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INDU 6331 Assignment 5 Solutions
  • Exam (elaborations)

    INDU 6331 Assignment 5 Solutions

  • 9.1. The data in table represent individual observations on molecular weight taken hourly from a chemical process. The target value of molecular weight is 1050 and the process standard deviation is thought to be about σ= 25. a) Set up a tabular cusum for the mean of this process. Design the cusum to quickly detect a shift of about 1.0σ in the process mean. σ= 25 μ0= 1.050 Magnitude of shift= 1,0(25)= 25 μ1= 1.050 + 1,0(25)= 1.075 K = /μଵ − μ଴/ 2 = /1.075 − 1.050/ 2 ...
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