Geschreven door studenten die geslaagd zijn Direct beschikbaar na je betaling Online lezen of als PDF Verkeerd document? Gratis ruilen 4,6 TrustPilot
logo-home
Samenvatting

Summary Functional Analysis

Beoordeling
-
Verkocht
-
Pagina's
41
Geüpload op
10-04-2025
Geschreven in
2022/2023

Summary of Functional Analysis

Voorbeeld van de inhoud

Lecture 1
1.1 Linear spaces
Def 1.1 let X be a set and let K = R or C. Let X × X → X(x, y) 7→ x + y and K × X → X, (λx) 7→ λx
be maps . Then X is said to be a linear space over K if for all x, y, z ∈ X and λµ ∈ K the following
axioms are satisfied:
1. x + y = y + x
2. (x + y) + z = x + (y + z)
3. there exists 0 ∈ X such that x + 0 = x
4. there exists −x ∈ X such that x + (−x) = 0
5. λ(µx) = (λµ)x
6. 1x = x
7. λ(x + y) = λx + λy
8. (λ + µ)x = λx + µx
A subset V of a linear space X is called a linear subspace when it is a linear space itself with the given
operations.
Def 1.5 Let X be a linear space. The sum of two linear subspaces V, W ⊂ X is defined as
V + W = {x + y x ∈ V, y ∈ W }
The sum is called direct if V ∩ W = {0}.
Def 1.6 Let X be a linear space and let E ⊂ X be a set. The linear span of the set E is defined by
\
span(E) = {H ⊂ X : E ⊂ H , H linear subspace}

Prop 1.7 . The linear span of E is the unique linear subspace of X which contains E and is contained
in every linear subspace which contains E. In fact:
( n )
X
span(E) = λi ei n ∈ N, λi ∈ K, ei ∈ E, i = 1, . . . , n
i=1

Def 1.8 Let X be a linear space over K. A nonempty finite set M = {e1 , . . . , en } ⊂ X is called linearly
independent if with λ1 , . . . , λn ∈ K one has
n
X
λi ei = 0 =⇒ λ1 = · · · = λn = 0
i=1

A nonempty subset M ⊂ X is called linearly independent if every finite subset of M is linearly indepen-
dent. The dimension of X is defined by

0
 if X = {0}
dim X = n if X is spanned by n linearly independent vectors

∞ if X has an infinite linearly independent subset


A set of n linearly independent vectors which span X is called a basis for X.

1.2 Linear operators
Def 1.9 A relation T from X to Y is a set T ⊂ X × Y . If Y = X one speaks of a relation on the set X.
The domain and range of T are defined by
dom T = {x ∈ X : (x, y) ∈ T for some y ∈ Y }
ran T = {y ∈ Y : (x, y) ∈ T for some x ∈ X}


1

,respectively. A relation is called a map T : X → Y if it satisfies the following property:

(x, y) ∈ T , (x, z) ∈ T =⇒ y = z

in which case one uses the notation y = T x. A map T : X → Y is called
1. injective if for every y ∈ Y there is at most one x ∈ X with y = T x
2. surjective if for every y ∈ Y there is at least one x ∈ X with y = T x
3. bijective if for every x ∈ X there is y ∈ Y with y = T x and for every y ∈ Y there is precisely one
x ∈ X with y = T x.
Def 1.10 Let X and Y be linear spaces over K. A map T : X → Y is called linear if T is everywhere
defined on X and if for all x, y ∈ X and λ ∈ K
1. T (x + y) = T x + T y
2. T (λx) = λ(T x)
The collection of all linear maps from X to Y is denoted by L(X, Y ).
Lemma 1.11 Let X and Y be linear spaces over K and let T : X → Y be a linear map. Then T is
bijective if and only if there exists a unique linear map S : Y → X such that ST = IX and T S = IY
Def 1.12 Let X be a linear space and let P : X → X be a linear map. Then P is called a projection if
P2 = P.
Lemma 1.13 A linear map P : X → X is a projection if and only if I − P is a projection. In this case:

ran P = ker (I − P ), ker P = ran (I − P ),

Moreover, X = ran P + ker P is a direct sum.
Def 1.14 Let X be a linear space and let V, W ⊂ X be linear subspaces. Then V and W are called
complementary if X = V + W is a direct sum. The subspaces induce corresponding linear projections
denoted by PV and PW with PV + PW = I
Def 1.15 Let X be a linear space over K and let T : X → X be a linear map. The point spectrum
σP (T ) of T is the set of all eigenvalues of T :

σP (T ) = {λ ∈ K : T x = λx for some x ̸= 0}

The geometric multiplicity of λ ∈ σP (T ) is the dimension of the corresponding eigenspace ker (T − λ)
Thm 1.16 Let X be a linear space and let T : X → X be a linear map. Eigenvectors corresponding to
different eigenvalues are linearly independent.

1.3 Quotient spaces of linear spaces
Def 1.17 A relation R on a set X is called an equivalence relation if
1. for each x ∈ X one has (x, x) ∈ R (reflexivity)
2. if (x, y) ∈ R, then (y, x) ∈ R (symmetry)
3. if (x, y) ∈ R and (y, z) ∈ R, then (x, z) ∈ R (transitivity)
The statement (x, y) ∈ R is denoted by x y and the equivalence relation is denoted by . For x ∈ X the
equivalence class [x] of x is defined as

[x] = {y ∈ X : x y}

The set of all equivalence classes in X is denoted by X/ and the map π : X → X/ given by π(x) = [x]
is called the quotient map.
Thm 1.18 Let X be a set with an equivalence relation . Let x, y ∈ X, then one has the following
statements:
1. x ∈ [x]


2

, 2. [x] = [y] ⇐⇒ x y
3. [x] ∩ [y] ̸= ∅ =⇒ [x] = [y]
S
4. X = [x], the disjoint union of all equivalence classes.
x∈X

Def 1.20 Let X be a linear space and let V ⊂ X be a linear subspace. Then V induces an equivalence
relation on X by
x y ⇐⇒ y − x ∈ V
The equivalence class to which x ∈ X belongs is denoted by x + V :
x + V = {y ∈ X y − x ∈ V }
The set of equivalence classes is denoted by X/V .
Prop 1.21 The space X/V provided with the following sum and scalar multiplication is a linear space
over K:
1. (x + V ) + (y + V ) = x + y + V , x, y ∈ X
2. λ(x + V ) = λx + V , x ∈ X, λ ∈ K
Def 1.22 Let X be a linear space and let V ⊂ X be a linear subspace. The quotient map pi : X → X/V
is defined by
π(x) = x + V, x ∈ X
Lemma 1.23 The map π is linear, surjective and ker π = V

1.4 Isomorphisms between linear spaces
Thm 1.24 Let X, Y be linear spaces and let V ⊂ X be a linear subspace.
1. Let T : X → Y be a linear map such that V ⊂ ker T . Then T induces a well-defined linear map
T̂ : X/V → Y, x + V 7→ T (x)
such that T = T̂ ◦ π
2. Let S : X/V → Y be a linear map. Then T = S ◦ π : X 7→ Y is a linear map with V ⊂ ker T
Corr 1.25 Let X, Y be linear spaces and let T : X → Y be a linear map. Then
T̂ : X/ker T → Y, x + ker T 7→ T (x)
is an injective linear map, so that X/ker T isomorphic to ran T . If in addition T is surjective, T̂ :
X/ker T → Y is an isomorphism of linear spaces.
Thm 1.26 Let X be a linear space with V ⊂ X a linear subspace. If dim X < ∞, then dim X/V < ∞
and dim X/V =dim X−dim V .
Corr 1.27 Let T : X → Y be a linear map with dim X < ∞. Then
dim ker T + dim ran T = dim X

1.5 Dual spaces of linear spaces
Def 1.28 Let X be a linear space over K. The dual space of X is defined as X ′ = L(X, K). The elements
of X ′ are called functionals on X.
Lemma 1.29 Let X be a finite-dimensional linear space. Then X ′ is a finite-dimensional linear space
and dim X ′ = dim X.
Def 1.30 Let X be a linear space over K. The second-dual space of X is defined as X ′′ = L(X ′ , K).
The natural map J : X → X ′′ is given by
J(x)(f ) = f (x), x ∈ X , f ∈ X′
Lemma 1.31 Let X be a finite-dimensional linear space. Then J : X → X ′′ is a bijection.
Def 1.32 Let X, Y be linear spaces and let T : X → Y be a linear operator. Then the conjugate operator
T × : Y ′ → X ′ is the linear operator defined by
(T × f )(x) = f (T x), f ∈Y′, x∈X
Page 14


3

, Lecture notes
A familiar example: Kn = {(x1 , . . . , xn ) | xi ∈ K}
Infinite-dimensional examples:
K∞ = {(x1 , x2 , . . . ) : xi ∈ K
F([a, b], K) = {f : [a, b] → K}
”Too large” for analysis purposes
Important examples:

X
ℓp = {(x1 , x2 , . . . ) : xi ∈ K, |xi |p < ∞}, (p ≥ 1)
i=1

x = (1, 1/2, 1/3, . . . ) ̸∈ ℓ1
x = (1, 1/2, 1/3, . . . ) ∈ ℓ2
ℓ∞ = {(x1 , . . . ) : xi ∈ K, sup |xi | < ∞}
i∈N

C([a, b], K) = {f : [a, b] → K : f is continuous}
L(X, Y ) = {T : X → Y : T is linear}. If X = Y , we write L(X).
Example of projection: P : R2 → R2 , (x1 , x2 ) 7→ (0, x2 )
Lemma 1.13 proof:
Claim: (I − P ) is a projection
Proof: (I − P )2 = (I − P )(I − P ) = I − P − P + P 2 = I − 2P + P = I − P
Claim: ran P =ker (I − P ) and ker P =ran (I − P ).
Proof: x ∈ ran P ⇐⇒ x = P y for some y ∈ X ⇐⇒ P x = P 2 y = P y = x ⇐⇒ (I − P )x = 0 ⇐⇒
x ∈ ker (I − P ).
2nd claim follows from (I − P ) is a projection.
Claim: X = ker P + ran P
Proof: ⊃ is trivial
⊂: x = (I − P )x + P x for all x ∈ X
Direct sum: If x ∈ranP ∩ ker P , then, x = P y and P x = 0. Then x = P y = P 2 y = P x = 0 hence x = 0
Ex: X = {books with a single author}. x y ⇐⇒ x and y have the same author is an equivalence
relation on X.
Ex: on X = Z define the equivalence relation x y ⇐⇒ x − y is even.
[0] = {. . . , −2, 0, 2, . . . }, [1] = {. . . , −1, 1, . . . } hence Z/ = {[0], [1]}.
L(X, K) = {f : X → K : f is linear}




4

Documentinformatie

Geüpload op
10 april 2025
Aantal pagina's
41
Geschreven in
2022/2023
Type
SAMENVATTING
€3,49
Krijg toegang tot het volledige document:

Verkeerd document? Gratis ruilen Binnen 14 dagen na aankoop en voor het downloaden kun je een ander document kiezen. Je kunt het bedrag gewoon opnieuw besteden.
Geschreven door studenten die geslaagd zijn
Direct beschikbaar na je betaling
Online lezen of als PDF

Maak kennis met de verkoper
Seller avatar
jardnijholt

Maak kennis met de verkoper

Seller avatar
jardnijholt Rijksuniversiteit Groningen
Bekijk profiel
Volgen Je moet ingelogd zijn om studenten of vakken te kunnen volgen
Verkocht
3
Lid sinds
1 jaar
Aantal volgers
0
Documenten
22
Laatst verkocht
11 maanden geleden

0,0

0 beoordelingen

5
0
4
0
3
0
2
0
1
0

Recent door jou bekeken

Waarom studenten kiezen voor Stuvia

Gemaakt door medestudenten, geverifieerd door reviews

Kwaliteit die je kunt vertrouwen: geschreven door studenten die slaagden en beoordeeld door anderen die dit document gebruikten.

Niet tevreden? Kies een ander document

Geen zorgen! Je kunt voor hetzelfde geld direct een ander document kiezen dat beter past bij wat je zoekt.

Betaal zoals je wilt, start meteen met leren

Geen abonnement, geen verplichtingen. Betaal zoals je gewend bent via iDeal of creditcard en download je PDF-document meteen.

Student with book image

“Gekocht, gedownload en geslaagd. Zo makkelijk kan het dus zijn.”

Alisha Student

Bezig met je bronvermelding?

Maak nauwkeurige citaten in APA, MLA en Harvard met onze gratis bronnengenerator.

Bezig met je bronvermelding?

Veelgestelde vragen