CSMLS Practice Verified Questions And Answers With Complete Study Tests

CSMLS Practice Verified Questions And Answers With Complete Study Tests .A calculated ABG value that indicates excess or insufficiency of HCO3 is? - ANSWER-Base Excess .A patient with prolonged nausea, Vomitting, diarrhea, will likely have an ABG result of? - ANSWER-Metabolic Acidosis .Are only intact leukocytes detected in urine? - ANSWER-The leukocyte test strip will detect intact and lyzed leukocytes .Are only intact leukocytes detected in urine? - ANSWER-The leukocyte test strip will detect intact and lyzed leukocytes .Clone vs. Strain - ANSWER-Clone is a population of cells derived from a single cell Strain is genetically different cells within a clone .Conjugation - ANSWER-Donor contracts recipient through a sex pilis. This results in both cells having identical copies of the genetic material .Define Antisepsis - ANSWER-The destruction of microbial life on living tissue (endospores may survive) .Define Disinfection - ANSWER-The destruction of microbial life on an inanimate object .Define Sterilization - ANSWER-The destruction of all microbial life .Describe the following: Ph = normal but 7.40 PaCO2 = up HCO3 = up - ANSWER-Fully Compensated (pH is fixed) Respiratory (because the pH and the PaCO2 are opposite to each other and the HCO3 is opposite to the pH for compensation) Acidosis (pH is slightly lower) .Describe the following: Ph = normal but 7.40 PaCO2 = down HCO3 = down - ANSWER-Fully Compensated b/c pH is normal Metabolic disorder because the pH and the HCO3 are moving in the same direction and the PaCO2 is opposite as it should be because the lungs are compensating to correct the pH Acidosis because the pH is slightly lower .Describe the following: Ph = normal but 7.40 PaCO2 = down HCO3 = down - ANSWER-Fully Compensated (pH is fixed) Respiratory (because the pH and the PaCO2 are opposite to each other and the HCO3 is opposite to the pH for compensation) Alkalosis because the pH is slightly higher .Describe the following: Ph = normal but 7.40 PaCO2 = up HCO3 = up - ANSWER-Fully Compensated b/c pH is normal Metabolic disorder because the pH and the HCO3 are moving in the same direction and the PaCO2 is opposite as it should be because the lungs are compensating to correct the pH Alkalosis because the pH is slightly higher .Describe the PB smear of Sickle Cell Disease - ANSWER-Normocytic/ Normochromic Poikliocytosis & Anisocytosis Target Cells NRBC's Spherocytes Basophillic stippling Pappenheimer bodies Howell jolly bodies Polychromasia Leukocytosis with neutrophilia and mild shift Thrombocytosis IgA increase Normal ferritin Increased bilirubin (jaundice) .Explain Cold Agglutinin Disease - ANSWER-IgM antibodies bind to RBC's after cold exposure in circulation IgM AB's initiate the complement pathway Extravascular hemolysis by hepatic macrophages that are removing the C3b portion from the RBC membrane .Explain ion exchange chromatography? - ANSWER-Charged beads will attract molecules of the opposite charge. The amount of molecules present will be proportional to the amount of charge coming from the beads .Explain Paroxysmal Cold Hemoglobinuria - ANSWER-Anti-P (Donath Landsteiner Ab) that is biphasic: Binds at cold temps and partially activates complement Full complement activation occurs at body temp (hemolysis occurs) P AB will dissociate from the RBC at warmer temperatures. Complement binding IgG .Explain size exclusion chromatography - ANSWER-Based upon molecular weight, solid matrix of gel beads is placed as a filter and only molecules of a certain size can pass through Larger molecules usually elute first because they don't go through the beads as more around them .Explain the acidometric test for the presence of b lactamase - ANSWER-Will detect penollic acid (end product of beta lactamase) because acid is produced, the pH will drop, producing a colour change .Explain the AMP C test - ANSWER-Used to test against beta lactamase activity. Uses the D test with discs around the Cefoxitin and cephalosporin (will have a D zone around it) Amp C is plasmid mediated .Explain the Coulter Principal of Electronic Impedance - ANSWER-Based on the measurements of changes in electrical resistance produced by cells as they travel through an aperture There is an internal electrode in the aperature and an external aperature outside of the electrode.