all rows ) We declared a variable i to
keep the track of the row number and then we are simply printing star in
1
