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College aantekeningen

PLACEMENT DSA COURCE

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IN THIS we will understand the Basics of Programming, we will create a lot of Flowcharts, also try some PseudoCodes

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We will learn about flow charts, pseudocode and programming languages. We will also
learn about programming languages and why do we use them. After this, we will write
our program. This will be our flow whenever we will solve any problem. First
question, then given values, then approach and at last we will code it. Bhaiya
explains what is a flowchart is a diagramatic approach of that approach known as
flow chart. The flow chart constitute various components, connected with each other
Bhaiyan says. He says that from where a program is starting we have a component
called terminator. Terminator is used to show the start and end start of the
program. Next block is a simple rectangle, which shows a process. Bhaiya explains
how to make a flowchart for the sum of 2 numbers. He says the pseudocode as a whole
is a generic way of representing logic. The flow of a flow chart is the same as the
flow of the components of the flow chart. We use parallelogram to show the
input/output of the program.


This Passage provides insights into programming languages, flow charts,, and
pseudocode.. The author discusses how these tools can be used to solve problems..
He also provides an example problem and the solution he comes up with in
pseudocode. Finally, he explains how to convert these solutions into executable
code. The flowchart in this passage shows the process of a program, including the
various components that are used to create it.. The first component is the
terminator, which shows the start and end of the program... The next block is a
simple rectangle, which shows a process.. The next block is a diamond-shaped block,
which is used for decision making.. The next block is an arrow, which connects the
previous two blocks.. The last component is a circle, which is used to connect the
previous three blocks.. The code block that starts. The program will take in two
numbers, A and B, and will print out their sum as 5 and 10. After that, the program
will end..


We want to make a flowchart for calculating simple interest This is the formula for
simple interest You must have studied it in your school We started our program from
this start block I do n't know p , r , t , so I need to take them as inputs first
So I asked user to give me the values for p, r and t So now I have P , R and T So I
made this rectangular block for the calculation part Here I wrote this formula
After finding this answer in the above calculation , I have to print the output too
So here I will print output with this block print SI and then we will end this
program We started the program , took a , b as input then we checked whether a is
less than b or not. If a < b print `` YES '' else print `` NO '' and its done
Simple You just have to write in english what you are thinking and it is called
pseudocode. If any number has 2 as its factor , then it is even number or ODD
number. We have to check a condition that whether N is ODD or EVEN , so we will
make one block for this condition Here is the decision making block , Is N % 2 =
0 ? We will get 2 outputs , YES or NO If output is YES, then it is an EVEN number ,
so I printed ODD Else, I will print ODD Then I made this end block and ended this
program something like this This is the flowchart for EVEN , ODD Got it right ?
Bhaiya, why are you putting this inverting commas again and again , you will come
to know soon.


We have to print something and then increment too You have to Print and then
increase the printed number too You can see here , we printed and then increased
the numbe by 1 But we do n't know how to do it How we will increase again and again
Let 's rub it You know that we have to start from 1 and print till 5 So if I give
you a number which starts from 1 to 5, will it work ? Your are like , yes , this is
what we needed So I took a number =1 This is not a input , it is a process , so I
wrote it inside rectangular block. You have to print all the odd numbers from 1 to
N as a part of your homework. The catch is , 1 and N are inclusive here in the
answer should be 15. The solution is easy , you just have to use less than equal to

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Geüpload op
10 maart 2023
Aantal pagina's
2
Geschreven in
2022/2023
Type
College aantekeningen
Docent(en)
Jenny
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