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fundamentals-of-electric-circuits-alexander-5e-solution-chapter-10
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September 2022

2022/2023

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Chapter 10, Solution 1. We first determine the input impedance. 1 1 10 10 H j  L j x j 1 1 0 1 10 1 F j j C j x    .1 1 1 11 1 1.0101 0.1 1.015 5.653 10 0.1 1 o Z j in j j                 2 0 1.9704 5.653 1.015 5.653 o o o I       i(t) = 1.9704cos(10t+5.65˚) A Downloaded by Brian Muchoki () lOMoARcPSD| Chapter 10, Solution 2. Using Fig. 10.51, design a pro...
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