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INSTRUCTOR RESOURCE TESTBANK FOR Applied Physics 12th edition Ewen - TESTBANK

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INSTRUCTOR RESOURCE TESTBANK FOR Applied Physics 12th edition Ewen - TESTBANK

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,TESTBANK FOR Applied Physics, 12th edition Dale
Ewen
Notes
1- The file is chapter after chapter.
2- We have shown you few pages sample.
3- The file contains all Appendix and Excel sheet
if it exists.
4- We have all what you need, we make update
at every time. There are many new editions
waiting you.
5- If you think you purchased the wrong file You
can contact us at every time, we can replace it
with true one.
Our email:


, Test Bank for
Applied Physics


Applied Physics
Twelfth Edition




Neill Schurter
P. Erik Gundersen

,Applied Physics, 12e (Ewen/Schurter/Gunderson)
Chapter 1 The Physics Tool Kit

1) The metric prefix for 0.010 is ________.
Answer: centi

2) The metric symbol, or abbreviation, for milli is ________.
Answer: m

Write the following number(s) in scientific notation:

3) 45,000
Answer: 4.5 × 104

4) 0.0000742
Answer: 7.42 × 10-5

Write the following number in decimal form:

5) 3.28 × 10-4
Answer: 0.000328

6) 2.65 × 108
Answer: 265,000,000

Fill in each blank: (Round to three significant digits when necessary.)

7) 1.2 km = ________ m
Answer: 1200

8) 6.9 L = ________ ml
Answer: 6900

9) 750 μm = ________ mm
Answer: 0.75

10) 670 mm2 = ________ cm2
Answer: 6.7

11) 6500 cm3 = ________ m3
Answer: 0.0065

12) 15 kg = ________ lb
Answer: 166



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,13) 96 in. = ________ yd
Answer: 2.67

14) 15 ft3 = ________ m3
Answer: 0.425

Determine the accuracy (the number of significant digits) in each measurement:

15) 20,900 m
Answer: 3

16) 0.04060 s
Answer: 4

17) 3.6 × 10-12 km
Answer: 2

Determine the precision of each measurement:

18) 23.9 m
Answer: 0.1 m

19) 14,050 ft
Answer: 10 ft

20) 5.0 × 104 s
Answer: 1000 s

21) Use the rules of measurement to add 18.5 m; 2070 cm; 95.25 cm; 0.045 m.
Answer: 40.2 m

22) Find the area of a rectangle 22.6 m long and 4.60 m wide.
Answer: 104 m2

23) Find the volume of a rectangular box 18.0 cm long, 9.0 cm wide, and 6.00 cm high.
Answer: 970 cm3

Express each of the following values using scientific notation:

24) 0.0001042 mi.
Answer: 1.042 × 10-4 mi

25) 6,800,000 in.
Answer: 6.8 × 106 in.



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,26) 0.00481 L
Answer: 4.81 × 10-3 L

27) 0.000000015 gal
Answer: 1.5 × 10-9 gal

28) 127,500 cm
Answer: 1.275 × 105 cm

29) 0.00008207 km
Answer: 8.207 × ×10-5 km

30) 89,600,000 g
Answer: 8.96 × 107 g

31) 18,000 in.
Answer: 1.8 × 104 in.

Perform the following conversion(s):

32) 47.5 ft3 = ________ gal = ________ L
Answer: 355 gal = 1340 L

33) 20 m2 = ________ ft2 = ________ cm2
Answer: 2380 ft2 = 2,20,000 cm2

34) 923 m3 = ________ yd3 = ________ gal
Answer: 1210 yd3 = 243,000 gal

35) 55.0 gal = ________ L = ________ ft3
Answer: 208 L = 7.36 ft3




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,Applied Physics, 12e (Ewen/Schurter/Gunderson)
Chapter 2 Problem Solving

1) What is the difference between a subscript and an exponent?
Answer: An exponent is a mathematical operation. A subscript is used to define a variable a
specific feature or component of a variable.

2) What is the difference between a formula and a working equation?
Answer: A formula is a basic equation, usually expressed in letters and numbers. A working
equation is created when the desired variable is isolated on one side of the equation.

3) What is the purpose of estimation when problem solving?
Answer: Estimating the expected answer in problem solving can serve as a check to make sure
the answer is correct.

4) Solve for m in the formula F = ma.
Answer: m = F/a

5) Solve for t in the formula s = 1/2 (vf + vi)t.
Answer: t = 2s / (vf + vi)

6) Solve for vf in the formula s = 1/2 (vf + vi)t.
Answer: vf = (2s/t) - vi

7) Solve for h in PE = mgh.
Answer: h = PE / mg

8) Given V= πr2h, if r = 5.0 cm and V = 250 cm2, what is h?
Answer: h = 3.2 cm

9) Given A = 1/2 bh, if b = 10.0 cm and h = 12.2 cm, what is A?
Answer: A = 61.0 cm2

10) A cone has a volume of 315 cm3 and a radius of 7.50 cm. What is its height?
Answer: h = 5.35 cm

11) A right triangle has a side of 82.4 mm and a side of 19.6 mm. Find the length of the
hypotenuse.
Answer: 84.7 mm

12) Given a cylinder with a radius of 14.4 cm and a height of 16.8 cm, find the lateral surface
area.
Answer: 1520 cm2




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,13) A rectangle has a perimeter of 80.0 cm. One side has a length of 28.0 cm. What is the length
of the adjacent side?
Answer: 12.0 cm

14) The formula for the volume of a cylinder is V = πr2h. If V = 4520 m3 and h = 36.0 m, find r.
Answer: r = 6.32 m

15) The formula for the area of a triangle is A = 1/2 bh. If b = 3.12 m and A = 82.6 m2, find h.
Answer: h = 52.9 m

16) A rectangular parking lot measures 80.0 m by 75.0 m. If the parking lot needs three sections
that each measure 8.00 m by 8.00 m for tree plantings, how much area is left for parking spaces?
Answer: A = 5810 m2




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,Applied Physics, 12e (Ewen/Schurter/Gunderson)
Chapter 3 Vectors

1) Explain the difference between a scalar and a vector quantity.
Answer: Scalar is a quantity that specifies magnitude. Vector is a quantity that specifies both
magnitude and direction.

2) Explain the difference between distance and displacement.
Answer: Distance is a scalar that specifies the magnitude or the amount that an object has
changed its position. Displacement is a vector that specifies the direct distance and direction that
an object has moved.

3) Using a scale of 1.0 cm = 25 km, find the length of the vector that represents a displacement
of 450 km.
Answer: 18 cm

Use graph paper to find the resultant of each set of displacements in the following problem(s).

4) 45 km due east, then 45 km due north, and then 45 km due east.
Answer: 100 km at 27° north of east

5) 85 km due south, then 25 km 45° south of east, then 45 km due east, and then 45 km at 25°
north of east.
Answer: 130 km at 38° south of east

Use a calculator to find each trigonometric ratio rounded to four significant figures in the
following problem(s).

6) sin 18.5°
Answer: 0.317

7) tan 67.25°
Answer: 2.385

8) cos 25.075°
Answer: 0.9058

Use a calculator to find each angle rounded to the nearest tenth of a degree for the following
problem(s).

9) sin A = 0.4639
Answer: 27.6°

10) tan B = 0.1679
Answer: 9.5°



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, 11) cos A = 0.8462
Answer: 32.2°

12) A right triangle has legs of 24.0 cm and 36.0 cm. Find the length of the hypotenuse.
Answer: 43.3 cm

13) A right triangle has a hypotenuse with length of 85.0 cm and one leg with 55.5 m. Find the
length of the other leg.
Answer: 64.4 m

14) A right triangle has one acute angle that measures 34.5°. What is the measure of the other
acute angle?
Answer: 55.5°

15) An antenna is attached to a vertical pole. If a guy wire is attached 40.0 ft from the bottom of
the pole and to an anchor on level ground 25.0 ft from the base, what angle does the guy wire
make with level ground?
Answer: 58.0°

16) A conveyor is used to lift grain to a bin. The angle of elevation of the conveyor is 48.5°. If
the grain is elevated 15.0 m, how long is the conveyor?
Answer: 20.0 m

17) Find the x- and y-components of the resultant vector R and graph the resultant vector R.

Vector x-component y-component
A +4 -6
B -6 -3
C -5 +2
D -1 +4
Answer: Rx = -8; Ry = -3

18) Find the x- and y-components of the vector v = 45.0 m/s at 205.0° in standard position.
Answer: vx = -40.8 m/s; vy = -19.0 m/s




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